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hi krassidegrees no radiansthank u
hi ganeshchoice (a) or(c) are true
thank you rashelyour question is very goodby
3cos^2x+3sinx=3 3(1-sin^2x)-sinx-2=03-3sin^2x-sinx-2=03sin^2x+sinx-1=0if sinx=y3y^2+y-1=0this equaition very easy (0 degree to 360 degree)
must be mistakes in your bookswhat is your name book
(x^2+1/x^2)-3(x-1/x)-2+2-2=0 then (x+1/x)^2-3(x-1/x)-4=0 if (x+1/x)=y y=4 and -1 now we solves (x+1/x)=4 and (x+1/x)=-1 these equaition very easy
hi!please solve this problem!
sin(36)? without calculator!
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