Math Is Fun Forum

That would work but the Latex interpreter commands are missing. Trouble is if I put them in then the interpreter works and it doesn't show the interpreter command.  So if I leave them out then of course they don't show and if I put them in then they don't show.  I'll try leaving one space between each character to see if that allows me to show what is missing.  You'll have to remove the spaces.

[ m a t h ] \left ( \frac{x+2}{x-2} \right )^5 [ / m a t h ]

Everything after the first ] and until the next [ is ok as it is.

Checked on my Galaxy A21 with Android and Latex shows ok.

Bob

Do you have to work through in order. What happens if you skip straight to calculus.  You'll find some gaps that mean you have to backtrack but I think you'll get to your goal more quickly.

Bob

The notation was invented to make it easier to write very big or very small numbers.

eg 12 000 000 000 000 becomes 1.2 x 10^(13)

0.0000000000000000012 beocmes 1.2 x 10^(-18)

The rule is (a number between 1 and 10) x (the right power of ten so the value of the number is preserved)

Positive powers of ten make numbers bigger and negative numbers smaller.

eg.

12340000

Put the point between the 1 and 2, then count how far it has 'moved' and correct for this by having the right power of ten.

1.234 x 10^(7)

eg.

0.00001234 becomes

1.234 x 10^(-5)

Scientific calculators automatically jump into standard form when the value won't 'fit' the display space.

Bob

Yes or no does imply equal probabilities. Will I win the lottery? The answer is yes or no, but definitely not equally likely.  As worded there's no way you can assess the actual probabilities.

Bob

Yes, your second thoughts are correct.  Work out the probability of football then baseball and add the two answers together.

Bob

root 10 is bigger than 3.16 so that is another possible answer.  If you round off root 10 before testing the criterion then you would need to exclude 3.16 as an answer, but the question isn't worded like that.

Bob

Yes. I think you've got it now. But you can always check with a calculator unless the display hasn't enough digits to avoid index form.

Bob

then

by subtracting the recurring digits cancel out

Bob

No. Move to the left to make a very small number.

B

yes.

B

No.

Suppose n was the number. Let's say its decimal form is 0.00000...x...... Let x be the first non zero digit. There must be such a digit or else the number is zero.  And say the next digits are y and z.

ie. n = 0.00000...xyz...... where every digit before x is zero.  Change x to zero too. New number is 0.00000.....0yz....... so it's smaller. So the number we thought we'd found isn't the smallest.

Bob

Bob