Here's my way of tackling these (others may have different methods).

**Problem #1**

The inches & fraction components in the first length are less than their counterparts in the second length, which adds difficulty to subtracting imperial lengths, particularly those with fractions.

To make the subtraction easier, I start with the following three steps:

1. convert the fraction to the Least Common Denominator (LCD); then

2. adjust the value of the fraction component to make it greater than that of the second length; then

3. adjust the value of the inches component to make it greater than that of the second length.

That leaves a simple subtraction exercise.

Btw, the 'take' and 'add' terminology that I used is like 'borrow' and 'pay', now aka 'regrouping', and is how I've always understood that concept.

Also, I've used symbols ' and " instead of abbreviations 'ft' and 'in' respectively...a common notation practice for these imperial length units.

Formula: You could convert both lengths to eighths of an inch, deduct the second from the first, and convert the result to feet, inches and eighths:

That last conversion from eighths is a bit tricky...

**Problem #2**

Same approach as for Problem #1:

Formula: You could convert both angles to seconds, deduct the second from the first, and convert the result to degrees, minutes & seconds:

]]>

**Welcome to the forum!**

Please see the links:

]]>Problem #1

17ft. 7 1/2in.

- 14ft. 9 7/8in.

=??????????

Problem #2

59degrees 37’ 18”

- 40 degrees 43’ 22”

=????? I don’t understand how you subtract something with degrees and feet and inches

Again I have the answers from the answer key but no idea how the answers came to be…

Please help

]]>