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#1 Re: Help Me ! » Functions PLEASE HELP » 2006-09-14 23:37:29
Ok, english is not my native language, so I have to translate some terms literally.
To answer your question-calculate the measuring number of the surface between the curves. This would be more accurate. Does this make more sense, there are no typos, that's why I told you if you find something impossible or strange you should just pick a nearly indentical problem from that particular area.
#2 Re: Help Me ! » Functions PLEASE HELP » 2006-09-14 05:37:55
OK, just take your time to type all of the procedure-every little step to each solution.
Thanks.
#3 Re: Help Me ! » Functions PLEASE HELP » 2006-09-14 04:09:22
If you find it that some tasks are impossible or smth. it doesn't matter. you can just pick other nearly indentical task because the point is to see step by step solutions of each type of tasks, not the specific task itself.
#4 Re: Help Me ! » Functions PLEASE HELP » 2006-09-14 03:29:18
Thank you so much!
If you find the time for other tasks I would really appreciate it, I have until monday.
I meant the first case, and as for the other question the task was given in that form so I'm not sure what do you mean.
#5 Help Me ! » Functions PLEASE HELP » 2006-09-14 01:55:29
- matikastat
- Replies: 9
If someone would be so kind to solve these problems and explain the hows and the whys:
(x<2> means x²)
1. g(x)=1-3ln(1-2x)
a)inverse function?
b)draw it
2. f(x)=- x / x<2>-3y +2
a)domain of the function?
b)extremes of the function?
3. with gauss-jordan procedure solve this equation system
x-2y+3z=4
2x+z-z=5
3x-z+2z=5
5x+z=6
4.
5. calculate the surface between the curves: 2e<x>+y=0 y<2>-4=0 y=0
6. the matrix is A= 0 -2 3
0 0 4
0 0 0
calculate (I-2A)<1>
7. f(x)=2+e<1-x> and g(x) = (2-x)/3. Define these functions(domain, picture and rule):
a)f ºg
b)(g º f) <-1>
8.Test the extremes of the function f(x)=(2x<2>+x+2)/x<2>+1
9.Using integrals calculate the surface between the curves:
y-x<2>+1=0
x-y=0
You can send me step by step solutions to these tasks to matikastat@yahoo.com
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