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i am having one idea i.e first obtain locus of above coordinate system
x^2/3 +y^2/3=16 now obtain dy/dx for this curve that comes out to be -tan(t)
now obtain equation of tangent to this curve
but what i understand that you want to apply concept of gradient in above problem but that always gives equation of normal
d is correct answer of this question
we know that irrational root occur in conjugate pair
we assume g(x)=(x-y)f(x)
(x-y)(x^2+ax+b)
x^3+ax^2+bx-yx^2-axy-by=x^3+px+q
x^3+(a-y)x^2+(b-ay)x-by=x^3+px+q
a=y
b-ay=p
-by=q
from here no relation will match
please mention that a,b are positive or not
assume a,b>0
is tending to zero at theta=pi/2-(tan^-1b/a)
it is a function because a line parallel to y axis cuts at only at one point hence it will having unique image.it represent relation also because all functions are relation also
obtain partial differential of above function w.r.t x&y equals it to be zero from here obtain value of x,y then obtain f" if it is less than zero then maxima will exist at that coordinate.
if any faimly of line f(x)+tF(x)=0 is given then minimum distance friom origin is (constant term)/[coef. of(x^2)+coef. of(y^2)]
since ans of above ques. =t^2 +2t +4
Fnet=(6i+2j)
anet={Fnet/2}=(3i+j)........Ans
Vx=V(initial)+ax*t
4+3*3=13
Vy=0+3*1=3
Vnet=Vxi+Vyj
(13i+3j).........Ans
X=X0+v(initial)*t+1/2*ax*t^2
=2+4*3+1/2*3*9
=27.5
Y=Y0+0+1/2*1*9
=-1+4.5
=3.5
="hence requried position vector=(27.5i+3.5j)".........Ans
when material inside bomb burn then burning material creats fume inside it then by this process a situation occur when pressure inside is greater than atmosphetric pressure so it explode in many small part now small parts are aso exploded this process occur on the microscopic label
i think that all plots are correct but in second plot at x=0 the slope will must be{ -infinite}
1.....when you obtain integration in close path then it may or may not be o
......it will be 0 if field will be coservative
.......coservative means du/dy=+or-dv/dx but it will be applicable if u is function of x only and v is function of y only
.......if it will function of x &y both then integration over close path will be o if curl of that field vector will be o
hello friend E=mc^2 fails if any material particle travell more faster than {c} "& such particle will having immaginary mass &hence not possible to exist"
MATHEMATICALY
m=m0/squrt(1-v^2/c^2)
IF......v>c then 1-v^2/c^2<0
hence m is immaginary
you are wrong you see my answer i answerd in this forum
a black hole will create or form if
1.......a star will die
2......star will be 4to20 times more massive than sun
FRIST CONDITION WILL BE NECESSARY
so how it can be explode
obiously a blackhole is hot"because any body is black means it absoarbs the tempreature by "steafn's law"....."
there will be no doubt it is dence also FIELD=GM/R^2
if R.....> 0 then Field is tending to infinite "this R is known as critical radius"
because R is much small after destroying the planet so it is dence also as comparison of its larger mass
example sun is also a black hole
hello friend E=mc^2 fails if any material particle travell more faster than {c} "& such particle will having immaginary mass &hence not possible to exist"
MATHEMATICALY
m=m0/squrt(1-v^2/c^2)
IF......v>c then 1-v^2/c^2<0
hence m is immaginary
p(x)=x^2-squrt2 *x+1=0 is minimal polynomial
frist let k is biggest side of triangle
then for formation of triangle {sum of two smallest side will always greater than biggest side}
(13+9)>k
k<22.................(1)
let in above triangle ABC the k is side infront of angle A
then for obtuse angle cosA<0
hence cosA=(9^2 +13^2-K^2)/2*9*13
2nd lowest statement emplies...........9^2 +13^2<k^2
on solving above inequality the accepted valu of k is greater than 15.81
hence integer values are 16 17 18 19 20 21 (total 6 integer value)
"NOW CHANGING CONDITION"
i.e 13 is biggest side
13^2>k^2+9^2
-9.38< k<9.38
but k+9>13
k>4
hence total integer valu 5 6 7 8 9
hence total no of integer value will be 11
A bulit is fired with velocity (v=2t). It strikes the tree having resistence 5 newton. Find velocity vs distance travell plot &total distance travell by bullet before stop as well as acceleration vs time plotl
max$min(3x+2y+5z)
Let ->
A=Xi+Yj+Zk
B=3i+2j+5k
A.B=mod(A)mod(B) cos (t) "max if cos(t)=1,min if cos(t)=-1"
3x+2y+5z=squrt(x^2+y^2+z^2)*squrt(38) cos(t)
put valu of x^2+y^2+z^2=45 $get ans
sorry friend in 1/(3-5cosx) you are wrong
CORRECT ANS
the denominator 3-5cosx=0 ->cosx=3/5 which is in the region [-1 1]
hence correct range is(-∞ -1/2]U [1/8 ∞)
hence you can see wht is max$min
what is maximum $minimum valu of 1/(3-5cosx)
if x,y,z are sides of a triangle R is radius of circumcircle A is area of triangle
then prove that
log(A)+log(4)+log(R)>=3(log(x)*log(y)*log(z))^1/3
hello friend.........
find max,min (3x+2y+5z)
if[x^2+y^2+z^2]=45
what is natural log of squt(-1)
if know then reply please
squt(24) is answer of max(3x-y-3z)
both are true I check your lagrange multiplier method
squt(5) is ans of max(x+2y)