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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

No, doing those dishes. All the dishes and glasses and everything else was in the sink. I got sick of looking at that.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**zetafunc.****Guest**

Oh, that. Yes, it takes me an hour to do the dishes sometimes... only because I am thorough.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Takes me long because I let them pile up.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**zetafunc.****Guest**

I think that is human nature...

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

I hate housework...

Does it have a residue command?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**zetafunc.****Guest**

I haven't been able to find one. So I tried looking for a Laurent series command or something (then I could just look for the 1/(z - c) power), but I could not find that either...

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Okay, I was just wondering. Perhaps taylor can do it?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

I tried that too but I cannot get it to give me negative powers (well it gives me something else that isn't making sense to me)...

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

What one did you try?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

taylor(exp(x), x, -5, 5);

that ends up giving me a Taylor series with powers of e in the denominators and powers of (x+5) in the numerators...

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

That is correct according to Mathematica.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

What is correct?

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

That expansion is correct.

Try this one and you will see that taylor can get Laurents too.

taylor(1/(1-x^2),x,-1,5);

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

That is interesting, so sometimes it works, sometimes it doesn't.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

When did it not?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

Hmm, never mind, I was confused why it was not working for e^x -- it seems e^x does not have a Laurent series?

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

Hi;

Correct , it does not.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

I feel like I have a powerful tool (Maxima) in an idiot's hands (me).

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

I have been working with many CAS since 1998. I have only scratched the surface. Welcome to the New Math!

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

I thought you said you knew 16 programming languages or something...

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

At one time I knew 10 or 12. The last being C++ which was my favorite. Then we discovered Mupad lite. I could not believe my eyes. Everything we were trying to write our program to do they had already done and then some.

I threw away those languages and my TI-92 and became what is known as a package jockey.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

Hmm. So, is there any use in knowing lots of programming languages these days? Or can a package likely do all of that for you?

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

A package can do all of that and more. Combining mathematics and programming produces a powerful weapon.

The newest idea is the revolutionary program called geogebra. It combines geometry with the rest of mathematics and programming.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**zetafunc.****Guest**

I've heard of that one. Never downloaded it though, I hate geometry...

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 86,309

I did too, until geogebra made it fun. What you hate is how they teach it.

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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