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The bob bundy argument is in fact correct (as usual), this equation has no solution in the real field. However, since you did not specify the field of the required solution this opens the door to consider a solution in other fields. Form this respect, it has a solution in the complex field and in the field of residue classes modulo 7. In the complex field it has eight roots namely:
I think this question is a little bit tricky. The answer which is provided is correct if the final phrase was “if one of them must be five”. However, the phrase is stating that “if you know one of them is five”, so how could you know that a number is exsit without its actual existence? Therefore, I think it is more appropriate in the later case to have one of the dice has the number five already exist on its upper face and the other has a possible outcome of six values hence the answer in this case would be 1/6.
It is very simple. You have to use the "strict' triangle inequality which states that the sum of the lengths of any two sides of a triangle is greater then the length of the other side or more precisely if x, y and z are the lengths of the sides of a given triangle then:
Hi kappa_am, Sorry I just saw the post. What exactly you are trying to do? Please give me more information.
It turns out that your approach to this problem related to the "conservation of energy" is incorrect. When calculate the work done by the weight in stretching the elastic string, you have supposed that the force acting on the particle is constant and equal to the weight. However, the tension in the string exerts a force on the weight equal to the sum of the vertical components of the tensions in the AC and CB parts of the elastic string, so the force which exerts a work on the particle is, in fact, variable! Taking this observation into our account, the work done to stretch the string is given by:
OK! You have reached different results because you assumed that the bowl reaction on the particle is "zero" when you calculated the "gravitational potential energy", according to your first argument the particle rest on the surface of the bowl without any force from the bowl on the particle. Therefore, you have, unconsciously, underestimated the weight W of the particle. This is confirmed by the following reasoning:
It is absolutely impossible assumption since the gravitational field is conservative hence the work done to reach two points of it is independent of the path between them (in fact, this explains why they did not mention the path taken by the particle in the problem). However, your solution is correct in the sense which I have explained to you, since the problem has no reference to the unit used to measure the weight (in this case they should say something like " a particle of weight W newtons"), so if you reject that reasoning then you are equivalently assuming that the weight is measured by the common units to which there is no reference in the problem. I have reviewed your solution and did not find any mistake even the elastic potential energy is derived correctly from Hook's law:
If your assumption is correct (i.e. the weight should be measured using the common units) then maybe there is something which I didn't notice.
Hi glendismollinew, your solution (if I am not mistaken) is correct. But, to err on the caution side, the only one preservation on your solution is that you have assumed that the triangle is a right-angled triangle which sounds more as a theory so it ought to be proven. However, if the general case is assumed, we will get a more sophisticated solution, so I will suppose that your assumption is plausible. With the previous notes in mind, you have, in fact, accomplished the required proof! This stems form your final result as follows:
which is the required result. If a quantity is proportional to another quantity then each or both of them can be measured such that their constant of proportionality is normalized (i.e. equal to unity). This solution remains correct since the problem does not restrict you to deduce the required result for particular unit of weight.
It can fit to the 9 graders, just change the "total surface area" to the "lateral surface area" and everything will be fine. In fact it is a common practice in mathematics to refer to the lateral surface area as the "surface area" without any restriction. If the problem composer want the reader to include the areas of the bases they usually refer to that by the phrase "total surface area".
If you would like to avoid trigonometry you can use Maclaurin series of the inverse trigonometric functions. So if we let D=r-d we would have:
So there is no trigonometry at all and I think the 9 graders can do the arithmetic operations.
It is very simple! the surface areas of the first and the second cones are given, respectively, by:
so the ratio is 1. I hope that answer your question.
I am sure that there are several approaches to tackle the problem. However, one of them is as follows:
If we let d and r to be the water height in the pipe and the radius of the base of the pipe, respectively, then we would have:
Note: We get the Volume of the cylinder (the water pipe) in the case that r-d=-r (that is when the pipe is full of rain water).
Hi kappa_am, sorry for delay. In fact sciences are human inventions, so we can modify, change or create any concepts to be suitable to answer our needs (always keep in your mind that you can solve any problem, but you have to figure out how to do it). The derivations are very simple. Suppose that we have an oblique triangle with sides a, b and c which are opposite to the angles
and , respectively, and suppose further that we have taken the angle to be opposite to the hypotenuse (c in this case), then from the sines law we have:Now define the generalized Trigonometric functions (suggested by their traditional definitions) as follows:
But from the sines law we have:
and hence:
Which are the required results.
Note: The fundamental identity can be generalized using the cosine law and the other identities have also their generalized versions, but they are very sophisticated (ugly). Please do not hesitate to ask, if you have any question. It was a great time to meet you.
Dear kappa_me, to what extent do you what to go deeper. The subject is very broad, we can talk about plain Trigonometry, spherical Trigonometry, hyperbolic Trigonometry and a mixture of them. The formulae which I have given you is my generalization of the traditional definition of the Trigonometric functions (which is a paraphrasing of the sines law). If you wonder why they are work, the reason is very simple: The nomenclature of any science is an equivalence class and the definitions into each vicar of the nomenclature aggregate into definitional clusters which have infinitely many vicars that could be used to represent them. If you would like the derivation of these formulae I could provided it to you, also if you have questions about the "plain Trigonometry" (since you are asking about it), please go head and ask them. Finally, if you want a reference about the plain Trigonometry with a lot of solved questions I would recommend "Schaum's Outline of Trigonometry, 5th Edition".
By the way, what is your profession?
My approach to this problem is to generalize the definition of trigonometric functions by taking the angle
opposite to the hypotenuse to be . In this case, by using the sine laws, it can be show that:and hence in your situation the decomposition will be:
Notice that:
The above formulae can be used with any oblique Cartesian coordinate system. I hope that will answer your question.
If we drop a vertical line on the side that is opposite to any vertex of the equilateral triangle it will bisect it, so since the are of a triangle is half the base (b) times the height (h), we would get:
Note: What do you what to do exactly? It is easier to calculate the Area using the original definition than using trigonometry!! It is like trying to kill a sparrow by a cannon!!
It can be shown that this probability problem follows the binomial distribution which is given by:
Note: If you would like the proof that this type of discrete probability problem does, in fact, follow the binomial distribution, I can provide it to you.
Of course!! And you deserve an addisional award for your creativity also
Excellent!!
Some elaborations to whom it may interest. The number "n" in the preceding argument is a discrete variable hence, by definition, we can not use the differentiation to calculate its limit (by applying L'Hopital's Rule). However, if we define a continuous variable x on the interval [1,ꝏ] , then we can write x=n+m where n and m are the integer part and the decimal part of x, respectively. So we have:
Hi bob bundy, in fact, your reasoning is correct, since the problem is a weighted arithmetic mean and each probability is actually the weight of the corresponding team (the total of the weights of all terms is 1). You don't have to derive a closed formula of the sum (I don't try, but from my experience, in these types of expressions, there is usually no closed form). However, we have:
It can be proven that the sum of an arithmetic series with general difference of 1 is given by:
I assume that you mean:
The use of "i" instead of "k" in the last step is valid since "i" and "k" are dummy variables. I hope that will answer your question.
OK, brilliant!! The problem should then be restated as follows:
``How long does it take to pay off a $125000 mortgage if the annual interest rate is 5.5% and compounded monthly with a monthly payment of $710?. hint:
and hence the solution goes as follows:
which is the final formula that you have utilized. However, solving for n and plugging the numbers we get:
Note: The students should have been taught that:
Otherwise, the hint should be included. Thank you very much Mathegocart. I hope that will help you Davidtrinh.
Dear Davidtrinh and Mathegocart, the question simply has something wrong with it. The numbers “30 years” and “94.3 years” are irrational (it is like calculating the length of a person, according to some data, and finding it to be 3 km!!). There is no “bank” that accepts this contract. Actually, in normal circumstances, the bank increases the period of payment if the costumer borrows more money until the period reaches a particular number of years (usually 6-8 years), then they would not increase the period no matter what is the amount that was borrowed. Therefore the problem is unrealistic which is not expected from a textbook. The number “30 years” is probably a typo and the correct number seems to be “3 years”. On the other hand, the formula used by “Mathegocart” is probably not the correct one, since this equation is derived to calculate the saving account balance after a period of time in the case that an amount “P” is deposited in the bank (calculating the monthly payment of a loan in this way is a little bit strange). Finally, even if we assume that the number of years was not “30 years”, there would be a number of possible ways to calculate the period depending on the method applied for calculation. Therefore, without any further information, your question can not be solved “correctly”. This is, in fact, the reason why the brilliant mathematicians in this site did not answer this question.