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#9701 Re: Help Me ! » Help Me With Gcse Maths » 2010-12-19 23:53:48

Bob

hi mandy jane,

I've taught GCSE maths for more years than I care to remember.  And I've got past papers. 

What board are you entered for, what level and when is the exam?

Bob

#9702 Re: Help Me ! » Ratio » 2010-12-19 23:48:16

Bob

hi Aartt,

How was the vacation?  smile

The streets here are still full of snow.

Now to business.

Here's the problem:

Subtract (-3x² + 5y - 4xy + y²) from (2x² - 4y + 7xy - 6y²)

So you have to start with the second expression and take away the first.

There are lots of + and - terms so it is safest to put the second expression in brackets.  Thus

2x² - 4y + 7xy - 6y² - (-3x² + 5y - 4xy + y²)

Notice that there is a minus outside the bracket at this stage.

Because -- makes +    and   -+   makes -  when I clear the bracket all the internal signs change.

2x² - 4y + 7xy - 6y² + 3x² - 5y + 4xy - y²

As I moved each term beside its 'partner' I took the sign along too.

2x² + 3x² - 4y - 5y + 7xy + 4xy - 6y²  - y²

Now when you tidy up the terms the required answer emerges

5x² - 9y + 11xy - 7y²

My advice with these is to take four lines; don't try to do them in your head.

so (i)  write with a bracket     (ii)  clear the bracket and change the signs as necessary  (iii) collect like terms carrying the sign with the term  (iv) simplify

Hope that helps

Bob

#9703 Re: Help Me ! » Geometry » 2010-12-19 09:00:00

Bob

You're welcome.

Good luck with the exam.

Bob

#9704 Re: Help Me ! » Pre-Algebra and Algebra II, and blah, and blah » 2010-12-19 06:26:54

Bob

Vacation?  smile Where are you going?  I'm snowed in here.  sad

There are lots of exercises on all branches of maths. 

When you first log on the links at the top are Forum Home  then Maths Is Fun, then New Posts.......

The link Maths Is fun is the start page for exercises on maths and puzzles and lots more.

Once you go there you had better put your life on hold, because there is lots and lots to do!!!

Bob

#9705 Re: Help Me ! » Pre-Algebra and Algebra II, and blah, and blah » 2010-12-19 06:20:41

Bob

hi Aartt,

Why don't you work through the Maths Is Fun algebra section that starts at http://www.mathsisfun.com/algebra/introduction.html

Bob

#9706 Re: Help Me ! » Ratio » 2010-12-19 06:15:18

Bob

hi Aartt,

I have looked at this site and it says you got the wrong answer.  So I need to know what answer you had.

Bob

#9707 Re: Help Me ! » Sin, Cos, and Tan » 2010-12-19 06:11:22

Bob

hi Aartt,

Very good.  I got 6.35903..... so I rounded up to 6.36 cm.  Take care with the rounding!

Another one below.  Say when you feel you've had enough trig and want to move on.

Bob

#9708 Re: Maths Is Fun - Suggestions and Comments » Can you check these, please? » 2010-12-19 02:42:08

Bob

Thanks phrontister

And now I can play it.  Perhaps I should say I know how to lose to the computer!

sad

Bob

#9709 Re: Help Me ! » Sin, Cos, and Tan » 2010-12-18 21:27:55

Bob

hi Aartt,

Ok, here's one

Bob

#9710 Re: Help Me ! » Can Someone Help Me Make Sense of This Algebra Problem? » 2010-12-18 15:29:54

Bob

Hi Charlie,

You originally said you had lots of problems like this.  Unfortunately, the one you gave had an 'unhelpful' answer.

How about posting another?

Bob

#9711 Re: Help Me ! » Sin, Cos, and Tan » 2010-12-18 15:16:29

Bob

hi Aartt,

Sorry I've not contributed to this thread for a while.  I was out for a whole day and then, when I looked, you seems to be progressing well with your trig. 

Now you seem to be hung up on rounding off.

So, maybe a little lesson in that will help.

I'm going to look at the decimal number 1.817

Here's a picture that shows where it is on the number line.

decimal1.GIF

Firstly, the gap between 1 and 2 is divided into tenths.  Our number is over 1.8 but under 1.9

Then, the diagram is magnified by x 10 so you can see the hundredths.

Our number is between 1.81 and 1.82

Then the diagram is magnified by x 10 again to show the thousandths.

Our number can now be shown exactly as 1 unit, 1 tenth, 8 hundredths and 7 thousandths.

Now for the rounding off.

decimal2.GIF

If you truncate the number you just chop off unwanted digits so you'd get 1.81

But the diagram shows that 1.817 is nearer to 1.82 so this is the correct thing to write if you are rounding.

I've seen you write the rule for this in post 99

because the digit behind it is greater than 4 so you up the number in front of it by one

But why this rule?

Because you're looking to see which way is nearer;
4 and below means 'to the left' is nearer;  this is ROUNDING DOWN
above 4 means 'to the right is nearer;  this is ROUNDING UP.

There are many ways to ask someone to round off:

Give answer to 2 decimal places
Give answer to 3 significant figures
Round to the nearest whole number
etc etc.

Does that help?

Footnote.  It's 3.16am, here in England.  I woke up and couldn't sleep so I thought I'd have a look at MIF.

I think there's a big time difference between us, which is why you sometimes post and then wonder why there's no reply for a while.  Tell me what your screen says for the time I posted this and we can work out the time zone difference.
Bob

#9712 Re: Maths Is Fun - Suggestions and Comments » Can you check these, please? » 2010-12-18 04:55:49

Bob

hi again,

Actually it's IE8 and I've got flash player.  Slightly more happens now.  I click a red piece and it is touched by 3 green bordered hexagons and those by 5 more in yellow.  Then nothing.  ??

If I click another red that gets the greens and yellows instead.  ??

What am I supposed to be doing?

Bob

#9713 Re: Maths Is Fun - Suggestions and Comments » Can you check these, please? » 2010-12-17 23:17:35

Bob

Hi MathsIsFun

Money Master loads and runs. I only tried one option.  It looks like it's got loads of potential.  Thanks.

Got hexxagon loaded but couldn't do anything with it.  I'm using IE7.  I could toggle between the games options so I chose 'against the computer'.  Board appeared but I couldn't move a piece.  Did I miss the instructions?

Bob

#9714 Re: Help Me ! » Inverse Matrices » 2010-12-17 08:23:12

Bob

hi Au101,

in post 3 you  wrote:

I'm really not sure what to do here, I can't multiply both sides by A

But what you have subsequently done is exactly that and it's fine!  So that answer is correct.

Post 4 is also correct.  I had in my mind that there would be more than one way of doing this; and you've shown this is true, so thanks.

Bob

#9715 Re: Help Me ! » Inverse Matrices » 2010-12-17 04:57:20

Bob

Hi again

How about:

Consider

What is it equal to?

Then use what you are given to show what

is equal to.

Use this to show

And then to the required result.

Can you fill in the gaps?

Bob

#9716 Re: Help Me ! » Centre of mass » 2010-12-17 02:45:42

Bob

Hi Au101,

First I thought the diagram was:

AU1.JPG

But now I'm thinking:


AU2.JPG

Anyway, it sounds as though you've got this problem sorted.

I did those pictures in a brilliant software prog. called 'Sketchpad'.  I use it a lot.

Then (and this is a windoze PC) I press PrtSc to snap the screen, paste into 'Paint', edit as required, and then save as a GIF.  The file sizes are pretty small, and I can do what bobbym says and do an image upload.  You cannot do this if you choose a Quick Post.  You have to choose Post Reply for the full range of facilities.

Bob

#9717 Re: Help Me ! » Sin, Cos, and Tan » 2010-12-17 02:23:24

Bob

So do you want another one?

Bob

#9718 Re: Help Me ! » Sin, Cos, and Tan » 2010-12-17 02:09:58

Bob

hi Aartt,

Yes, be systematic; do each step and tell us what you are getting.

in post 69 I  wrote:

(i)  Check you have got a right angled triangle.  (In our exams it's common to give an isosceles triangle.  The students must cut it down the line of symmetry before they can use trig.)

(ii)  Decide what you know:  angle?  adjacent?  opposite?  hypotenuse?  and what you are asked to calculate.

(iii)  Choose SOH, CAH or TOA as appropriate.

(iv)  Decide the exact form of the formula.

(v)  Substitute numbers and find the required value.

(vi)  Consider, 'is this a sensible value for this problem?'

Here's an example:

See diagram below.

(i) Yes, it has a right angle.
(ii)  I know Adjacent and Hypotenuse and want the angle.
(iii) I'll use CAH
(iv)  So

(v)  so


so x = 36.9

(vi)  8 is not too far under 10 so the angle is probably under 45.  36 seems reasonable.

Please note, I recommended 6 steps and in my example I wrote down all six.

That way, each step is only a little one so it's easier to take; and if you mis-step, we can immediately spot what went wrong and put you straight.

I've got loads of these trig problems and I'm happy to keep posting them if you want to keep trying them.

Bob

#9719 Re: Help Me ! » Centre of mass » 2010-12-16 07:40:15

Bob

hi Au101,

That's weird.  I didn't see a diagram so I assumed the lamina was lying flat against the plane.

Having read part B, I'm suspecting this may have been a false assumption.

Any chance of getting a diagram into a post?

Bob

#9720 Re: Help Me ! » Sin, Cos, and Tan » 2010-12-16 07:29:39

Bob

hi Aartt,

You know H = 10, and the angle.

You want to find 'O'.

So you should be using SOH.

Do you want to try again from there?

Bob

#9721 Re: Help Me ! » Centre of mass » 2010-12-15 23:05:47

Bob

hi AU101,

6 marks does seem a lot for a simple pythagoras and two easy divisions, but I cannot see a way to make this question more difficult to do.  So well done! Have 6 marks!

I'm guessing that there a part (b) in which you have to do something involving theta.

Perhaps the person who made up the question thought "Part b is the bit I really want to test, so I'll give an easy part a just to get them warmed up"

Bob

#9722 Re: Help Me ! » Sin, Cos, and Tan » 2010-12-15 22:44:53

Bob

hi Aartt,

You'll notice a big time difference between our posts.  My clock is saying that you posted at 5.07 GMT.  I'm in Essex, England, so I was tucked up in bedy-byes at that time.  I've only just logged in to MIF (10.30 GMT).  Sorry for the delay, but this is going to happen as our posts fly around the world.

Your method is exactly right and your answer so well done!

3 sf means three significant figures.  This exam board says that because they don't want students copying 8 or 10 digits off their calculators and because it tests their ability to round off answers sensibly.

So to 3 sf the division should be 0.594.  Then I left the full digit value in my calculator and did the inverse tangent to get 30.69972255 which I rounded to 30.7

I notice your answer is a little below this.  That's because you did the inverse tangent of a figure that was already rounded.  That leads to a minor inaccuracy.  (inv tan 0.59 = 30.54)  Best practice is to leave the full set of figures in your calc. at each stage even if you write down a rounded answer.  That way you preserve maximum accuracy throughout.  But this is a minor point;  the great thing is you applied the right method! smile

At the bottom is another one to try:

Bob

#9723 Re: Help Me ! » Sin, Cos, and Tan » 2010-12-15 04:55:41

Bob

hi Aartt,

Don't be depressed about it.  MIF help will get you there!

This is how I get my students to do these:

(i)  Check you have got a right angled triangle.  (In our exams it's common to give an isosceles triangle.  The students must cut it down the line of symmetry before they can use trig.)

(ii)  Decide what you know:  angle?  adjacent?  opposite?  hypotenuse?  and what you are asked to calculate.

(iii)  Choose SOH, CAH or TOA as appropriate.

(iv)  Decide the exact form of the formula.

(v)  Substitute numbers and find the required value.

(vi)  Consider, 'is this a sensible value for this problem?'

Here's an example:

See diagram below.

(i) Yes, it has a right angle.
(ii)  I know Adjacent and Hypotenuse and want the angle.
(iii) I'll use CAH
(iv)  So

(v)  so

so x = 36.9

(vi)  8 is not too far under 10 so the angle is probably under 45.  36 seems reasonable.

Would you like to try this one:

see second diagram

Bob

#9725 Re: Help Me ! » Sin, Cos, and Tan » 2010-12-15 01:07:50

Bob

Hi bobbym,

I never knew about the

women start chasing you

!!:)!!

Maybe I should re-consider my life-plan.

Now about this cat. 

Is the adjacent still 100ft and the angle 37.  Because I then make it hypotenuse = 125.2ft.

Hint for you and Aartt.

(i) bobbym.  Post a fresh diagram so Aart can see what you're giving for each problem.

(ii) Aartt  Say whether you are using SOH, CAH or TOA each time, then exactly what calculation you are doing, finally your answer.

That way it will be clear where you are going wrong. (or hopefully, not going wrong at all!  smile  )

Bob

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