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if i have the ellipse x²/16 +y²/9 = 1
If x = 1.8 how do i fin y
could you please show your steps
thanks.
ie. Sometimes its easier to understand when you see the formula
if the line gradient is ½ the the gradient of a perpendicular line will be -(1/(½) = -2
therefore in general the line with gradient m will have a pependicular line with gradient -1/m.
can someone help me to solve this. If you could show me the steps you took it would be greatly appreciated.
(3√(16 - x²)/4) - 3 = (-3x/4√(16 - x²))(x - 2)
thanks in advance
Can someone please help me find the derivative of this:
y=+3√(16-x²)/4
Could you please let me know how this is to be worked. Stating any general rules i should know
Many thanks in advance
thats ok I think that im nearly there x
Hi hoping you could help,
I have a problem that goes like this if I have a a point (2, 3) and the ellipse x²/16 + y²/9 = 1. I want to find the tagent to the ellipse that passes through the point (2, 3).
Point (2, 3) is not on the ellipse and there will be two at which it touches the ellipse.
All I would like is the quadratic equation that need to be solved to find out the points on the ellipse at which the line touches. It would be nice if I could see the equation in the quadratic form ax² + bx + c = 0
Thanks in advance:)
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