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It's Calculus, so the answer is:
How do we get there?
Can you please take me through this question step by step please:
As usual I've been given the answer, but need to show steps to get there
(my teacher does know I get help on here, as I write about it in my reflection sheet)
I can post the answer if you like?
My teacher told us a nice way for students to remember to add the +C when integrating with calculus. He said call him Colin and don't forget Colin.
Has any of you teachers or students got any other ideas for how to remember?
thanks
Hi
I have a student who likes to have worksheets on paper, rather than staring at the computer screen. I find the Maths is Fun website to be the best resource for explaining things like fractions (love the pizzas).
Would you mind, oh amazing creator, if I included the images and descriptions in a worksheet if I acknowledge where I got it from?
Yours humbly
A soon to be trainee teacher
Yeah. See, I knew it was simple. Been staring at the problem too long.
Thanks
Why are they plus? I'm sure it's a very simple reason, and I've probably been staring at the problem for too long to see it.
I don't know what you mean. All the signs are negative, so how have I not changed a sign. Can you write it out for me because I can't see why it's wrong.
THis is what I did.
Why is it not working?
I'm still not getting the right answer. It's supposed to be 4., apparently, and I'm getting -1. (I don't even know how it's possible to get a minus for area).
Headache
(and thanks for the help)
Okay. I've gone wrong again. The next question is to find the area of the shaded area.
So I worked out the quad to have an area of 10.5 (the average of the two sides times the base).
Then I did Funny symbol with top number 4 and bottom number 1 y=6x-x^2-3
=[6x^2 + x^3 -3x] 4,1
----- ----
2 3
=(6X4^2 + 4^3 - 3X4) - (6X1^2 + 1^3 -3X1)
--- --- ----- ----
2 3 2 3
= 32 + 21 1/3 - 12 - 3 + 1/3 - 3
=35 2/3
Minus the Quad = 35 2/3 - 10 1/2
=26 1/6
But the answer says it should be 4.5. So where did I go wrong?
Many thanks
ahh. thanks
The diagram shows the line with equation y=x+1 and the curve with equation y=6x-x^2-3.
The line and the curve intersect at the points A and B, and O is the origin.
a) Calculate the coordinates of A and the coordinates of B.
I've done this:
x+1 = 6x-x^2-3
x=6x-x^2-4
0=5x-x^2-4
x^2-5x+4=0
(x-1)(x-4)
Coordinates are (1,4)
The answer says (1,2) and (4,5) so how do I get the 2 and 5?
Many thanks.
In a historgram, do both axis have to be to the same scale (for example, if I have one large square on graph paper representing one minute along the bottom, does the y asia have to be one square for each increase on frequency)?
I know this isn;t the case for other types of graphs, but because the y axis isn;t numbered in the histogram, I was wondering how someone would interpret the data if the areas where not done to this scale.
Does this even make any sense?
Thanks Bob. That was very interesting (and I actually understood what you were saying).
(I'd like to get a second opinion on this, as I have just started statistics, and I had never seen a Venn diagram before last month. I'll ask my stats teacher tomorrow when I'm in if you like, or maybe a more advanced member can tell me if I've got this right).
P(A or B) means the chances that A or B occur. So add the A circle and the B circle.. Remember that the 0.15 can occur both in A and B, so make sure you count it, but be careful not to count it twice. (I work it out to be 0.99)
P(A' and B') means the complement of A (the total of A not occurring) and the Compliment of B (the total of B not occurring). I'm hoping someone h=will correct me if I'm wrong, but I'd read that as A not occurring and B not occurring. When you add up all the decimals, you get 0.99. That means that the chances of none of these events happening is 0.01) as the total must be 1).
P(A/B) means given A, The chances of B then happening. So if A has happened (this is the denominator) what is the chances of B happening (the numerator).
I really need to check my workings, because I am unsure whether the intersection has been counted twice in my workings, I believe it has. But the notation is right: The A' means compliment (anything that is not A) and A/B means given A happening, chances of B happening.
I'm going to ask why Bob. Because I always want to know why.
Anon, I was wondering that as well, actually. I might ask my teacher than tomorrow.
Thanks guys. That's really helpful.
I'll be coming on tomorrow with your questions
Why is the integration not right? Is it because it's missing the denominators for the 2x3^2 and 2x-1^2
(sorry if I'm not making a lot of sense. I've been doing calculus all day)
Could you go through step by step. I'm now completely lost.
The answer on my answer sheet, by the way, is 10 and 2/3
Okay, so next part of the question. (I can't do the notation on here so I'm just going to write it without the correct notation).
Intergrating 5+2x-x^2.
=5x+2x^2 - x^3
------ ------
2 3
Then supplement the two coordinates in for x
= (5x3 + 2x3^2 - x^3 ) - (5x-1 + 2x-1^2 - -1^3)
------- ------ -------- -----
2 3 2 3
and that's where I get a bit unstuck. The first part is easy enough:
=15 +9 -3) - (this is the bit i am sure I have wrong)
Thanks. I didn't do the multiply everything by -1.
So the factoring would be:
(x-3)(x+1) and the points at A and B would be 3 and -1. Is that right?
I don't want to sound dumb, but could you just put the solving up? I think I have it, but I just need to double check I've done it right. (My biggest problem is confidence)
Hi all. I am onto Calculus now. Thing is, I have only done 2 lessons and never studied it before. I'm getting on alright, but I have a really hard question (well, hard to me). It's an extra question, so if I don't do it it isn't a big deal, but I am trying to figure it out.
This (if it works) is a roughly drawn picture. It says:
The figure shows the curve with equation y=5+2x-x^2 and the line with equation y=2. The curve and the line intersect at the points A and B.
a) Find the x-coordinates of A and B.
The shaded region R is bounded by the curve and the line.
b) Find the area of R.
Can someone please take me through step by step how you find the x-Coordinates of A and B? I do have the answers by the way, just don;t know how to get to it. Our teacher gives us the final answers so we can check we have it right, and he marks us on our working.
The thing that's confusing me the most is that the equation isn't in the normal format, and so the x^2 value is negative, which I always thought meant an imaginary number, so I think I've missed something.
As I say, my teacher did say he doesn't mind if I don't do this question, as I have never done calculus before, but I am now intrigued as to how it's done.
Thanks all.