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#1 2005-08-13 20:31:40

wcy
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interesting numbers

i found this in a book:

11826=139854276

30384=923187456

which are all the digits from 1 to 9

 

#2 2005-08-14 08:58:49

NIH
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Re: interesting numbers

I found this in a book...

1 + 6 + 7 + 17 + 18 + 23 = 2 + 3 + 11 + 13 + 21 + 22;
1^2 + 6^2 + 7^2 + 17^2 + 18^2 + 23^2 = 2^2 + 3^2 + 11^2 + 13^2 + 21^2 + 22^2;
1^3 + 6^3 + 7^3 + 17^3 + 18^3 + 23^3 = 2^3 + 3^3 + 11^3 + 13^3 + 21^3 + 22^3;
1^4 + 6^4 + 7^4 + 17^4 + 18^4 + 23^4 = 2^4 + 3^4 + 11^4 + 13^4 + 21^4 + 22^4;
1^5 + 6^5 + 7^5 + 17^5 + 18^5 + 23^5 = 2^5 + 3^5 + 11^5 + 13^5 + 21^5 + 22^5.


2 + 2 = 5, for large values of 2.
 

#3 2005-08-14 09:17:41

mathsyperson
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Re: interesting numbers

What an amazing coincidence! It must be coincidence because it stops working when you use any power higher than 5.


Why did the vector cross the road?
It wanted to be normal.
 

#4 2005-08-14 09:38:38

NIH
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Re: interesting numbers

mathsyperson wrote:

What an amazing coincidence! It must be coincidence because it stops working when you use any power higher than 5.

It's a consequence of the following even bigger coincidence!

a^n + (a + 4b + c)^n + (a + b + 2c)^n + (a + 9b + 4c)^n + (a + 6b + 5c)^n + (a + 10b + 6c)^n = (a + b)^n + (a + c)^n + (a + 6b + 2c)^n + (a + 4b + 4c)^n + (a + 10b + 5c)^n + (a + 9b + 6c)^n,

where a, b, c are any positive integers and n can be 1, 2, 3, 4, or 5.

See also http://nrich.maths.org/askedNRICH/edited/412.html and http://www.primepuzzles.net/puzzles/puzz_065.htm

Last edited by NIH (2005-08-14 09:39:19)


2 + 2 = 5, for large values of 2.
 

#5 2005-08-14 10:27:42

kylekatarn
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Re: interesting numbers

2 + 2 = 5, for large values of 2.

funny : )

 

#6 2005-09-06 10:32:55

Zhylliolom
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Re: interesting numbers

Here's an interesting one:

111111111 = 12345678987654321.

Basically, when any number composed entirely of n ones is squared, the result will be 12...n...21. Well, at least when n < 10, once we get to 10 the middle gets screwy.

Last edited by Zhylliolom (2005-09-06 10:33:34)

 

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