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#1 Help Me ! » Yet another integration problem... » 2005-11-16 13:24:17

CloudV3
Replies: 2

Hi all, im new here and desparately need some help, itl probably be tooe asy for you guys, but i just cant seem to find the solution, so here goes...

A particle moves along the x-axis with velocity at time t, given by v=5t^2 + 2t. Find the distance it moves in the 2nd second.


...Now, integrating v to get 5/3t^3 +t^2 + C.  Now how would i find out what C is equal to? Any help would be greatly appreciated!

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