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To Devanté
Quote
Anthony, 0.333..., as you said (I think), multiplied by 3, is 0.999... . Now, 1/3 multiplied by 3 is 3/3, right? If 1/3 = 0.333..., tell me what you answer is when you multiply that my 3. And stop straying from the answer.
3 x Infinite 0.3 ( If it was possible? ) = 0.9999........ /3 = 0.333... multiply that my 3 = 0.9999........
To Ehiness
Quote
Ok I am 99.999...% sure that you have no idea what infinite means.
I am 1% more sure than you that I have more idea what Infinte means,that makes 100%,which is greater than any Infinite Number.
Hi! did not think I would get the chance to put this forward anyway!
Quote: Ricky " Anthony, I'm pretty sure that most people are just ignoring you now."
Maybe in yours eyes they are! but as long as there are an Infinite Amount of people! I will always have people who are not!
(ENDLESS <> END) = (INFINITE 0.9 <> 1)
p.s have a Good One back in the new year!!
A.R.B
So there we have it! No one can say how many .9s it takes for a number to be or become a whole Number!!
Never forget what the great Philosopher/Mathematician MATHIUS (1803) said!
For someone to prove the end of an Infinite Number, would be the same as someone saying, I have captured all the Stars in the Universe, and put them in this Bag!
p.s have a Good One back in the new year!
A.R.B
Lets have a look at why its impossible to Mutilply, Subtract, Divide Etc any Infinite Numbers!
For this I will use the Infinite 4.9 put forward as an example.
A = Infinite 4.9 (stage one) 1 decimal place.
B = Infinite 4.99 (stage two) 2 decimal places.
C = Infinite 4.9 (Actual Number) Endless decimal places!
10 x A = 49.9 we know this is a true Number because we know the size of the Number i.e. 1 decimal place!
10 x B = 49.99 we know this is a true Number because we know the size of the Number i.e. 2 decimal place!
10 x C = 49.9 ? Its impossible to know this because we dont know the size of the number and more important how many decimal places!
The only possible answer would be based on the facts! C started 0.1 less than 1.
In the calculations no other Numbers have been Add to C (or can be!).
No other Numbers have been multiplied,(or can be) the Number remains the Infinite!
So an Answer would be Infinite 4.9 = (0.1 < 5) this way we dont need to know how many .9s there are!
To Ricky first!
Yes 1/3 is a Number! but once it becomes Infinite 0.3 then you can't multiply the Number!
p.s I forgot to say!
"I'ts impossible to actually multiply an Infinite number! because to be able to multiply a number! first a person has to know the size of the number!"
The true value of the infinite number as in your post above is!
10 x 4.9........... = 49.99999999999999999999999999999999999999999999 ..
Now just as I have asked before!! if some can show how many decimal places it takes for Infinite 4.9 to equal or become 5 then we might be getting somewhere!
Or Infinite 0.9 ( How many .9s there are! Or it takes to = ) 1 ?
The Biggest mistake Mathematicians make! Is that they believe an Infinite Endless number some how is! Or ends up a whole number!
The example below is the purest Math, with no assumptions, no beliefs, no forecasts, and no calculations other than what is the truth in front of ones eyes!!
A = 1
B = Infinite 0.9
C = 3
A + B + C = 4.99999999999999 (NOT (5) ?
p.s Fermat never claimed he had a Proof!!
I HAVE DISCOVERED A TRULY MARVELLOUS DEMONSTRATION [ OF THIS GENERAL THEOREM ] WHICH THIS MARGIN IS TOO NARROW TO CONTAIN.
The Beauty of the Method I have put forward to Show In a Demonstration, that all cube numbers are made the same! is just the opposite of what you are saying above.
When I started out to show in a Demonstration if Xn3 + Yn3 = Zn3,I knew it would always be impossible to include the Last test Group of Ten Cube Numbers! This is where the (it is not possible to have a 100% Proof for Any Infinite Math Problem!)
Comes from.
So no matter How large a Test number or Group is put forward, there will always be a larger one!
The only place we can try to prove a problem like this is by looking at the start (How Cube Numbers are Made).
It Can be (Proved!) from the First Ten Cube Numbers Onwards, For as far as (we!) can (Calculate!),That Every Group of Ten Cube Numbers, Repeats Itself as a Pattern!
It is very important to Note that when doing this, we are fully Aware of the Numbers we are Testing, i.e. We know we have started From the Smallest possible (Whole) Cube Number, and worked forward! (We Cannot Start From The End!!).
We are Aware of The Patterns A,B,C Continually being True, we are Aware of the Count Value! i.e. How far we have Gone forward.
Below is The Truth Table for All Groups of Ten Cube Numbers Starting from the first Ten Onwards.
**********************************************************************
CUBE = (n01) last number must = 1) : PATTERN(A) = (a01(1) PATTERN(C) = (c01) : COUNT = (d01)
PATTERN(B) = (b01)
CUBE = (n02) last number must = 8) : PATTERN(A) = (a02(8) PATTERN(C) = (c02) : COUNT = (d02)
PATTERN(B) = (b02)
CUBE = (n03) last number must = 7) : PATTERN(A) = (a03(7) PATTERN(C) = (c03) : COUNT = (d03)
PATTERN(B) = (b03)
CUBE = (n04) last number must = 4) : PATTERN(A) = (a04(4) PATTERN(C) = (c04) : COUNT = (d04)
PATTERN(B) = (b04)
CUBE = (n05) last number must = 5) : PATTERN(A) = (a05(5) PATTERN(C) = (c05) : COUNT = (d05)
PATTERN(B) = (b05)
CUBE = (n06) last number must = 6) : PATTERN(A) = (a06(6) PATTERN(C) = (c06) : COUNT = (d06)
PATTERN(B) = (b06)
CUBE = (n07) last number must = 3) : PATTERN(A) = (a07(3) PATTERN(C) = (c07) : COUNT = (d07)
PATTERN(B) = (b07)
CUBE = (n08) last number must = 2) : PATTERN(A) = (a08(2) PATTERN(C) = (c08) : COUNT = (d08)
PATTERN(B) = (b08)
CUBE = (n09) last number must = 9) : PATTERN(A) = (a09(9) PATTERN(C) = (c09) : COUNT = (d09)
PATTERN(B) = (b09)
CUBE = (n10) last number must = 0) : PATTERN(A) = (a10(0) PATTERN(C) = (c10) : COUNT = (d10)
**********************************************************************
In The Truth Table Above,
The Cube Numbers (n01) to (n10) Are Any Ten Related Cube Numbers (First Ten Onwards).
The Pattern (A) Numbers (a01(1) to (a10(0) Are the End Cube Numbers, And will always be the Same Numbers.
The Pattern (B) Numbers (b01) to (b09) Are the Difference Numbers Working Backwards i.e. (n10)-(n09) Then (n09)-(n08) Etc.
The Pattern (C) Numbers (c01) to (c10) Are the Numbers Produced, From Dividing The Cube numbers (n01) to (n10),
by The Count Numbers (d01) to (d10) (How far we have Gone, from the Start!) i.e. (n01)/(d01) Then (n02)/(d02) Etc.
Below are the Three Constant Pattern Numbers, for All Groups of Ten Cube Numbers!
PATTERN (A) = 1,8,7,4,5,6,3,2,9,0.
PATTERN (B) = 7,9,7,1,1,7,9,7,1.
PATTERN (C) = 1,4,9,6,5,6,9,4,1,0.
So Within the Above Truth Table we Can Place Any Group of Ten Cube Numbers, From the First Ten Onwards, And Prove All Cube Numbers Are Made The Same!
It is Impossible to Place The Largest Possible Group Of Ten Cube Numbers, Because They Can Never be Found! But then that is the Same as Any other Infinity Problem!
So Now we Have a Sound Demonstration, That All Cube Numbers Are Made the Same Way!
The Only way my Demonstration Can Be Proved Wrong! is if Someone Can put Forward Ten Numbers, That pass the Truth Table Tests Above, And the Results Are! None of The Numbers Put Forward Are Cube Numbers! I am Still Waiting!! ARB.
Hi
Everyone
I Have shown that Xn3 + Yn3 does not Equal Zn3
The reason being all cube numbers are made the same! (look at the 3 Patterns ) as shown in my Demonstration!
The same applies for Xn>3 + Yn>3 The 3 Patterns are the same!
Quote Ricky!
Ok lets do this 1/3 = Infinite 0.33333333333333333333...................
Anthony, we are so close. I just ask you to do one further thing. We both agree to the above. Just multiply both sides by 3 and tell me what you get.
The above Number has nothing to do with Infinite 0.9!
Any Calculations you put forward must be based around the number we are working on! ie Infinite 0.9
Its like me saying show me if you can divde 4 by 3 ? and make a whole number!
oh and by the way can you show me that is 7 - 4 = 3 its nothing to do with the above! I just want to see your answer!
If you like this one!! then have a look at this new thread!
FLT DEMONSTRATION By Anthony.R.Brown
FERMATS LAST THEOREM DEMONSTRATION! BY, ANTHONY.R.BROWN (1998 SOLVED )
THE INFINITE MATHEMATICAL PATTERN OF CUBE NUMBERS!
BELOW IS MY DEMONSTRATION OF FERMATS LAST THEOREM,IT IS BASED ON THE INFINITE MATHEMATICAL PATTERN OF THE FIRST (10) CUBE NUMBERS AS A GROUP! YOU WILL SEE THAT THE LAST OR SINGLE NUMBER,FROM EACH OF THE (10) CUBE NUMBERS REPEATS ITSELF AT THE END OF EACH CUBE NUMBER, IN THE COLUMN,GIVEN IN BRACKETS () THIS PATTERN REPEATS ITSELF NO MATTER HOW LARGE OR SMALL THE CUBE NUMBERS ARE.
THE DEMONSTRATION IS! THAT BECAUSE YOU CANNOT ADD ANY TWO CUBE NUMBERS TOGETHER,TO MAKE A THIRD CUBE NUMBER,WITHIN ONE OF THE GROUPS, OR THE SAME WITHIN ANY TWO GROUPS,NO MATTER WHAT SIZE THE CUBE NUMBERS ARE! THEN YOU WILL NEVER BE ABLE TO MAKE A THIRD CUBE NUMBER,FROM ANY TWO CUBE NUMBERS.
Andrew wiles proof? (not possible! 100 %) of ( FLT ) is far too long! And contains math not really needed,with such a simple problem such as ( FLT ) plus only a few people in the world can really understand it.
Fermat stated the words below!
I HAVE DISCOVERED A TRULY MARVELLOUS DEMONSTRATION [ OF THIS GENERAL THEOREM ] WHICH THIS MARGIN IS TOO NARROW TO CONTAIN.
I believe my Demonstration must have been along the same lines as Fermats if not the same.
To understand ( FLT ) the answer is right there at the beginning, just like time itself, everything you need to know is in the first ten cube numbers!
The fact that all the numbers are used from 0 to 9 at the end of the cube numbers,the fact that some of the cubes are odd,the fact that some of the cubes are even,the fact that the cubes as a group look random!
The first ten cubes can be checked amongst themselves, for any two cubes that may make a third,and checked with any other ten as part of their group.
The infinite unique pattern is what makes everything work! Once you understand how cubes are made,then you have found all the cubes!
p.'s except the last!! The last case is unsolvable! for this reason its impossible to have a 100 % Proof! ( and applies to any infinite math problem ) only a Demonstration,as Fermat himself said!
BELOW THE FIRST TEN CUBE NUMBERS.
CUBE = (1): PATTERN = (1): COUNT = 1
CUBE = (8): PATTERN = (8): COUNT = 2
CUBE = 2(7): PATTERN = 2(7): COUNT = 3
CUBE = 6(4): PATTERN = 6(4): COUNT = 4
CUBE = 12(5): PATTERN = 12(5): COUNT = 5
CUBE = 21(6): PATTERN = 21(6): COUNT = 6
CUBE = 34(3): PATTERN = 34(3): COUNT = 7
CUBE = 51(2): PATTERN = 51(2): COUNT = 8
CUBE = 72(9): PATTERN = 72(9): COUNT = 9
CUBE = 100(0): PATTERN = (0): COUNT = 10
BELOW THE NEXT TEN.
CUBE = 133(1): PATTERN = (1): COUNT = 11
CUBE = 172(8): PATTERN = (8): COUNT = 12
CUBE = 219(7): PATTERN = 2(7): COUNT = 13
CUBE = 274(4): PATTERN = 6(4): COUNT = 14
CUBE = 337(5): PATTERN = 12(5): COUNT = 15
CUBE = 409(6): PATTERN = 21(6): COUNT = 16
CUBE = 491(3): PATTERN = 34(3): COUNT = 17
CUBE = 583(2): PATTERN = 51(2): COUNT = 18
CUBE = 685(9): PATTERN = 72(9): COUNT = 19
CUBE = 800(0): PATTERN = (0): COUNT = 20
AND THE NEXT TEN ETC.!
CUBE = 926(1): PATTERN = (1): COUNT = 21
CUBE = 1064(8): PATTERN = (8): COUNT = 22
CUBE = 1216(7): PATTERN = 2(7): COUNT = 23
CUBE = 1382(4): PATTERN = 6(4): COUNT = 24
CUBE = 1562(5): PATTERN = 12(5): COUNT = 25
CUBE = 1757(6): PATTERN = 21(6): COUNT = 26
CUBE = 1968(3): PATTERN = 34(3): COUNT = 27
CUBE = 2195(2): PATTERN = 51(2): COUNT = 28
CUBE = 2438(9): PATTERN = 72(9): COUNT = 29
CUBE = 2700(0): PATTERN = (0): COUNT = 30
EXAMPLE BELOW : TRY TO FIND IF THE TWO NUMBERS BELOW ADD TOGETHER MAKE A CUBE NUMBER!
2685619 + 4173281 = 6858900
Following what I have said in my Demonstration,all cube numbers are made in the same way,the infinite pattern is unique in the fact that the numbers 0 to 9 are only used once as in PATTERN A, at the end of the cubes numbers,within each group of any ten! plus more proof further on.
What it is like is a Mathematical engine that produces the cube numbers in unique groups of ten,starting from the first group of ten onwards Infinitely.
The sum of the two numbers above ( 6858900 ) is not a cube number! the reason its not a cube number is because it does not fit in any of the groups of ten,that are produced!
The nearest cube number too ( 6858900 ) is ( 6859000 ) this cube number is part of the 19 th Group given below,and is just before the start of the 20 th Group.
I will explain more how the Demonstration works below!
19 th Group
CUBE = 5929741 : PATTERN A = (1)
CUBE = 6028568 : PATTERN A = (8)
CUBE = 6128487 : PATTERN A = 2(7)
CUBE = 6229504 : PATTERN A = 6(4)
CUBE = 6331625 : PATTERN A = 12(5)
CUBE = 6434856 : PATTERN A = 21(6)
CUBE = 6539203 : PATTERN A = 34(3)
CUBE = 6644672 : PATTERN A = 51(2)
CUBE = 6751269 : PATTERN A = 72(9)
CUBE = 6859000 : PATTERN A = (0)
20 th Group
CUBE = 6967871 : PATTERN A = (1)
CUBE = 7077888 : PATTERN A = (8)
CUBE = 7189057 : PATTERN A = 2(7)
CUBE = 7301384 : PATTERN A = 6(4)
CUBE = 7414875 : PATTERN A = 12(5)
CUBE = 7529536 : PATTERN A = 21(6)
CUBE = 7645373 : PATTERN A = 34(3)
CUBE = 7762392 : PATTERN A = 51(2)
CUBE = 7880599 : PATTERN A = 72(9)
CUBE = 8000000 : PATTERN A = (0)
MORE INFORMATION BELOW ON HOW MY DEMONSTRATION WORKS!
The next pattern is the group of numbers that are produced, by taking away the cube numbers starting with the largest and working backwards,as in the first group below,so 1000 - 729 = (271),729 - 512 = (217),512 - 343 = (169),343 - 216 = (127),216 -125 = (91),125 - 64 = (61),64 - 27 = (37),27 - 8 = (19),8 - 1 = (7).
What we now have is the second unique pattern (B),that shows us we have a group of related cube numbers,the end numbers are made up of 7,9,7,1,1,7,9,7,1 in brackets ()
1 st Group PATTERN B
CUBE = 1
DIFFERENCE = 7 : PATTERN B = (7)
CUBE = 8
DIFFERENCE = 19 : PATTERN B = (9)
CUBE = 27
DIFFERENCE = 37 : PATTERN B = (7)
CUBE = 64
DIFFERENCE = 61 : PATTERN B = (1)
CUBE = 125
DIFFERENCE = 91 : PATTERN B = (1)
CUBE = 216
DIFFERENCE = 127 : PATTERN B = (7)
CUBE = 343
DIFFERENCE = 169 : PATTERN B = (9)
CUBE = 512
DIFFERENCE = 217 : PATTERN B = (7)
CUBE = 729
DIFFERENCE = 271 : PATTERN B = (1)
CUBE = 1000
Now we move on to pattern (C) this pattern is made by dividing the actual COUNT position,in relation to where the cube numbers are from the start onwards! NOTE: the resulting numbers are always WHOLE numbers! the end numbers are made up of 1,4,9,6,5,6,9,4,1,0 in brackets ()
1 st Group PATTERN C
CUBE = 1 : COUNT = 1 : EQUALS 1 : PATTERN C = (1)
CUBE = 8 : COUNT = 2 : EQUALS 4 : PATTERN C = (4)
CUBE = 27 : COUNT = 3 : EQUALS 9 : PATTERN C = (9)
CUBE = 64 : COUNT = 4 : EQUALS 16 : PATTERN C = (6)
CUBE = 125 : COUNT = 5 : EQUALS 25 : PATTERN C = (5)
CUBE = 216 : COUNT = 6 : EQUALS 36 : PATTERN C = (6)
CUBE = 343 : COUNT = 7 : EQUALS 49 : PATTERN C = (9)
CUBE = 512 : COUNT = 8 : EQUALS 64 : PATTERN C = (4)
CUBE = 729 : COUNT = 9 : EQUALS 81 : PATTERN C = (1)
CUBE = 1000 : COUNT = 10 : EQUALS 100 : PATTERN C = (0)
Now lets see if the number ( 6858900 ) the sum of the two numbers is a cube number or not! I will put the number in the group where the number is closest matched,which happens to be the tenth place within the 19 th Group below,and replace the true cube number ( 6859000 ) with the number ( 6858900 ) and see what happens to the patterns A,B,C!
19 th Group
CUBE = 5929741 : PATTERN A = (1) : COUNT = 181 : EQUALS 32761 : PATTERN C = (1)
DIFFERENCE = 98827 : PATTERN B = (7)
CUBE = 6028568 : PATTERN A = (8) : COUNT = 182 : EQUALS 33124 : PATTERN C = (4)
DIFFERENCE = 99919 : PATTERN B = (9)
CUBE = 6128487 : PATTERN A = 2(7) : COUNT = 183 : EQUALS 33489 : PATTERN C = (9)
DIFFERENCE = 101017 : PATTERN B = (7)
CUBE = 6229504 : PATTERN A = 6(4) : COUNT = 184 : EQUALS 33856 : PATTERN C = (6)
DIFFERENCE = 102121 : PATTERN B = (1)
CUBE = 6331625 : PATTERN A = 12(5) : COUNT = 185 : EQUALS 34225 : PATTERN C = (5)
DIFFERENCE = 103231 : PATTERN B = (1)
CUBE = 6434856 : PATTERN A = 21(6) : COUNT = 186 : EQUALS 34596 : PATTERN C = (6)
DIFFERENCE = 104347 : PATTERN B = (7)
CUBE = 6539203 : PATTERN A = 34(3) : COUNT = 187 : EQUALS 34969 : PATTERN C = (9)
DIFFERENCE = 105469 : PATTERN B = (9)
CUBE = 6644672 : PATTERN A = 51(2) : COUNT = 188 : EQUALS 35344 : PATTERN C = (4)
DIFFERENCE = 106597 : PATTERN B = (7)
CUBE = 6751269 : PATTERN A = 72(9) : COUNT = 189 : EQUALS 35721 : PATTERN C = (1)
Below is the tenth place!
Below is the true cube number,and shows all three Patterns working as normal!
DIFFERENCE = 107731 : PATTERN B = (1)
CUBE = 6859000 : PATTERN A = (0) : COUNT = 190 : EQUALS 36100 : PATTERN C = (0)
Below is the new number,you will notice the number works with only two of the patterns,but is way out with the third,i.e. not a WHOLE number! and ending with the wrong number in the () this proves its not a cube number!
DIFFERENCE = 107631 : PATTERN B = (1)
CUBE = 6858900 : PATTERN A = (0) : COUNT = 190 : EQUALS 36099.473 : PATTERN C = (int(9)? or (3)? both are wrong!
MORE INFORMATION BELOW ON HOW MY DEMONSTRATION WORKS!
As I have already said,all cube numbers are made the same way using what I would like to call a MATHEMATICAL ENGINE!
the process is from the first single cube number (1) onwards.
The most important numbers are the end numbers in brackets () the reason they are the most important is because they are the end of the process for making cube numbers! they are if you like the TRUTH numbers! its a bit like the numbers go round and round mathematically,and eventually make a whole cube number!
I have put forward three patterns A,B,C that show how these TRUTH numbers are present in any group of ten cube numbers,I am again giving the 1st and 19th Groups as examples!
The size of the cube numbers never changes how these TRUTH numbers are made! another way of looking at what im saying is that the cube numbers in the 1st Group are the same as in the 19th Group by the way they are made, and both are the same as any other group! size does not affect the TRUTH number results!
So if these two groups are the same,then trying to find if any two cube numbers make a third ,within the first group! is the same as trying with any other group,then after that test! we only need to test two groups against each other,because the maximum test is two from one group,or one from each group!
Now if we want to find out if a group of any ten numbers are cube numbers,the ten numbers must pass the three tests,they must conform to the patterns A,B,C and at the same time if we want to test if any single number is a cube number,this can be done by finding if it fits in with the nine cube numbers that are related to it,as part of its own group!.
PATTERN (A) = 1,8,7,4,5,6,3,2,9,0 in brackets ()
PATTERN (B) = 7,9,7,1,1,7,9,7,1 in brackets ()
PATTERN (C) = 1,4,9,6,5,6,9,4,1,0 in brackets ()
1 st Group
CUBE = 1: PATTERN A = (1) : COUNT = 1 : EQUALS 1 : PATTERN C = (1)
DIFFERENCE = 7 : PATTERN B = (7)
CUBE = 8: PATTERN A = (8) : COUNT = 2 : EQUALS 4 : PATTERN C = (4)
DIFFERENCE = 19 : PATTERN B = (9)
CUBE = 27: PATTERN A = (7) : COUNT = 3 : EQUALS 9 : PATTERN C = (9)
DIFFERENCE = 37 : PATTERN B = (7)
CUBE = 64: PATTERN A = (4) : COUNT = 4 : EQUALS 16 : PATTERN C = (6)
DIFFERENCE = 61 : PATTERN B = (1)
CUBE = 125: PATTERN A = (5) : COUNT = 5 : EQUALS 25 : PATTERN C = (5)
DIFFERENCE = 91 : PATTERN B = (1)
CUBE = 216: PATTERN A = (6) : COUNT = 6 : EQUALS 36 : PATTERN C = (6)
DIFFERENCE = 127 : PATTERN B = (7)
CUBE = 343: PATTERN A = (3) : COUNT = 7 : EQUALS 49 : PATTERN C = (9)
DIFFERENCE = 169 : PATTERN B = (9)
CUBE = 512: PATTERN A = (2) : COUNT = 8 : EQUALS 64 : PATTERN C = (4)
DIFFERENCE = 217 : PATTERN B = (7)
CUBE = 729: PATTERN A = (9) : COUNT = 9 : EQUALS 81 : PATTERN C = (1)
DIFFERENCE = 271 : PATTERN B = (1)
CUBE = 1000: PATTERN A = (0) : COUNT = 10 : EQUALS 100 : PATTERN C = (0)
19 th Group
CUBE = 5929741 : PATTERN A = (1) : COUNT = 181 : EQUALS 32761 : PATTERN C = (1)
DIFFERENCE = 98827 : PATTERN B = (7)
CUBE = 6028568 : PATTERN A = (8) : COUNT = 182 : EQUALS 33124 : PATTERN C = (4)
DIFFERENCE = 99919 : PATTERN B = (9)
CUBE = 6128487 : PATTERN A = (7) : COUNT = 183 : EQUALS 33489 : PATTERN C = (9)
DIFFERENCE = 101017 : PATTERN B = (7)
CUBE = 6229504 : PATTERN A = (4) : COUNT = 184 : EQUALS 33856 : PATTERN C = (6)
DIFFERENCE = 102121 : PATTERN B = (1)
CUBE = 6331625 : PATTERN A = (5) : COUNT = 185 : EQUALS 34225 : PATTERN C = (5)
DIFFERENCE = 103231 : PATTERN B = (1)
CUBE = 6434856 : PATTERN A = (6) : COUNT = 186 : EQUALS 34596 : PATTERN C = (6)
DIFFERENCE = 104347 : PATTERN B = (7)
CUBE = 6539203 : PATTERN A = (3) : COUNT = 187 : EQUALS 34969 : PATTERN C = (9)
DIFFERENCE = 105469 : PATTERN B = (9)
CUBE = 6644672 : PATTERN A = (2) : COUNT = 188 : EQUALS 35344 : PATTERN C = (4)
DIFFERENCE = 106597 : PATTERN B = (7)
CUBE = 6751269 : PATTERN A = (9) : COUNT = 189 : EQUALS 35721 : PATTERN C = (1)
DIFFERENCE = 107731 : PATTERN B = (1)
CUBE = 6859000 : PATTERN A = (0) : COUNT = 190 : EQUALS 36100 : PATTERN C = (0)
THE ABOVE EXAMPLES CLEARLY SHOW ALL CUBE NUMBERS ARE MADE THE SAME WAY! SO THE METHODS USED TO SEE IF ANY TWO NUMBERS MAKE A CUBE NUMBER, WILL ALWAYS BE THE SAME! REGARDLESS OF THE SIZE OF THE NUMBERS.
Please forward any comments to me at my E-MAIL address below,or to any Forum this (FLT) Demonstration is on!
TONYSWWW@YAHOO.CO.UK
A.R.B
To Ricky! again I asked the Question first!!
To Ricky!
Ok lets do this 1/3 = Infinite 0.33333333333333333333...................
Agreed! and....Infinite 0.9 = 0.99999999999999999999................... which you say = 1
So if you are correct then Infinite 0.3333333333333333.................. must = > 0.3
Incase you dont understand the Above!
If one Infinite number,is or becomes another number from the number it started as! ie Infinite 0.9 (stage one) becomes or is some how equal to 1 ?
then surley using your Logic! all Infinte numbers! ie Infinite 0.3 (stage one) must also do the same!!
To Ricky!
Ok lets do this 1/3 = Infinite 0.33333333333333333333...................
Agreed! and....Infinite 0.9 = 0.99999999999999999999................... which you say = 1
So if you are correct then Infinite 0.3333333333333333.................. must = > 0.3
To Ricky!
I asked the Question first!!
Infinite 0.9 ( How many .9s there are! Or it takes to = ) 1 ?
To Ricky
Quote: "Anthony, what is the result when you divide 1 by 3, in decimals?"
Erh! I reckon the true Answer has an Infinite number of Decimal Places!!
To luca-deltodesco
Quote:"you really aernt getting this are you anthony, this really is like talking to a brick wall?"
The Brick wall argument has already been tried!!
QUOTE:
simron
Member
Re: 0.9999....(recurring) = 1So I guess that the official notation for this would be
lim(.999...)=1
Tell me if I am using the limit wrongly.
Hi! simron! or should that be "stillwrong" just to let you know! you are still wrong,
it should be Endless(.999...)<>1 because no one knows How many .9s there are! Or it takes to = ) 1 ? ie so far no limit!!
--------------------------------------------------------------------------------
So there we have it! A simple counter Proof to any Proof put forward so far,that says Infintite 0.9 = 1
Unless someone can actually say how many .9s there are! Or it takes for Infinite 0.9 to be! Or to equal 1,then its impossible for them to say they have a Proof!
But if someone has found the number Please insert your number in the Brackets below!
Infinite 0.9 ( How many .9s there are! Or it takes to = ) 1 ?
OK LET'S SEE IF SOMEONE CAN REALLY PROVE THIS QUESTION!
Infinite 0.9 (stage one) the start! = 0.9 that is a 0 then a . then a 9 (this is the first .9)
If anyone can? using time a guide to how far the calculations have run,prove that Infinite 0.9 = 1 ?
0.9999999999999999999999999999999......
Ok! for every .9 above I am going to use (1) second of time!
So now give me! using time how long it will take for Infinte 0.9 to = 1
Example below!
0.9 = (1 second) 0.99 = (2 seconds) 0.999 = (3 seconds) etc.........................
Genius! is seen in the eyes of others! when the problem is made clear! by the Genius!
A.R.B
To Ricky!
QUOTE: "I feel like I'm talking to a brick wall, and I'm getting tired of it."
This is a good point! at the end? of the Universe! and at the end? of an Infinite Number! there is a BRICK WALL! but unfortunatly behind the BRICK WALL! is an endless stream of .9's