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#1 Re: Help Me ! » Boolean algebra help » 2006-10-21 02:34:06
Yeah..I think I made a mistake there because I'm figuring out a way to explain it, and can't think of what I did. Sorry, hehe.
#2 Re: Help Me ! » Boolean algebra help » 2006-10-17 15:29:59
I figured out another way to get a smaller answer for #2..
= ~C~D + ~AC~D + A~B~C + C (~A~BD + A~D)
= ~D [(~C+~AC) + AC] + C (~B + A~D)
= ~D [~C + (~A + AC)] + ~BC + AC~D
= ~D[ (C+~C) + A] + ~BC + AC~D
= ~D (1+A) + ~BC + AC~D
= ~D (1+AC) + ~BC
y = ~D + ~BC
don't know if it's right or not
#3 Re: Help Me ! » Boolean algebra help » 2006-10-17 15:16:03
Wow. You are truly a kind man. Thanks a lot, you made it all very clear for me.
#4 Re: Help Me ! » Boolean algebra help » 2006-10-17 14:48:38
For the 2nd, are you sure the answer is supposed to be:
~D + A~B~C + ~A~BC
I got ~D + A~B~C + ~A~BCD
ie, with a D at the end...
It's a pain to type though... I just applied De Morgen to ~(C+D), and then factored out ~D on every term possible, then what was left over simplified to 1, which left ~D.
that's exactly what I got! But apparently it's not correct..the book has the answer I told you. Maybe it's a mistake in the printing? (lol I always tell myself that).
#5 Re: Help Me ! » Boolean algebra help » 2006-10-17 14:27:35
thanks..!!!!!
I'll keep trying on that last one..it's tough.
#6 Re: Help Me ! » Boolean algebra help » 2006-10-17 13:25:27
Wow, thanks a lot!!
Now, I'm having a bit of trouble with these three problems. I have the answers, but I can't seem to get there.
q = RST (all negated at the same time) ( R+S+T) (all negated at the same time)
the answer is supposed to be ~R~S~T ..but I just can't get there. Spent hours on this one.
The other one is:
y = ~(C+D) + ~AC~D + A~B~C + ~A~BCD + AC~D
and the answer is: ~D + A~B~C + ~A~BC .. this one I got kinda close to.. but not quite.
and the last one (and hardest) is
x = ~(M+N+Q) + ~(M+~N+Q) + ~(~M+N+Q)
and ALL of that negated
answer, apparently, is simply MN + Q.. I'm frustrated 
#7 Help Me ! » Boolean algebra help » 2006-10-17 12:02:27
- johnd29
- Replies: 12
I know A + 1 = 1
but does A (negated) + 1 = 1 too?
or in any case.. would AB + 1 = 1 too?
and would AC(negated) * A(negated)C = 0?
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