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Hi,
can you put Iraq, baghdad
for the time zone sitting?
cause I can't know the real time from this website topics and comments time
please
I need scientific reasons to proof my solution that is right and not wrong,
because the the Associate Dean for Academic Affairs((he is an professor in mathematics)) and the Dean of the university
say to me that your answer was wrong????????????
please help me they all against me, they say the end of the result is right but when I said ( Limit R.H.S = limit L.H.S) that wrong and you must write it (LIMIT L.H.S = f(0) ) .
please Help me! Put yourself in my place, what would you do with them?
please ! I'm weak and they are Dr and Professor and lecturer all against me or against one that maybe wrote a simple mistake
I don't have any Idea please help me the course will end in the end of the week so I will not be able to change my marks......
please!!!
How is that be?
but I saw a lot of textbook that, they toke the Limit or the R.H.S cause x ≠0 she these example please :
http://archives.math.utk.edu/visual.calculus/1/continuous.5/
https://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/continuitydirectory/Continuity.html
if the Limit does not exist can we say just k^2+3k-3 = 0 (just make it equal to zero then find the solution it if can be)
or we can't?...................(1)
so now I understand.... the limit does not exist because x approaches to 0
.I'm afraid maybe he will change his answer again and tell me like what did you told me and he will say you must write in your paper (there is no way to find k ...............(2) ) (
thank you very much
do you mean when I have x in the second H.S I can't tell (limit L.H.S = limit R.H.S)
I have to say ( f(0) = R.H.S)I did not say that. There are so many things wrong with his question it is difficult to explain away each one.
First, let me say in light of what I was told, my answer, your answer and his answer are all incorrect.
no no sorry I didn't mean by that.. I just asked a question ( do you mean ...)
sorry it is my bad language and I didn't understand you so well because my bad translation sorry again...
it was just a question,...
so what is the correct answer..
and what is the wrong in his question
if the question was wrong how do I'll get the 10 marks hehe!!
what to do please help me in everything you can
and what is the k value???
In this position, do I have to take the limit R.H.S or the f(0)?
As I understand them those two things are not interchangeable.
do you mean when I have x in the second H.S I can't tell (limit L.H.S = limit R.H.S)
I have to say ( f(0) = R.H.S)
cause when we will have x inside this so : (xk^2+k-3)
and when we will take the limit L.H.S = Limit R.HS s0 ..
limit x+1 = limit xk^2+k-3 ((x apro to 0)
1= 0 + k- 3
k=1+3 = 4
is that right? or it will be wrong...
just tell me this please..
I told him it is the same, He told you did a crime in mathematics science when you wrote it like that!!!
He want excuses just that..
anyway lets close this section I'll will deal with that problem and I will refer my rights in my way
_____________
I have another question please ...
lets suppose there is x in the question (xk^2+3k-3)
In this position, do I have to take the limit R.H.S or the f(0)?
no no no ,
He is said my solution is wrong cause I toke L.H.S = R.H.S to find k value
he said you must write it like this lim L.H.S {which x+1} = f(0) {which it K^2+3k-3)
not Lim L.H.S {which x+1} = Limit R.H.S which it K^2+3k-3}
you do understand what he is saying ...
yes it is .. sorry I don't care for the R.H.S and L.H.S I changed between them every time cause I forget always what is the L.H.S and R.H.S
anyway he said f(0) =L.H.S (it is the K^2+3K-3)
and so it is 1=it is the K^2+3K-3.............,
he said to me it is not Limit R.H.S ( x+1) = Limit L.H.S (K^2+3K-3)
and you said he is wrong too
so how he is wrong in that part?
and it is the same result so why he is doing that
nice to me all here
Please tell me answers that I can tell these answers to him so I can defend my right and myself please explain to me why wrong...
please I need these 10 marks , I need the prove of his wrong
and thank you cause you told me he is wrong now I'm more quietly and relaxing
I talked and discussed to him today but he changed his answer to this! :- see this is my sol in red color and his solution in blue color
He said you must take f(0) = R.H.S then find k not L.H.S=R.H.S,
what is that crazy man talking about???????? even he is right but it is the same result????
and he didn't teach us to do that I swear in god!!!
Hi I need to learn java language "Arrays"
from zero, cause I don't know how to use arrays I'mm fully not understaing this topic in java
Draw a graph of this polynomial and label it to find out when that polynomial goes above the x-axis.
I'm not sure what you are trying to do with the line "(x-3) > 0". If you consider the cases x ≥ 3 and x < 3 separately, you won't need to do this.
Hi, can you please teach me ho to draw a qraph for this? and how to find a full solution in an
actual way?
please we have a two more exams and we always get like these questions ...
I don't know bobbym he even don't know what are he doing, like me and the remain of students....
thickhead I don't know what do you mean be (Lim x->0 k^2-3k-3 is incorrect..)
do you mean my solution is wrong?
bobbym , the teacher said to me when I asked him : we chose the R.H.S = R.H.s and it will be k value = {-1,4}
when only we see have (≥) and (<)
not = and ≠ , cause in (≠ and = )
we chose the equation that have (=) and solve it
he said that to me
thank you ...
cause he told us when you see x ≠ 0 , you ignore the equation while you find k value
can you give me justification SO I can talk to him cause this question is from 10 mark too
at least I can take this 10 marks cause he give me 0
please help me with that
I don't understand
and he didn't say that,
but he say we can't take the L.HS cause the f(x) = x+1 , x ≠ 0,
because x ≠ 0, we just use the R.H.S
is he wrong?
yes it is k^2 -k + 4 k - 4 = 0
(k-1) (K=4) = 0
k=1
k=-4
set is {-4,1}
it is the same sorry I write to you -1 and 4 ,,, but in exam I write it correct like that ....
so it right?
it is the same k^2 + 3k -3