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#426 Re: Help Me ! » Norman Window » 2024-05-18 06:22:52

Bob

Yes.

Maths isn't everything though.

I also do gardening, ornithology, volunteer with heath conservation, volunteer with show events at my local school, DIY, watch dvds and listen to music, visit relatives, go on holiday .......

Bob

Our blue tit babies flew the nest today.  At least 4 successful youngsters.

https://pixabay.com/photos/feeding-fled … t-5183136/

#427 Re: Help Me ! » Long Division » 2024-05-18 06:10:56

Bob

That quotient is correct.  The last subtract should be:

- x^2 + x + 1
-x^2    -x  - 1

Bob

#429 Re: Help Me ! » Long Division » 2024-05-18 06:06:38

Bob

'Difference of cubes' ?  I only know difference of two squares.

There's a theorem known as the remainder theorem ... that leads to the factor theorem.

If F(x) = Q(x).(x-a)+ R

If we put x = a we get F(a) = R

This can be useful in getting a remainder quickly.

example. An earlier question was "Find the remainder if (4x^3 - 3x^2 + x + 1) ÷ (x + 2)

a in this case is -2 so put that value into the dividend:

4 times (-2)^3 - 3 times (-2)^2 + (-2) + 1 = -32 -12 -2+ 1 = -46 + 1 = -45

If that is no remainder then R = 0 so F(x) = Q(x) . (x-a)  Putting x=a leads to F(a) = 0.



Example.  x^3 - a^3.  Put x = a and we get a^3 - a^3 = 0.  So (x-a) is a factor.

Bob

#430 Re: Help Me ! » Long Division » 2024-05-18 05:56:42

Bob

I find the most likely source of error is sign mistakes.  You need to be careful with minus a minus.

Bob

#432 Re: Help Me ! » Long Division » 2024-05-18 05:54:31

Bob

I get that remainder. What did you get for the quotient?

Bob

#433 Re: Help Me ! » Square ABCD Inside Circle 0 » 2024-05-18 05:05:27

Bob

Yes correct.  On the way to this answer you have done Q39 correctly.

Bob

#434 Re: Help Me ! » Square ABCD Inside Circle O » 2024-05-18 05:04:15

Bob

Again it is a great help to have the page ref.

You have got the diameter correct as root(8)  + root(4) x root(2) = 2root(2)

So the radius is root(2) that's all you need as the shaded area is a circle so youcan forget the square now. You only needed it for that diagonal.

Bob

#435 Re: Help Me ! » Area of Shaded Region » 2024-05-18 04:58:27

Bob

Thanks for the page reference. That helps a lot.  For this one the square is bigger than the circle so your calculation is the wrong was round. 4 is bigger than pi.

Bob

#436 Re: Help Me ! » Long Division » 2024-05-17 21:08:18

Bob

(2x^4 - 3x^2 + x + 1) by (2x^2 + x + 1).

                                                                    x^2        -  0.5 x      -      1.75
                         ___________________________________________
2x^2 + x + 1    |   2x^4       + 0 x^3        -  3x^2        +       x      +     1

                            2x^4       +    x^3       +    x^2
                           __________________________

                                           -     x^3       -     4 x^2      +      x
                                           -     x^3       -  0.5 x^2       - 0.5 x   
                                          ______________________________
           
                                                              - 3.5  x^2      + 1.5  x     +     1
                                                              - 3.5  x^2      - 1.75 x      -     1.75
                                                             _____________________________

                                                                                   3.25 x        +    2.75   

Hhmmm not what the book says.

Try  (2x^4 - 3x^3 + x + 1) by (2x^2 + x + 1)

Bob

#437 Re: Help Me ! » Long Division » 2024-05-17 20:16:26

Bob

I'll trying to set this out here. The alignment may get a little messed up.

(4x^3 - 3x^2 + x + 1) ÷ (x + 2)

                           4x^2     -11x     +23
_____________________________________
x+2  |  4x^3      - 3x^2      + x      +  1

           4x^3      +8x^2
          _______________

                        -11x^2      +x

                        -11x^2    -22x
                      ________________

                                      +23x      +  1

                                      +23x       +46
                                     ______________

                              remainder =     - 45               

Bob

#438 Re: Help Me ! » Find Number of Revolutions » 2024-05-17 20:05:14

Bob

The circumference of a circle is 30.  Work out the area.

There are two steps here: (1) calculate the radius (2) calculate the area

If I round this off to 5 then

If I keep the full accuracy for r

That's quite a difference.  The error is made worse because r is being squared which magnifies the error.

Bob

#439 Re: Help Me ! » Polynomial Horizontal & Vertical Addition & Subtraction Methods » 2024-05-17 19:49:09

Bob

I have got the pdf of the book.

When I log in and look at the Active or New posts I see a long list of yours; some new and some old ones.  I find it hard to keep track of which ones need a reply and which ones are just your sign off comment.  This is why I suggested numbering them.

Please understand, I'm not complaining about you asking for help. It makes me feel good to be able to provide it.

Bob

#440 Re: Help Me ! » Similar Triangles » 2024-05-17 19:47:45

Bob

I discovered I was good at geometry when, in the year 9 exams, I got 100%. Having been subjected to physical and verbal abuse by a 'teacher' who kept telling me I was useless, I realised I could be good at something and started to work seriously.

Post on!

Bob

#441 Re: Help Me ! » Area of Shaded Region » 2024-05-17 19:42:48

Bob

Oh I get it. And yes the set up is right.

Bob

#442 Re: Help Me ! » Square ABCD » 2024-05-17 19:41:51

Bob

Yes that looks right.

B

#443 Re: Exercises » Applying the Pythygorean Theorem » 2024-05-17 19:37:42

Bob

This is the LOH lighthouse problem again.  The diagram still works but now L is the height of the observation deck.

Bob

#445 Re: Help Me ! » Exponents / Algebra / Equations » 2024-05-17 07:26:44

Bob

smile

I thought I was missing something

As x can anything you can equate the non x bits and separately the x bits

Bob

#446 Re: Help Me ! » Polynomial Horizontal & Vertical Addition & Subtraction Methods » 2024-05-17 05:53:05

Bob

I've never heard of this , so I'm guessing. If you just add across like terms (eg add or subtract the x^3 terms) I suppose that is horizontal. If you write one polynomial under the other, carefullly lining up like terms (eg put the cube terms one under the other) perhaps that's the vertical method.

Bob

ps.  I've got to log off now as I've got chores to do .

#447 Re: Help Me ! » How Far Is the Ship From Shore? » 2024-05-17 05:48:57

Bob

The diagram I posted for a previous lighthouse question will also work here. 

L is the height of the man's eyes.  B is for his feet. O is the centre of the Earth.  H is the ship. Angle LHO is 90.

LO^2 = HO^2 + LH^2  so Pythag rather than sines and cosines.  As trigonmetry means the measurement of triangles Pythag
is also trig.

Bob

#448 Re: Help Me ! » Right Triangle Prove » 2024-05-17 05:42:39

Bob

You have to prove that the left hand side = the right hand side.

So writing that they are equal is a bit ahead of yourself.

Rather start with LHS =  (m^2 - n^2)^2 + (2mn)^2 , expand and simplfy.

Finally factorise, hopefuly ending up with the RHS.

Bob

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