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I think Marxism is incontigent, for Karl Marx just doubtfully applied Hegellian dialetics to materilism.
By the way, why do you say they are inferior? They themselves claim to have a "better" logic than "yes or no".
Why did I say insufficient? You cannot have 2 same apples, so 2,3...are just approximations for reality.
WEIRD
After simplification they are both ln2 (log2) !!!
It took my software 2 minutes to compute n=7 case and 7 minutes to compute n=18 case. Although it didn't return ln2, the numerical approximation are both 0.693147 ! ! !
I admit my method is wrong, because the trapezoid fails to approximate even
So is the answer ln2 instead? It depends on whether (sint)[sup]n[/sup]/t[sup]n+1[/sup] can be treated as 1/t.
Math structure is basically based on a simple philosophy-either A, or not, but not both. This is a logical, but insufficient interpretion of our world.
for example, we know that
A->B <=> notB->notA
Proof:
A status can be strictly categoried into B and not B, and a status( though whether it is the same as the former status is unknown) can be categoried into A and not A
then we have
A -> B
notA notB
A cause only B, and A cannot cause notB, which is the very meaning of
A->B
then if notB "turns on", we say that the latter status must fall into notA class to avoid controversary.
then notB->notA
So basically "yes or no"philosophy, yes is yes, no is no, others are Plain #@$!
Mikau, do you love movies? I think a philosophical movie would be a good start.
And basicly I think people who hold an interest in math and science generally prefer to occupy their brain with different types of thoughts that in some way relate to math or science, while other more poetic people are content to occupy their thoughts with small talk and simple conversations, and can find the beauty in simple things.
I think math is already simple, you have only a few formulas to remember, which are even correlated! And that's why I hate my major and love simple, brief and elegant math.
IT IS A GOOD QUESTION!!!
It's a question about coords, combination of derivatives, and vector calculus altogether.
It's about expressing the original combination of derivatives in another co-ords, usually orthogonal curvy ones. For example, polar co-ords are curvy, and dr and dθ at any given point are orthogonal to each other.
It's usually explained in a vector calculus book or a calculus book for physicians. Untill now, I haven't got a satisfactory explaination for this kind of transfer in any books.
However, I do find a particular solution for your coords and your case.
Define
After substition,
According to Chain Rule
Thus you can compute the right of your equation and use cos²θ+sin²θ=1 to prove it equates the left.
I didn't make up this problem, its in a book. But yeah it seems we need one more piece of information.
Maybe I should have used passive format.
If two objects' projecture on a surface are equal, while their angles against the surface are equal, they are equal, too.
you should give another condition - two angles equal, or two line segments equal.
yes the formula you use is correct
for
85/3 +85/3 +85/3 = 85
1st mon 2nd mon 3rd mon 3months altogether
Franklin wrote: but the answer is likely zero the the area under the curve from 0 to 0, unless n is way bigger than m- Right
when n is just 1 larger than m, the limit does exist and is not 0.
before x reached 0, we can treat x as a small amount. 2x is small too.
then the integral can be approximately treated as the area of a trapezoid, with height x=2x-x,
the left base (sinx)^m/x^n, the right base (sin2x)^m/(2x)^n.
Since x and 2x are very small. the left base can be treated as
(x+o(x))^m/x^n= (both*1/x[sup]m[/sup])= (1+o(x))/x
and the right base
(1+o(x))/2x
Hence the area is
[(1+o(x))/x+(1+o(x))/2x] x/2= 3/4+o(x)
_______________________________________________________
Special Note for o(x)
o(x) is a variable dependent on x which satisfies Limit x->0 {o(x)/x}=0.
Hence o(x) is always much smaller than x, for example x²,x³ or sin²x
o(x)+o(x)=o(x)
o(x) o(x)= atleast o(x) or exactly o(x²)
o(x) anyC =o(x)
o(x) x/x =o(x)
_______________________________________________________
Let's now have a look at the whole limit of 3/4+o(x) - it approaches 3/4 when x gets smaller and smaller, and the limit should be 3/4
when n=1+m, 3/4
when n<1+m, no sense or infinity.
when n>1+m, 0.
(H0) If the (original )coefficient of holidays is 0, while its sample standard deviation is 0.0975, then according t distribution for degree of freedom being 10 (Samples Size)-2 (Coefficient Amount)=8, -1.425/0.0975 should be at the very tail of the bell curve. Thus the probability for a sample observation of a 0 coefficient, -1.425/0.0975, to occur is very low. Usually they integrate PDF before -1.425/0.0975 and double it for symmetricity of t distribution to demonstrate how low the "altogether" probability is and say it's an almost imposible event.
Since its probability is too low under the assumption that the coefficient is 0, we have enough reason to doubt the very assumption. This is like what cops do-yes the victim can die of an accident but the situation is unnormal and the probability for an reasonable accident in that situation is too low, thus a further investigation should be compulsory.
Refusing 0 assumption= admitting non zero= admitting that there is a correlation between AbsentDays and Holidays-we can interpret it as lack of Holidays being cause and absent behavior being effect. And -1.425Holidays is called statistically significant.
Initially I used excel (tools-data digging-regression, load vb before first using) to do the regression of absent days to 3 other variables (grades turned into wages), but 2 of the 3 independent variables doesn't pass the 0 test-their integrated probabilty is more than 10%. Then I used only the remaining independent variable, also the significant variable Number of Holidays to do the regression and get post #5, with R²=96.4%, virtually as same as the previous R²=97.6%. So I could say this new function with variable amount reduced to 1, can explain as much dependent variable, the amount of absent days, as the previous function with 3 variables, why not choose the new one? Both my econometric textbook author and I believe in Occum's Razor, and I give you the simple function(formula).
You should find another constraint to determine a.
3 parameters a, b and c, at least need 2 constraints to determine, according to my experience.
This should be a geometry problem, but I've forgotten all the theorems.:(
AbsentDays= 48 -1.425Holidays
(2.388) (0.0975) R²=0.964
I totally agree with your idea. Sometimes it's really difficult to apply math by just referring to a formula (Or else everybody could escape from math lessons through keeping a handbook). Yet introducing the whole system would be like authoring a new book and unrealistic.
So my idea is to set a Theory Piece Section, to allow people to explain and dig difficult, fundamental ideas or whatever he/she thinks important to a math learner, in Existing math theories.
When X is less than K, the probability is 0,
Else Binomial distribution would be the answer.
for a single experiment,
P(dice showing 6)=1/6
P(dice not showing 6)=5/6
But that won't be too much help.
It's like proposing a Euclid post. Can you imagine a bunch of formulas or theorems can express the whole system, or at least the majority of?
What if a third similar element added to your formula? It can't be covered by the old one.
What job can we do if you put all the tricks online ????
Yes, polar co-ords can be really helpful and a good alternative!
:d :d