Math Is Fun Forum

bob bundy
emm..thanks...:(

yup...because i have answer -0.1,why?

can not be helping, and do not understand :(

(a)  f(x) = c - 0.2x between 0 and 2.

f(0) = c
f(2) = c - 0.4

So the total area under this graph ( trapezium and rectangle) is

A = (c + c - 0.4)x2/2 + 0.3 x 1

This must be 1 (by definition) so you can solve for c.

I made it c = 0.55 <--my calculate--> (0+0-0.4)x2/2 + 0.3 x 1 =-0.1?how can the number of 0.55..?

the next question
how tu calculate from calculator  casio?you have website or address to learn about this?

haii bob,

touched because you're willing to help me...

bob... can you help the next question which I attach yesterday...
please...been my best and I do not sleeping from the yesterday .. not me do not finding but I have tried to do my own ;(

bobbym

it's okey..never mind, thanks alot..

:touched can u explain i dont understand
did you answer the question or not?

yes!! i have answer...and understand..

(c)(C)  Similarly here ?do you main similarly at Q(b)

P(M and local)          = 0.1638
P(not M and local)     = 0.0666
P(local) = 0.1638+ 0.0666 = 0.2304<--answer for probability that a randomly (inter fresh)

it's true or not?

PDF= did you main prbability distribution function?

I have taip wrong title, which actually is about probability density function of continuous random variable

c.m.f, p.d.f ?
file pdf?

a)
P(NotM) = 1 - 0.63 = 0.37 <--P(non-M)
P(inter) + P(local) + P(exp) = 1
P(exp) = 1 - 0.47 - 0.26 = 0.27<--P(Exp)<--answer for (m)
P(exp) = 1 - 0.33 - 0.18 = 0.49<--P(Exp)<--answer for (non-m)

b)

P(M and exp)          = 0.1701
P(not M and exp)     = 0.1813
P(exp) = 0.1701 + 0.1813 = 0.3514<--answer for probability that a randomly (inter exp)

it' true completion of path the work?

and  (C)  Similarly here ?do you main?

p/s :SORRY BOB I ASK TO MANY BECOUSE I NOT UNDERSTAND MY LECTURER EXPLAIN BECAUSE SHE GIVE MORE AND ANSWER AND I DO KNOW WHERE ANSWER FOR QUESTION A,B,C,OR ANY QUESTION...