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Thanks for all those links Bobby and the definition. So from what I've understood, this is what a derivative is: The slope of a tangent at any given point on a curve (or maybe even line).
http://www.youtube.com/watch?v=ay8838UZ4nM I even ended up watching that link for the extra examples and I'm sort of getting the basic understanding of the things.
Mind asking me 2 or 3 questions (any basic sort) to see if I get the hang of things?
Alright, I just have a few general question about this concept. I'm only into Pre-Calculus at the moment so we haven't come across this.
I know that derivatives can be used to find the average rate of change, or was it the instantaneous rate of change.. (I somehow used some function on the calculator and was able to find one of them.)
But I was just wondering, can someone tell me how they work? I asked my teacher if I could borrow a Calculus book for the year but he said I'd have to wait til next week.
So until then, any basic knowledge would be helpful, and it will give me something to think about.
Thank you!
Wow, that mod stuff is confusing. <.<
I'm gonna go Google it for a while and see if I come up with a result.
The sum means the addition of all the numbers. So just add:
128
145
+106
-------
If you can no longer find it, think about it this way. Let x represent oranges.
So you have 5 oranges. Someone takes away 2 oranges. Then you gain 8. The 8 doesn't have a unit. So as well as the new 8 you have, how many oranges do you have left? Fill in the blank:
_x+8
I thought about the first one for a while and couldn't conjure up an answer. Mind posting the results in hidden text?
Hi Anakin;
I recently had a small argument with a guy who is a Physicist on another forum who believes it is not important to teach children the multiplication tables even though he learnt them. I couldn't disagree more.
Yeah, he couldn't have been more wrong. Nearly everything in more complex math (not that I'm even that far) requires the use of multiplication and without having to punch in every digit into the calculator certainly saves time. For instance, division is made a lot easier with multiplication, finding LCM is easier, and even working with fractions is made a lot easier with knowledge of the multiplication tables.
Enough of my babbling now.
Particularly, you should know the multiplication tables by heart for all numbers up to at least 12. When I was a bit younger, I used to do tons of multiplication in my head before falling asleep and now it's permanently set in there. Knowing them directly will help you a lot in the future in math where you have to start factoring and such.
Good luck.
Do what with them?
Do you mean solve for x if the equation was equal to zero? If so:
3x+2=0
3x=-2
x=-2/3
7x-2=0
7x=2
x=2/7
Thanks for the link. I guess apart from knowing the different identities, it's experience that will allow one to decide while identity to use.
And if that doesn't work, I gotta go all the way back and try a new one.
I'll keep trying different examples, it'll help during exam time.
Thanks for the reply Bobbym.
Yeah sometimes I find a complex side easier, sometimes the simpler side's easier to prove. Usually I start with the complex as well.
1. http://www.sosmath.com/trig/Trig5/trig5/trig5.html Would that qualify as a good table?
As for everything else, I do try to do exactly what you mentioned. Especially checking the last step to verify if I made any mistakes, as that can be crucial.
I was just wondering whether you guys had some specific advice, hints, or strategies involving proving trigonometric identities.
I can usually get them but it takes quite a long time for really complex ones, in which case I may not even end up proving it.
Most of them involve double angle formulas, half angle formulas, quotient identities, Pythagorean identities, and the reciprocal identities.
I know it's hard to get better at these without experience and seeing nearly all the sorts of examples but any advice would be appreciated.
Thanks!
I suppose to have more than 100% would mean that you now have more in comparison to your original amount.
So if you had 5 cookies before and now have 5 cookies, you have 100% of your cookies.
If you had 5 cookies and now have 10 cookies, you have 200% of the original amount of cookies.
Normally when then the textbook says solve graphically, it means graph it on a graphing calculator or some applet like this: http://www.mathsisfun.com/data/graph.html
And you see for what value of x, y is equal to 0 by looking at the x-intercepts of the graph. That is how you would go about solving it.
Thanks Mathsyperson.
Nevermind, I thought of it quite a bit and I think I've got the concept.
But just to make sure:
First 100 km/h is converted into 2777.78 cm/s. That is the speed at which the tire travels. So basically, every second, it moves 2777.78 cm. This would make it the arc length.
Now we have to look at it in a perspective of ONE SECOND intervals.
So Θ = a/r
Θ = 77.16 is the value of the angle in radians but for ONLY ONE SECOND.
Then we must find out how many times it rotates in one second or how many revolutions it has so we divide that number by 2pi.
Is my understanding correct?
So here is the question:
"A car is traveling at 100 km/h and the tire of the car has a radius of 36cm. Find the number of revolutions per second."
Process:
100 km/h * (10,000,000 cm/km) * (1h/3600 secs) = 2777.77777778 cm/s is the speed of the car.
Θ = a/r
Θ = (2777.78) / (36)
Θ = 77.16
To find number of revolutions, we must divide by 2pi.
77.16/2pi = 12.28 revolutions/sec. That is the correct answer.
a) I did not get that on the quiz because I do not understand the mechanics behind the operation. Can anyone walk me through each calculation and state why that step is done?
b) And why is 2777.78 cm/s equal to the arc length? Isn't arc length a distance? I thought 2778.78 cm/s was a velocity measurement.
Thank you.
That is the point. You CANNOT use synthetic division unless the divisor is linear.
Note that when you expand the divisor, it has a degree of 9. So in the end the divisor is two degrees higher than the dividend. I'm still relatively inexperienced in math so I may be incorrect but I don't think you can perform that division.
I guess you can just leave the answer as (4x^7 - 8x^6 + 4x^5 - 5x^3 + 2x^2 +3) / (2x^3 + x + 1)^3 .
2.
That would mean that it is in quadratic form, because the highest degree is 2. In other words, the first equation that you provided (1/x + x/2=x/3 + 1/2) has the same solutions as the quadratic I provided.
I think you're assuming that for any value of x, the first equation holds true.
Let's say
So that means only when x is equal to 8, does the left side equal to the right side.
When you put in a random number, it does not work out. Ex. when we substitute in 5 for x:
Obviously, that is not the case.
950
+750
------
1700
First add the ones, then the tens (if it gives a two or higher digit value, add the extra digits to the next column). So for this example, 5+5 = 10, the one goes to the hundreds column.
Then add the hundreds, including the one that was moved over.
0+0=0
50+50=100
900+700=1600
100+1600=1700
With something this easy, I try to simply it a bit. I add 50 from the 750 to the 950 to get 1000. 1000+700=1700
http://www.mathsisfun.com/numbers/addition-column.html
Have a look at that. It's well written.
I worked it out visually as well for the page Bobbym linked.
Nationality: Norwegian Dane Brit German Swede
Pet: Cats Horses Birds --------- Dogs
Color: Yellow Blue Red Green White
Sport: Hockey Baseball Polo Soccer Billiards
Drink: Water Tea Milk Coffee Beer
This leaves us with one blank missing and since we were given no information about the fish, we could not determine where it belonged.
Since the only spot left is for Germany, the fish would have to belong to the German.
Good pages!
The one change I'd make is to add a bit more explanation to when you say √2 * √2 = 2.
√2 * √2 = √(2*2) = √4 = 2
About that.. ^, if you really want to, you can also state that the √a * √b = √ab is not always true.
For instance, - 1 = i^2 = i * i = √-1 * √-1 = √(-1*-1) = √1 = 1
That is untrue, so if you are really bored enough, you can add that and explain why.'
You have to flip the signs when you multiply/divide both sides by a negative number. I'm just posting the above to show you that, but my process is not right.
The correct answer should be -1/10 < x < 0 OR 0 < x < 1/10. Plug in values and you will see that my answer is correct. For instance if what the text says about x having to be less than 1/10 was true, then that means we can sub a value like -2/10 in for x.
Which obviously is not correct.
One more thing. Does that mean the SQUARE ROOTS of 4 are positive 2 and negative 2? But the principal square roots (symbolized by the use of a radical sign) is only positive 2?