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To Ricky"
You can do better than that! or can you?
Quote:
"But by his words in his last post, he in fact thinks 0.3 is the same as 0.333... Thus, contradiction, and therefore ARB does not exist."
A.R.B
Show me!
A x C = 1.11111...
B x C = 0.99999....
It Only takes One Calculation for A x C to = 1.1111.....Because A is! and A eqauls 1
It takes B x C to = 0.9999999..... Which is One Calculation Because B is < 1 to start with!
If B was Now to Some how now Reach! or Equal 1 by Multiplication! this would only then = 1
This would be would still make B 0.1 < A because B never started as 1 or = 1 the same as A
"This is Better! is? it! "
A starts as = 1
B starts as = 0.9
A x C results in a number > 1
B x C results in a number < 1
The point is A is 1
and B never = 1
If we are going to Infinitely multiply a number so that it becomes 1 "if possible"
Then a number that is already 1 must always be Greater!!
To Dross?
A x C = 1.11111...
B x C = 0.99999....
I Think a really good T-Shirt be........
" ITS IMPOSSIBLE TO HAVE A 100% (FLT) PROOF! "
" UNLESS THE LARGEST POSSIBLE N > = 3 + N > = 3 HAS BEEN TRIED! "
To MathsIsFun
Quote:
"Could you write down that number clearly. The one between 0.999... and 1. On its own. "
A.R.B
.9
To " Everyone! pleae help with this PROOF! "
A starts as = 1
B starts as = 0.9
A x C results in a number > 1
B x C results in a number < 1
The point is A is 1
and B never = 1
If we are going to Infinitely multiply a number so that is becomes 1 "if possible"
Then a number that is already 1 must always be Greater!!
To luca-deltode
Quote :
"so, if 0.999.... < 1, show me some numbers that are inbetween, if there exists no numbers, then 0.999... = 1"
A.R.B
That's an easy One! and tried many times! as an argument!
0.999999......(The Number in Between is Another 0.9).99999999999999... <> 1
To luca-deltodesco
A = 0.3
B = 0.3
C = 0.3
A + B + C = 0.9
----------------------------------------------------------------------------------------------------------------
I was waiting for the Answer! Ricky etc.. A = 0.3 B = 0.3 and C = 0.4
"That's a Shame! because then I was going to Hit yer with the Answer Below!!"
ALL THREE DECIMAL VARIABLES A,B & C MUST HAVE THE SAME DECIMAL VALUES!
A = (Decimal Value)
B = (Decimal Value)
B = (Decimal Value)
Using the Three Decimal Values A,B & C above must equal 1
A + B + C = ?
To luca-deltodesco
I think you are missing the point of what I am saying!
A starts as = 1
B starts as = 0.9
A x C results in a number > 1
B x C results in a number < 1
The point is A is 1
and B never = 1
If we are going to Infinitely multiply a number so that is becomes 1 "if possible"
Then a number that is already 1 must always be Greater!!
To Ricky etc...
Ok so Now we Both agree on something!
A = 0.3
B = 0.3
C = 0.3
A + B + C = 0.9 "Needs 0.1 to Equal 1"
---------------------------------------------------------------------------------------------------------------
Here is a Fraction Calculation
A = One 3rd
B = One 3rd
C = One 3rd
A + B + C = 1 "This I am sure you agree! is true! and needs no other numbers to = 1"
Ok according to your Quote below!
"Sorry to burst your bubble ARB, but decimal calculations are defined in a very strict sense so that they behave exactly (no if's, and's or but's) as your "normal calculation"."
Can you give me Three Decimal Values! so that the Variables A , B & C Below also need no other numbers to = 1
A = (Decimal Value)
B = (Decimal Value)
B = (Decimal Value)
Using the Three Decimal Values A,B & C above you have put forward! must equal 1
A + B + C = ?
To MathsIsFun
The Variables below A & B are Both Single Start Values.
A = 1 "This has to be the Start Value for 1"
B = 0.9 "This has to be the Start Value for Infinite 0.9"
C = A / B = 1.1111111111......
A x C = 1.1111111111 ......"This is the same Calculation to Make a Number Infinite! as with B"
B x C = 0.9999999999 ......"This is now Infinite 0.9"
The two Values for A and B are different! because Infinite 0.9 <> 1
If the Result for A did Equal B then Infinite 0.9 does = 1
Even If! by some Magic B does become 1 it wil still be Infinite 0.11111..... Less than A
To Ricky!
A = 0.3
B = 0.3
C = 0.3
A + B + C = 0.9
Can you show me the Value that needs to be add in this Calculation! to make A + B + C = 1
A = 1/3 "If this is a Normal Calculation! then this Equals One 3rd"
B = 1/3 "If this is a Decimal Calculation! then this Equals 0.3 i.e NOT QUITE One 3rd!!"
To Ricky!
A = 1/3 "If this is a Normal Calculation! then this Equals One 3rd"
B = 1/3 "If this is a Decimal Calculation! then this Equals 0.3 i.e NOT QUITE One 3rd!!"
INFINITE 0.9 <> 1 PROOF By,Anthony.R.Brown,15/01/07.
The Variables below A & B are Both Single Start Values.
A = 1
B = 0.9
Below Proves A is Infinitely > B And Gives The Variable C This Value.
C = A / B = 1.1111111111......
Below is How Infinite 0.9 is Calculated.
0.9 x C = 0.9999999999 ......
Below Proves Infinite 0.9 is <>1 By Using The Original Variables A & B.
A x C = 1.1111111111 ......
B x C = 0.9999999999 ......
JUST FOR THE FOOLS!..........................................................................................................
A = (1/3 x 3) = 1 "This is all part of the same Calculation! and so does = 1"
B = 1/3 = 0.333333....."This has now been Converted to Decimal! and lost its Accuracy!"
"i.e the Nearest Decimal to one 3rd can only be 0.3.. which is inaccurate! but important"
B x 3 = 0.9999...."This has now been Multiplied as Decimal! and has still lost its original Accuracy!"
"i.e the Nearest Decimal to one 1 can only be 0.9.. because of the Calculations that have been done! which is inaccurate! but important"
B has become Infinite 0.999...... "Because it is Inaccurate! but Nether less! and Most Important! permanently < 1
A - B must Equal 0.1 Because their Values have come from Different Calculation Accuracy's!
To Ricky
A = (1/3 x 3) = 1 "This is all part of the same Calculation! and so does = 1"
B = 1/3 = 0.333333....."This has now been Converted to Decimal! and lost its Accuracy!"
"i.e the Nearest Decimal to one 3rd can only be 0.3.. which is inaccurate! but important"
B x 3 = 0.9999...."This has now been Multiplied as Decimal! and has still lost its original Accuracy!"
"i.e the Nearest Decimal to one 1 can only be 0.9.. because of the Calculations that have been done! which is inaccurate! but important"
B has become Infinite 0.999...... "Because it is Inaccurate! but Nether less! and Most Important! permanently < 1
A - B must Equal 0.1 Because their Values have come from Different Calculation Accuracy's!
B "is a Decimal Calculation"
B = 1/3
B Must Eqaul 0.33333333........
B x 3 Must Eqaul 0.99999.......
B Must be Infinite!
B Must be < 1
OK Let's answer the Questions below!
A = (1/3 x 3) =
B = 1/3 x 3 =
A is not a Decimal Calculation! so A = 1
B = "wait for it!!
B = 1/3 x 3 = B
And also Wasp = 1/3 x 3 = Wasp
If I was able to ask "luca-deltodesco" this Question Verbally! I'm sure with the Small Brain he/it has! as proved by his "SWEARING SESSION" he would have got it Wrong!
The joke is always better when told Verbally!
If i say A = (1/3) and A is not a decimal Calculation! then A must = one 3rd
If i say A = 1/3 and A is a decimal Calculation! then A must = 0.333333333......
Back another Day!
to see if this can Trap! anymore "FOOLS"
A.R.B
Any more challenges on this! the "MAIN FOOL!" got it completely "WRONG!"
A = (1/3 x 3) =
B = 1/3 x 3 =
Give both Values for A & B
To luca-deltodesco
WRONG!!
To luca-deltodesco ? " and the fools that follow him? it ?
A = (1/3 x 3) =
B = 1/3 x 3 =
Give both Values for A & B