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#27 Re: Puzzles and Games » Easy one » 2005-05-13 13:37:55

I would like you to try "What should be the question" puzzle - that one is much more difficult, and more interesting. - some members have mentioned that you can solve it. Can you?

#28 Re: Puzzles and Games » Easy one » 2005-05-13 13:30:05

Zach wrote:
Milos wrote:

OK. For one day it climbs 1m(I agree with that ; 3-2=1), but when it comes to 17m(17th day) , it has 3m to reach the top. As it climbs 3m for 12h, he will reach the top on 18th day.

smile

Incorrect, though I see your logic.

The answer is the 17th day with this new answer. On the 18th day, he'd be at 18m.

after 1st day-1m
after 2nd day-2m
after 3rd day-3m
after 17th day-17m
day-24h
now, as there are 3m left, in the first part of 18th day (first 12h) it will reach the top. So it is 18th day, not 17th. It doesn't need to go back when it has reached the top -or if it does, that does not interest us. Question was:' When will it reach the top', so if it wants to jump after reaching the top that is its problem, not ours. smile
I hope you understand it know. My answer is correct, I assure you.

#29 Re: Help Me ! » Sum of positive integers 0 to N » 2005-05-13 06:34:31

I have learned this formula before. It is connected with mathematical induction. German mathematician Gauss, when he was 7 years old, thought of this formula. His teacher told students to find the sum of numbers, starting from 1 to 100. He thought that students won't finish it in next 30 minutes, but Gauss did. n(n+1)/2 where n is the last number.
This formula can be generalised so you can start from any number you like that belongs to N:
since n(n+1)/2 is when you start from  1, we will subtract the sum that needs to be subtracted:
if you are starting from 3 you will subtract from the main formula, 1+2. So let's write it:
n(n+1)/2 - x(x+1)/2
x=number below the one you are starting from
st= starting number
n(n+1)/2 - (st-1)(st-1+1)/2= [n(n+1)-st(st-1)]/2=[n^2+n-st^2+st]/2=[(n-st)(n+st)+n+st]/2=(n+st)(n-st+1)/2 -formula that administrator has mentioned
You also have formula for:
n e N   1^2+2^2+3^2.......n^2= n(n+1)(2n+1)/6

#30 Re: Puzzles and Games » Easy one » 2005-05-13 05:39:32

OK. For one day it climbs 1m(I agree with that ; 3-2=1), but when it comes to 17m(17th day) , it has 3m to reach the top. As it climbs 3m for 12h, he will reach the top on 18th day.

smile

#31 Re: Puzzles and Games » Easy one » 2005-05-12 22:38:45

No Zach, that is not correct. I will leave it unsolved, because I want others to try.
There is not a French man who eats it, and all parameters needed for solving puzzle are given.

#32 Re: Help Me ! » Algebra help » 2005-05-12 22:20:21

2AB = 2x - 1  ^2
4A^2B^2=4x^2 - 2x + 1
Now: A=sqr(x+1); B=sqr(x-1)
4x^2-4=4x^2 - 4x + 1
then:
4x=5
x=5/4
It was easy, because administrator has finished the difficult part.

#33 Puzzles and Games » Easy one » 2005-05-12 11:36:42

Milos
Replies: 25

In the first 12 hours snail climbs 3m, and in next 12 hours it slides down 2. If a column is 20m high, when will snail reach the top of it?(e.g. on the 5th day)

#34 Re: This is Cool » Mathematic complexity » 2005-05-09 07:33:38

Roraborealis wrote:

When you say "time," what do you mean? I understand how space can be dragged into a hole, but I don't understand how time, the thing that passes us for ever, can.

Physics of Time   
Einstein’s first major contribution to the study of time occurred in 1905, when he introduced his special theory of relativity and showed how time changes with motion. The word relativity derives from the fact that the appearance of the world depends on the observer’s state of motion and is relative to the observer. Today scientists do not see problems of time or motion as absolute with single correct answers. Because time is relative to the speed an observer is traveling, there can never be a clock at the center of the universe to which everyone can set his or her watch. Einstein’s special theory of relativity tell us that an object traveling at high speeds ages more slowly than an object that is not traveling as fast. This means that if a person from Earth were to travel in outer space at a speed close to the speed of light (about 300,000 km per sec or about 186,000 mi per sec), that person could return to Earth thousands of years into Earth’s future.
Time is distorted in regions of large masses, such as stars and black holes. In Einstein’s general theory of relativity, which was introduced in 1916, the very existence of time depends on the presence of space. Einstein’s general theory explains how gravity warps and slows time and why time moves very slightly slower in regions of high gravity, such as near stars, compared to regions of lesser gravity, such as on planets. This time-slowing effect becomes pronounced in regions of extremely high gravity, such as near black holes.

Contributed By:
Clifford A. Pickover

#35 Re: This is Cool » Mathematic complexity » 2005-05-08 22:26:43

t886344a.jpg
Dragging Space and Time

The results of two studies announced in early November 1997 provide unprecedented support for “frame-dragging,” a concept predicted by physicist Albert Einstein's general theory of relativity. Frame-dragging describes how massive objects actually distort space and time around themselves as they rotate. One of the studies examined frame-dragging around black holes, an example of which is shown here in an artist's conception.

Encarta Encyclopedia
Joe Bergeron

#36 Re: This is Cool » Prove this » 2005-05-08 06:03:13

If the triangle is equilateral then his angles are
180:3=60, and formula for surface you mentioned is for right-angled triangle.
If a=b=c=2 than P=(2xh)/2 . You can calculate h. cos30=h/a ; h=sqr3. So P=sqr3 - as you see this is not a whole number. This also could be the first proof.
But you should try to do it using Heron's formula which administrator mentioned.

#37 Re: This is Cool » Can this be possible? » 2005-05-07 20:04:57

Yes that is corret. The same mistake as it was before. My calculation in second pard wasn't good. (x+1)(x-1)=x-1  , x=1 so THIS IS ALSO CORRECT, but I realised that this morning - my appologies.

#38 Re: This is Cool » Can this be possible? » 2005-05-07 10:51:14

About the problem 1=0

Let's take this for exapmle:
a=a
a+a-a=a  , now devide it with a+a
1-a/(a+a)=a/(a+a)
1=1 correct
but if you devide it with a-a then you have
(a-a)/(a-a)+a/(a-a)=a/(a-a)        (a-a)/(a-a) > 0/0 THIS IS NOT  EQUAL TO 1 so we do not have the problem 1=0. If we presume that 0/0=0 than equation would be correct, and it is the only way for it to be correct. SO:
0+a/(a-a)=a/(a-a).Is it true that 0/0=0 - my calculator doesn't think so. ????
The same problem occurred when you(administrator) devided (a-b) and (a-b) where a=b. You calculated that it equals 1 but it is incorrect.
But what I can not solve is the first problem where everithing is ok until this:
x^2-1=x-1 - this is also ok because we said that x=1
(x+1)(x-1)=x-1 - this is also ok - my appologies
THE SAME PROBLEM AS BEFORE 0/0 is not 1
I hope this was helpful

#39 Re: Help Me ! » Algebra help bad » 2005-05-07 06:07:48

y(y+11)=0, There have to be 2 possible solutions for this because it is square equation y^2+y11=0, so your explanation is incomplete.
y1,2=(-b+-sqrb^2-4ac)/2a. As c=0 > y1,2=(-11+-11)/2

1st y1=(-11-11)/2=-11         2nd y2=(-11+11)/2=0
This is longer and more complicated but it proofs that there are two solutions. When we meet such a problem I would suggest this:

y(y+a)=0 where a is known number   this equation can be correct when one of the agents =0

y=0     V      y+a=0
                   y=-a

#40 Puzzles and Games » What should be the question? » 2005-05-07 05:22:12

Milos
Replies: 34

There is a prisoner in one room with two guards. One guard stands in a front of the door which will lead prisoner to freedom if he choses that door. That guard tells truth and nothing but the truth. The other one stands in a front of the door which will lead prisoner to 5 years in prison. That one tells only lies. Prisoner can ask one question to one of the guards so the guard could answer Yes or NO. With this question he should find out through which door he should pass(logically that should be the door of freedom).

*Note: He doesn't know the connection between guards and doors(that the guard who tells truth is in a front of the door of freedom and that the other one is in a front of 5 y. in preason), but he does know that one of them tells truth and one doesn't.

#41 Re: This is Cool » Prove this » 2005-05-07 03:34:18

Yes, the idea is good, you are on the right way. Now we need proofs.:)

#42 This is Cool » Prove this » 2005-05-06 23:30:48

Milos
Replies: 8

Prove that if the sides of a triangle are prime numbers its surface can not be whole number.

Try to work this out - it is interesting and not too difficult.
I will give you the possible solution in few days.

#43 Re: Maths Is Fun - Suggestions and Comments » i have the solution fo "who owns the fish" » 2005-05-06 09:35:05

It is a very good puzzle but all you need is good organization and time- I wouldn't agree that only 98% can do it. I would agree with the statement that beer should be changed, although as far as I am concerned it doesn't matter(if you are really concentrated on the puzzle you don't pay much attention to its morality). But, there are some who care about this and it should be changed then because it is , as I said, a very good puzzle and there shouldn't be bad critics about it.:) I suppose that everyone has correct solution: It is German who lives in green house, drinks coffee and plays soccer. If there is anyone who would like to have it explained, I would be willing to do so.

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