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awesome!!! thank you!

i've converted it to .jpg

thank you Au..

I need it at home.. can you give me the code?

hey.. how do i put .gif in latex?

yes, site is wonderful..thank you very much for sharing

your site helped me..i just drew

no..i don't how to get it here..

great.. thank you bobbym and anonimnystefy

it's

\usepackage{ bbold }

\mathbb{1}

**loida**- Replies: 1

i need help, i don't have much materials where i could read this..so, if there is anyone willing to help... i'd be thankful

find minimal polynomial over Q from (1+ i)/ (sqrt2)

determine all generators of Galois group 13th cyclotomic field Q_w13

you too!

both of you

i know.. it's because i didn't see that it's y>=1

i'm thankful to both of you Bobies

thank you!

i'm getting pi*176/3 in both cases

http://en.wikipedia.org/wiki/Solid_of_revolution Cylinder method

i got

the same u get in

thanks .. i missed 1<=y part .. i drew y<=1

**loida**- Replies: 20

I'd like to check if i got correct answer

Find the volume of the solid generated by rotating the region trapped between

around the y-axis.i get

i was using formula

then

tnx R

**loida**- Replies: 2

let r be a commutative ring, I ideal in R and P r-module.

how should i prove that P/IP is module over R/I for multiplying (r+I,p+IP)-->rp+IP

and if P projective R-module, i have to prove P/IP is projective R/I-module

thanks

woow!!

thanks Ricky!

**loida**- Replies: 0

i thank him for sharing his knowledge..sth little to cheer u up

tnx Ricky

(1),(2),(3),(5),(7),(8),(9) ?

don't know how check with 2 elements, sorry

i'm afraid i have to quit, i don't have much time left and have much things to learn

but thanks anyway...i really appreciate ur effort

i'm ashamed of my ignorance..

would it be a problem if u put a solution on these exerices and i tell what i don't understand..i'm sorry, i'm just stupid for this things and don't know the basic

tnx once again...i'm really thankful for everything what u've written

Ricky..thanks alot!!! i really appreciate ur help

so, 1 is out cause p=7 prime, |G|>1

can i say that A_8 has (8*7*6*5*4*3*2)/7 cycles of length 7, which means 5760 cycles 7-cycle

i get 960 subgroups of order 7 from this cycles..960=1(mod7) and 960| |A_6| ..??

#3 ..dont know

tnx Ricky

i only know Z/10Z={10Z, 1+10Z,2+10Z,....9+10Z}

2 is prime, but not irreducible

a) (0)^(-1)=0 , (1)^(-1)=1, (2)^(-1)=8, (3)^(-1)=7, (4)^(-1)=4,(5)^(-1)=5,(6)^(-1)=6,(7)^(-1)=3,(8)^(-1)=2,(9)^(-1)=9 ?

i'm desperate

could u pls help me to figure this out?