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So, uh, should we make some poem or something?
So I guess that the official notation for this would be
lim(.999...)=1
Tell me if I am using the limit wrongly.
Sorry... I totally edited this message because I wasn't clear in my first post.
EDIT: I can believe MathsIsFun, but that wasn't the ratio I meant. It's the side of the inner pentagon I meant. (Not the diagonal) Sorry for the confusion. Also, I probably calculated it wrong. Shame on me for not using a calculator.
Nullity is null and void.
OK, how does the Golden Ratio corrospond to 2.013?
Oh. The only other thing that could stand in one's way is the way it's played. I'm most familiar with the Colorado Lottery, and unless you are either speaking for all of them, or you are not familair with all of the rules. I guess this is a time to hit the websites and books HARD.
Hey, I looked on a graphing calculator and found that the limit of acos(x)-(pi/2) as x goes to 0 equals 0. Here's the only iffy part: is pi/2 a coincidence just popping up as some random number, or does the acos function acually really relate to pi/2?:/
Hold on- I've heard that sometimes nobody wins.
What are the Navier-Stokes equations?
I don't really care about the numbers, I just scroll down and think about the power of computers these days! When I first saw this, I was amazed!
Hey, there's another way to memorize the first like, 10 decimal places. First, memorize this:
May I have a large container of orange juice now please?
Then just count the number of letters in each word and put a decimal point after 3.
3.141926536
I just like to leave it like pi.
You may have noticed this before, but here goes:
1. Draw a regular pentagon.
2. Make a star in there by connecting every other vertex
3. Draw a star in that one by the same method
The pattern is the larger star's length is about 2.013 times the smaller star's length.
This number might be irrational (though I have no way to find out. )