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## #1 Help Me ! » solve the equation » 2006-02-21 06:53:25

rp_
Replies: 1

if i have the ellipse x²/16 +y²/9 = 1

If x = 1.8 how do i fin y

thanks.

## #2 Re: Help Me ! » Perpendicular Lines » 2006-02-16 10:42:10

ie. Sometimes its easier to understand when you see the formula

if the line gradient is ½ the the gradient of a perpendicular line will be -(1/(½) = -2

therefore in general the line with gradient m will have a pependicular line with gradient -1/m.

## #3 Help Me ! » need help to solve the equation » 2006-02-11 02:42:35

rp_
Replies: 11

can someone help me to solve this. If you could show me the steps you took it would be greatly appreciated.

(3√(16 - x²)/4) - 3 = (-3x/4√(16 - x²))(x - 2)

## #4 Help Me ! » Finding the derivative » 2006-02-11 02:01:27

rp_
Replies: 1

y=+3√(16-x²)/4

Could you please let me know how this is to be worked. Stating any general rules i should know

## #5 Re: Help Me ! » Finding a point on ellipse » 2006-02-10 15:07:54

thats ok I think that im nearly there x

## #6 Help Me ! » Finding a point on ellipse » 2006-02-10 14:45:58

rp_
Replies: 2

Hi hoping you could help,
I have a problem that goes like this if I have a a point (2, 3) and the ellipse x²/16 + y²/9 = 1. I want to find the tagent to the ellipse that passes through the point (2, 3).

Point (2, 3) is not on the ellipse and there will be two at which it touches the ellipse.

All I would like is the quadratic equation that need to be solved to find out the points on the ellipse at which the line touches. It would be nice if I could see the equation in the quadratic  form ax² + bx + c = 0