You are not logged in.
Calculate the area for each of the polygons below. If you do not know an equation to use, divide the polygon into other shapes to determine the area.
1. An equilateral triangle with a side of 1 inch
A0.43 sq in
B0.56 sq in
C0.89 sq in
D0.23 sq in
E 0.19 sq in
F 0.54 sq in
2. A square with a side of 2 feet
A9 sq ft
B4 sq ft
C2 sq ft
D7 sq ft
E 3 sq ft
F 8 sq ft
3. A regular pentagon with a side of 3 centimeters
A23.01 sq cm
B12.34 sq cm
C39.17 sq cm
D9.46 sq cm
E 34.21 sq cm
F 15.48 sq cm
4. A regular hexagon with a side of 10 cm
A641.25 sq cm
B194.45 sq cm
C361.25 sq cm
D259.81 sq cm
E 105.22 sq cm
F 453.01 sq cm
5. A regular heptagon with a side of 7 inches.
A178.06 sq in
B294.16 sq in
C169.21 sq in
D358.91 sq in
E 157.36 sq in
F 277.91 sq in
6. A trapezoid where the height is 18 cm, base 1 = 16 cm and b2 = 8 cm.
A178.06 sq cm
B122.5 sq cm
C216 sq cm
D230 sq cm
E 280.9 sq cm
F 510 sq cm
7. A trapezoid where the height = 7 mm, base 1 = 26 mm and base 2 = 9 mm.
A178.06 sq mm
B122.5 sq mm
C216 sq mm
D230 sq mm
E 28.9 mm
F 510 mm
Fill in the missing information for the following trapezoids:
8.
height = 19.8 cm
b1 = ________
b2 = 14.4 cm
area = 401.94 cm2
A26.2 cm
B12.5 cm
C216 cm
D23 cm
E 28.9 cm
F 51 cm
9.
height = 23 mm
b1 = 23 mm
b2 = ________
area = 529 mm2
A78.06 sq mm
B22.5 sq mm
C21.6 mm
D23 mm
E 28.9 mm
F 30 mm^2
10.
height = ________
b1 = 20 cm
b2 = 21 cm
area = 205 cm2
A17.06 cm
B12.5 sq cm
C26 cm
D10 cm
E 28.9 cm
F 50 cm^2
11.
height = 28.9 m
b1 = 26.9 m
b2 = ________
area = 806.31 m^2
A17.06 sq m
B15 m
C46 m
D23 m
E 28.9 m
F 51 m
12. If the area of a parallelogram is 690.84 m^2 and the height is 20.2 m, what is the length of the base?
A78.06 m
B22.5 m
C216 m
D34.2 m
E 28.9 m
F 51 m
13. If the base of a rectangle is 28 cm and the area is 588 cm^2, what is the height of the rectangle?
A17.06 cm
B122.5 sq cm
C216 sq cm
D23 cm
E 21 cm
F 51 cm^2
14. If the height of a rectangle is 26.1 m and the base is 17.3 m, what is the area of the rectangle?
A451.53 m^2
B122.5 m^2
C216 m^2
D430 m^2
E 289 m^2
F 510 m^2
15. If the height of a parallelogram is 34 cm and the base is 15 cm, what is the area of the parallelogram?
A178.06 cm^2
B122.5 cm^2
C216 cm^2
D230 cm^2
E 289 cm^2
F 510 cm^2
16. What is the area of a parallelogram with height 26 cm, base 16 cm, and side length 28 cm?
A178.06 sq cm
B122.5 sq cm
C216 sq cm
D416 cm^2
E 28.9 cm
F 510 cm^2
17. What is the area of a regular octagon with a side of 6 cm?
A178.06 sq cm
B122.5 sq cm
C216 sq cm
D23 cm^2
E 173.82 cm^2
F 510 cm^2
18. What is the area of this polygon?
ls_XF = 53 mm ls_XV = 72 mm ls_VR = 16 mm
ls_FB = 31 mm ls_BT = 31 mm ls_EU = 47 mm
ls_UL = 31 mm ls_TL = 88 mm ls_DE = 16 mm
ls_RM = 70 mm ls_MC = 21 mm ls_DC = 70 mm
A8014 mm2
B7030 mm2
C6027 mm2
D5478 mm2
E 1782 mm2
F 1225 mm2
19. What is the area of this rectangle?
A17.06 sq units
B60 sq units
C21.6 sq units
D53 sq units
E 28.9 sq units
F 51 sq units
20. What is the area of this polygon?
A178 sq units
B129 sq units
C230 sq units
D240 sq units
E 219 sq units
F 206 sq units
I don't understand what my teacher is asking
I dont understand.... please someone help fast ive been on this lesson forever
SHE SAID
Please simplify your answer. Don't forget the unit of measure, too, please.
PLEASE HELP
How do I do this with 75?
Please help fast so i can go onto the next lesson!
She said
You CORRECTLY calculated 75 pi as the overlap, and you should include that value when you answer problem #10.
I told her I thought we corrected the answer. I'll let you know what she says.
On July 31, you did not calculate "95" as the overlap. You calculated "75 pi."
MY teacher said that
So
1875(pi)+225(pi)+225(pi)-95
= 7209.20292
#10
I added number from questions 6,7,8 and subtracted from number 9.
1875(PI)+225(PI)+225(PI) 75
2325(PI) 75
7304.202 75
7229.202 answer
I DID THAT ON JULY 31
My teacher said
I am not accusing you of cheating, in any way. On July 31, you did a precise calculation of the overlap. I am merely asking you to use that correct value in your calculations for problem #10.
My teacher said..
You DO subtract the overlap. But it doesn't equal 95. Your own calculations did not produce "95" as the overlap.
Okay so if i subtract 95, then what?
Do you subtract 95?
Yes i am having difficulty viewing these. i really need to finish this lesson, i have been stuck for too long
What did zee-f use?
I need the correct values so I can add 6,7,8 and subtract 9...
I know but i cannot figure out the answer
What is Q10?
well what estimate should i try
I really dont understand what you or my teacher are saying, please explain.
my teacher said the overlap i calculated earlier is not 75
1875 PI is 5890.486
5890.486225+706.858+706.858-75= 7229.312
Q6
43.301????
right