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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi;

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

The solution #1745 is perfect. Good work!

#1746. If the product of three consecutive terms in Geometric Progression is 216 and the sum of their products in pairs is 156, find them.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi;

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

The solution #1746 is correct. Fantastic!

#1747. Find the first three consecutive terms in Geometric Progression whose sum is 7 and the sum of their reciprocals is

.Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi;

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

The solution #1747 is correct. Excellent!

#1748. The sum of the first three terms of a Geometric Progression is 13 and the sum of their squares is 91. Determine the Geometric Progression.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

The solution #1748 is perfect. Stupendous!

#1749. Find the sum of the first 75 positive integers.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

The solution #1749 is correct. Neat work!

#1750. Find the sum of the first 125 natural numbers.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

The solution #1750 is correct. Neat job!

#1751. Find the sum of the first 30 terms of an Arithmetic Progression whose n[sup]th[/sup] term is 3 + 2n.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi ganesh;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

#1752. Find the sum of the arithmetic series 38 + 35 + 32 + ........ + 2.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi ganesh;

Yes, I used the zeroth term. My mistake.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

The solution #1752 is correct. Good work!

#1753. Find the sum of the arithmetic series

25 terms.Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi;

Do you want it to 25 terms or 25 terms more?

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

The problem requires 25 terms.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

The solution #1753 is correct. Remarkable!

#1754. Find the S[sub]n[/sub] for the series : a = 5, n = 30, l = 121.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi ganesh;

Thanks for the additional information.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**

**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,276

Hi bobbym,

#1755. Find the S[sub]n[/sub] for the following arithmetic series.

a (first term) = 50

n (number of terms) = 25

d (Common difference) = -4.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,210

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

**Online**