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Sorry guys, I made a mistake, the question should be:
A different integration?
I have found a way to integrate this directly, but it is very tricky.
There actually is closed form, but through a different integration.
Oops, I post the wrong question
Actually, the answer is 3
Look at this poster before 2013 Asian Football Championship, the score will be 3:0
Let me explain conditional statement via set arguments.
If you know A is true for sure, and you can immediately infer that B is true.
A is true is sufficient condition that B is true.
We can also say that the event A is true is contained in the event B is true.
Like you are in London implies that you are in UK. But the other way around is not necessarily true.
and we can say B is necessary condition for A, for notB is in notA - you are not in UK so you are not in London.
Hope this theory make your logic class a lot easier!
anyone?
Alright guys, I think I should give up.
Thank you anonimnystefy
I have been searching for good Latex Editor.
However I found that any of them cannot work alone- it has to work with a 1 GB Tex platform called MikTex.
Is there an independent Latex Editor that satisfy basic editing needs?
Thanks.
choose 3 and choose 6, and choose between 4 and 5, multiplied by number of choosing sequence possibilities
But it is with replacement, so we have to consider 336 and 366
why (1/6)?
I suggest you go to quantnet forum
eigenvalues can appear more than once, as far as I know.
In 1943, US Navy launched an experiment near Philadelphia, in which a battle ship with the crew, became invisible due to a special electro-magnetic field. The ship not only disappeared, but reappeared in a different place and a different day, and the crew has gone mad as well.
This is a REAL time travel case, not a fiction!
Tennis
Chinese Caligraphy
The idea need proof is
Proof:
First, a review on Pascal's Triangle
The intuition is n already chosen from m and then add 1 to m and choose n+1 instead. the added 1 to pool of m can be either selected with n already chosen or neglected. In the former case m choose n, the latter case m choose n+1. The two way conclude all the possible ways to choose n+1 from m+1.
Hi, I know a proof through Pascal's triangle, but can anyone latex the combination sign?
5 choose 3
= 2 choose 2 + 3 choose 2 + 4 choose 2
10=1+3+6
That looks fine
C[sub]n+1[/sub][sup]m+1[/sup]
=
C[sub]n[/sub][sup]n[/sup]+C[sub]n[/sub][sup]n+1[/sup]+...+C[sub]n[/sub][sup]m[/sup]
How do we define 0!?
0!=1?
Does this result comes from combination?