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Ok. Thanks for the help.
No venn diagram. It's the mechanics of a game that im just curious about. Each stat is a separate occurrence. The stats I'm looking at give 4% chance to block an attack. If this fails you get another 9% chance to block. If this fails you then have a 7% chance to block. I've checked with adding them and it doesn't work that way because there is a spec that gives u +80% to block. This would put me at 100% chance to block but you can still occasionally get hit.
how do you calculate the probability of something happening when there are multiple percentages? i know you cant just add them haha
the problem: there is a 4% chance something won't happen. then there is a separate 9% chance it won't happen. again separate is a 7% chance it won't happen. what's the overall probability of the event not happening?
i think this much is right
1+secB
sinB+tanB =cscB
(1+secB)(1/1+secB)
(sinB+tanB)(1/1+secB)
_____1_____
sinB+tanB
1+secB
so now do I need to make the part under 1=sinB, so it will be 1/sinB, which is equal to cscB
ok, thanks
edit: nvm the equations are back
10+x+y=180
the only way i know how to do this is guess and check, giving me:
x=60
y=110
this way they progress arithmetically and the common difference is 50
how did you get form the first line to the second line?
hmm, so you mean that each letter can be replaced by a number?
and can a digit be used twice, for instance, L=2 and T=2?
here it is:
secA+cscA-cosA-sinA=sinAtanA+cosAcotA
ty btw
I got the answer but need to show my work. Answer is x=3.
Let P(x)=x³-3x²+2 and Q(x)=x²-6x+11. Find all values of x such that P(x)=Q(x).
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