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Well you need to double the probability since it is a two-tail test
so Y=1/X when X~U(0,1)
P(Y<y)=P(1/X<y)=P(X>1/y)=1-1/y
Is it about Fourier transformation
I am planning to study it
You already studied Young & Williams?
Oh my!
I guess it is a common trick that the power is the same for the same engine at its full power.
what is Matrix T?
Your original matrix A is not symmetrical around its diagonal
page 39 appendix
at page 19
"You need to assume an infinite amount "
If infinite independent factors were real, normal curve would have explained everything. Unfortunately, there is always "fat tail" phenomenon, which indicates only finite factors in the real world.
They have also similar cycle puzzles like
1 3 9 7 1
+2+6-2-6
and
2 4 8 6 2
seems swap the last two biggest number in a four number ascending sequence could produce a cycle.
Hi boys and girls
I recently encounter an interesting task on studying fund rating methodologies. And I fund Lipper's Preservation Measure is
Sum(Min(0,ri))/T or Sum(Min(0,ri))/N*(T/N)
What it actually does is turn all the positive return r's to 0 and compute the average.
If we assume r normally distributed as N(u,s²)
The negative expectation can be modeled as E- =∫r*pdf dr over (-∞,0)
I came up with the answer
E-= u*N(-u/s)-(s/√2π)*exp(-u²/2s²)
But Michael Stutzer in his paper Mutual Fund Ratings: What is the Risk in Risk-Adjusted Fund Returns? derived an approximation as
Could you check this out and tell me why the difference? Thanks!
i.e.
Stock quotes
Bond quotes
FX quotes
It is actually very hard to address their distributions accurately
I think of George Cantor
And in the second round it gives Kurt Gödel
Quite close
I guess we have different classificasion of mathematicians into scientists or nonscientists
That makes sense.
See it another way, (3a)^n gets trapped in its own loop {3,6,9}
beside 0
{1,2,4,8,7,5}must be seperated from{3,6,9}
The hardest part is the ascending and then descending order of
1 2 4 8 7 5 1
Suppose we have identically distributed random numbers, which are independent to each other.
There is a saying that the turning points, each either larger or smaller than both its neighoring numbers, accounts for 2/3 of the sample size.
Can anyone prove it?
Thanks
Many individuals, looking at a body of water, may be struck by its beauty or wonder about its swimmability. When MITs Daniel Nocera looks, he sees, among other things fuel.
And not just any fuel, but potentially green and basically limitless fuel.
Noceras perspective reflects his long-time goal of achieving a variation on what plants do: aided by sunlight, split water into oxygen and hydrogen. Then, he wants the gases to be stored for use as electricity is needed.
Very little water would be required. The average household uses about 30 kilowatt hours of electricity a day, notes the MIT chemistry professor. To obtain the fuel to generate that amount would take roughly five liters of water. And because the oxygen and hydrogen recombine, the system could be closed: you could truck one to your desert hideaway along with a water supply and be set for years.
Thats the vision. And if realized, not only would we have a green technology whose feedstocks water and sunlight are everywhere, wed be on our way to overcoming a tough obstacle to a big ramp-up in solar power use, which is storing the suns energy for when its dark or cloudy.
Of course, realizing the dream will itself be very tough. But Nocera and his main co-worker on the project, postdoctoral associate Matthew Kanan, recently overcame one of the biggest hurdles: separating out the oxygen in water in much the way plants do.
The basics of the proposed system are straightforward. Using solar panels, you generate electricity. That power can directly meet your homes electrical needs some of the time. Or, it can run a device called an electrolyzer the guts of which are the pairs main contribution to the system which breaks down H2O molecules, two at a time, into a molecule of oxygen and two molecules of hydrogen. You store the gases in tanks. They can then be used to run a fuel cell, an electricity producer thats like a battery in generating current electrochemically but that requires a fuel supply. You use the electricity to power well, whatever you want.
To make the system work financially and otherwise, though, Nocera needed low-cost watersplitting catalysts that work in environmentally benign conditions. Its a goal the faculty member has been pursuing since he began his career more than 20 years ago.
Nocera started with foundational research for example, studying plant processes to understand more about them. More recently, hed made progress on specific scientific phenomena undergirding the reaction chemistry needed to split water. But the problem was, says Nocera, that we hadnt done anything on the oxygen side. I knew we had to get O2 for my system to work as a closed one.
Last winter, Nocera and Kanan obtained the result they wanted. Among the keys to success were two chemicals: phosphate, widely used in fertilizers among other products; and the element cobalt, whose features include the fact that positively charged particles of the metal readily dissolve in water.
Using an apparatus that resembles a high school chemistry lab set up for splitting water, the researchers dissolved the cobalt ions and phosphate. They then sent current through the electrodes. The cobalt built up on the positively charged electrode and off those deposits bubbled molecules of oxygen.
It was a chemists version of a Eureka moment, though Nocera says the pair didnt start popping champagne corks. We immediately started thinking about the months of experiments we would have to do to verify the results, he says.
Those experiments worked, but a vast amount is still to be done. One goal is to solve the chemical structure of the catalyst that allows the oxygen to emerge a quest that seems in reach thanks to the researchers access to a high-energy instrument for probing matter.
Nocera and Kanan have other goals, too. One example: find alternatives to the pricey platinum thats the catalyst on the negative electrode.
Then theres the overall cost issue. In its current form, his system would go for at least $20,000, and maybe a lot more. Thats too much to make it competitive, especially since Nocera sees emerging countries as a key market. These systems have got to be cheap, cheap, cheap, he says.
Nocera thinks thats doable. A startup is forming to further the systems technological development. The MIT group, he notes, continues to focus on the science.
Meanwhile, the work has already had one positive impact. His system has become a conversation-starter, with the subject being what he calls personalized energy. Whether people are for it or against it, says Nocera, theyre talking about it. And thats the first step toward making it happen.
Taking difference:
1 2 4 8 7 5 1
1 2 4 -1 -2 -4
acceleratingly ascending
1 2 4 8
and then acceleratingly descending
8 7 5 1
Hi;
Your idea is easier to understand in terms of mods. Reducing a number to a single digit or a digital sum as it is sometimes called is done using mod 9. There it is easier to see why the pattern will repeat.
1,2,4,8, (2 * 8 = 16 mod 9 = 7), (2 * 7=14 mod 9 = 5), (2 *5=10 mod 9 = 1)...
Thank you!
Using spreadsheet, I just discovered not only do 2^n corresponds to 6 figures, but the figures follow a special sequence too!
2^0=1 1
2^1=2 2
2^2=4 4
2^3=8 8
2^4=16 =>7 7
2^5=32 =>5 5
2^6=64 =>10=>1 1
2^7=128 =>11=>2 2
2^8=256 =>13=>4 4
2^9=512 =>8 8
2^10=1024 =>7 7
2^11=2048 =>14=>5 5
2^12=4096 =>19=>10=>1 1
2^13=8192 =>20=>2 2
2^14=16384 =>22=>4 4
2^15=32768 =>26=>8 8
2^16=65536 =>25 =>7 7
2^17=131072 =>14 =>5 5
2^18=262114 =>19 =>1 1
2^19=524288 =>29=>11 =>2 2
2^20=1048576 =>31 =>4 4
2^21=2097152 =>26 =>8 8
2^22=4194304 =>25 =>7 7
2^23=8388608 =>41 =>5 5
2^24=16777216 =>37 =>10=>1 1
2^25=33554432 =>29=>11=>2 2
2^26=67108864 =>40=>4 4
2^27=134217728 =>35 =>8 8
2^28=268435456 => 43 =>7 7
2^29=536870912 => 41 =>5 5
2^30=1073741824 =>37 =>10 1
So it is very obvious that the figure sums of powers of 2 endure an ascending 2 4 8 process and then a descending process 7 5 1 and the cycle repeats itself. And this is so called the wave, the cycle, the spiral, the yin & yang, whatever.
Anyone have a clue about the cause?
It is easy to explain why the remainder of any integers divided by 7 will be 0, 1, 2, 3, 4, 5, and 6.
However it is strange that the decimals (after the decimal point) appearing in N/7, are only 0
or 1, 2, 4, 5, 7 and 8
why crossing out 3, 6 and 9? why these particular three?
Is there a mathematical explanation to this phenomenon?
And is there a mathematical proof to the 2^n case?
Yes I agree it has something to do with base 10.
But the numerology exists in base 10 in concurrence:
the only decimal figures you get from division by 7 will be these 6:
1 2 4 5 7 and 8
aren't they special?
And the only figures you get from adding numbers of 2^n come to
1 2 4 5 7 or 8
Adding numbers together isn't the privillige of astrology, but mathematicians use this too -
Suppose you see 14532, and you can tell it is divisible by 3 since 1+4+5+3+2=15, and 1+5=6, 6/3=2.
Hmm, it is easy to prove why 3, 6 an 9 are missing. If the addition of the figures comes out as multiple of 3, the original number 2^k must be divisible by 3. Of course they will not appear. However the questions still remain why all of the 6 remaining appear in abstractions of 2^n, and why 3, 6 and 9 are missing in all 1/7, 2/7 , 3/7, 4/7, 5/7 and 6/7.
2048 -> 14 -> 5
4096 -> 19 -> 20 -> 2
8192 -> 20 ->2
...
It seems that you will never get 3, 6 or 9 through powers of 2, which are compounded by some figures out of 1, 2, 4, 5, 7 and 8. (3=1+2, 6=1+5 or 2+4, 9=1+8 or 2+7 or 4+5)
Recently I came across a myth saying that the division by 7 implies the utmost secret of the universe. The multiplication of life, from 1 to 2, to 4, to some power of 2, can be simplified to repeatitive 1 4 2 8 5 and 7, the figure appearing in 1/7.
Here is how it works:
1 2 4 8 16 32 64 128 256 1024
1
2
4
8
1+6=7
3+2=5
6+4=10, 1+0=1
1+2+8=13, 1+3=4
2+5+6=13, 1+3=4
1+0+2+4=8
So far, as you can tell, only 6 figures (1 2 4 5 7 and 8) out of the 9 non-zero figures appear in this abstracted number out of 2^n when n<=10.
And the method used is simple and commonplace in astrology. There is no deliberate manipulation here.
A further evidence is the Yin and Yang Taoism philosophy in China.We have a strange idiom saying 7 up and 8 down, meaning 7 represents the Yang, and the 8 represents the Yin. Indeed here 7 is the largest odd number out of the 3 odds, and 8 is the largest even number out of the evens. Moreover, if you add 1 and 8, 2 and 7, 4 and 5, you always get the result 9. And that is the utmost power number 9 in Daoism (Taoism), which is the unity of both Yin and Yang.
The question is,
Can someone prove the 6 figures rule applies to all 2^n's ?