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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

Have you ever seen anything like that done before?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**zetafunc.****Guest**

Can't say that I have... could be that he is correct, just using a bad, or insufficient explanation.

There used to be 3 stats questions in STEP. Barely anyone chose them and always focused on pure and sometimes mechanics, so they now have only 2 instead, and stats is still the least popular section of the paper.

Out of the 248 questions I have done, only 18 were stats...

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

What a shame. I have never worked on one like this. If you get the solution to it please post it.

I am going to eat, see you in a bit.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**zetafunc.****Guest**

Okay, see you later.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

Just made a sandwich. Did not take long.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

**Online**

**zetafunc.****Guest**

Probably my favourite food on the go, even butter sandwiches will do...

Haven't made much progress with the problem, still trying to understand it. All I know is that it is like saying a currant can lie anywhere in the area underneath y = 2x, between 0 and 1.

I am thinking of having two continuous uniform distributions L ~ [0, 1] for the x-axis, and M ~ [0, 2L] for the y-axis, but is there some way of combining the two?

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

Yes, there is a joint distribution, but does that solve the problem.

You know that symbol ~ ? In mathematica they call it a condition, what do you call it?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

I thought it just meant 'has the distribution' in this context...

I don't think it will solve the problem. Still trying to work out how the probability that a currant is in the portion is x.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

That's it, "the distribution" that is the correct phrase.

First thing, that answer he got might not be correct.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

Lots of posters seem to be agreeing with him though...

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

Yea, the good ones there are saying he is right.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

**Online**

**zetafunc.****Guest**

There was a poster called ben-smith who didn't understand the solution and the answers they gave in that thread didn't help either.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

I am looking through my library in the statistics books. Someone has to have done a problem like this somewhere.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

Okay, let me know if you find anything.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

Are you kidding? I will be jumping up and down with joy. I would post it right here.

What title or type of problem would you call this?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

The paper hasn't given it a title. Not sure what I'd call it...

Sometimes they post very difficult questions in STEP. They say that in the 2012 paper there was a problem no one in the maths department at Cambridge could solve, so they put it in the 2012 STEP paper to see what would happen. And then 2008 STEP III featured a question only 3 people in the country managed to get right (it was a stats question also).

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

That might be why I am not coming across something like it in these texts. I need to get some rest see you later and thanks bringing the problem in.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

Okay, see you later.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

Hi;

I am back and resuming the search.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

**Online**

**zetafunc.****Guest**

Okay, thanks. I asked Hanh and she has no clue either, she could not do the first part. If adriana comes online I will ask her what she thinks.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

Hi;

Okay, but I doubt they will have an answer.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

I doubt she will come online to help, either.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

You mean in here?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

No, on chat or by e-mail.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 87,256

Oh, she might. Based on that question she will be needing lots of help.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

**Online**