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Likewise, you've also made me realize that I can easily calculate the coordinates of the midpoint of the base, the distance from a bottom corner to the midpoint, and therefore the lengths of all three sides...I wonder can I now calculate the coordinates of the vertex without invoking vectors..?
-franky54
Ricky, thank you, that makes perfect sense to me ... I'm certainly no expert on vectors, but you have given me a direction to go in (no pun intended) and I will look into it further. Hopefully I'll be able to express the vector in terms of a function that can be calculated in a spreadsheet. Cheers,
-franky54
Hi, I'm hoping someone can help me come up with a formula to determine the rectangular coordinates of the vertex (Xc, Yc) of an isosceles triangle when the coordinates of the two bottom points are known (Xa, Ya and Xb, Yb) and the length of the two equal sides are known (d). I started to work backwards from the distance formula but quickly filled the page with unweildy equations. Assuming that the triangle base is roughly horizontal, I am only interested in the solution that puts the vertex 'above' the base, ie an 'upright' isosceles triangle. TIA for any help. Cheers,
Franky54
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