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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1732 is perfect. Excellent!

#1733. Find n so that the n[sup]th[/sup] terms of the following two Arithmetic Progressions are the same.

1, 7, 13, 19, ....... and 100, 95, 90, .........

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi ganesh;

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1733 is correct. Excellent!

#1734. How many two digit numbers are divisible by 13?

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi;

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1734 is correct. Good work!

#1735. The sum of three consecutive terms in an Arithmetic Progression is 6 and their product is - 120. Find the three numbers.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi ganesh;

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1735 is perfect. Good work!

#1736. Find the three consecutive terms in an Arithmetic Progression whose sum is 18 and the sum of their squares is 140.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1736 is correct. Neat work!

#1737. Find the common ratio of the Geometric Progressions:

a) 0.12, 0.24, 0.48, ......

b) 0.004, 0.02, 0.1, ........

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solutions #1737 (a) and #1737 (b) are perfect. Excellent!

#1738. Find the common ratio of the Geometric Progression

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1738 is correct. Excellent!

#1739. Find the common ratios of the Geometric Progressions

(a)

(b)

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1739 (both parts) are correct. Excellent!

#1740. Find the 10[sup]th[/sup] term and common ratio of the Geometric Progression

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1740 is correct. Good work!

#1741. If the 4[sup]th[/sup] and 7[sup]th[/sup] terms of a Geometric Progression are 54 and 1458 respectively. Find the Geometric Progression.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1741 is perfect. Splendid!

#1742. Which term of the Geometric Progression

is ?Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1742 is correct. Good work!

#1743. If the Geometric Progressions 162, 54, 18, .... and

have their n[sup]th[/sup] term equal, find the value of n.Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1743 is perfect. Excellent!

#1744. The fifth term of a Gometric Progression is 1875. If the first term is 3, find the common ratio.

Character is who you are when no one is looking.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 83,138

Hi;

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 13,264

Hi bobbym,

The solution #1744 is perfect. Good work!

#1745. The sum of three terms of a Geometric Progression is

and their product is 1. Find the common ratio and the terms.Character is who you are when no one is looking.

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