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**emieeeeeeeee****Guest**

help!!! if i hade 17 boxes and the value of these boxes is £437,656,61. what is the average amounnt in each one ???????????????????????????????????????

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 93,935

Hi emieeeeeeeee;

Welcome to the forum!

I am not sure where the decimal point is. It looks like you want 437656.61

**In mathematics, you don't understand things. You just get used to them.**

**I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,878

Good morning bobbym,

Now for the last point. If Bob Bundy keeps hogging all the grants how can any of my ideas come to fruition?

Well, you could publish them on-line. Have a look for a forum that'll accept your posts. I've heard that 'Maths Is Fun' is quite a good one!

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 93,935

Good morning and evening;

Yes, that is a good place.

**In mathematics, you don't understand things. You just get used to them.**

**I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.**

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**wally187****Guest**

Help bobbym,

I need your help or anyone that can help me!!!!!

How do you create a power formula and weight which ones I think are more important. If I supply my data can fit my results and prove that there is a correlation between them. Even if one does not exist!

I'm trying to come up with a system that will determine the individuals performance just in one game and its hard?@?@@?

I have looked at the castrol football web page and it is a lot to take in. is there an easier way???? or should admit defeat?

Is it possible that I could just do shots on of target, passes complete/incomplete and tackles in possession and try to prove the performance and link it towards the anxiety test that I have done on them?? loads to take in and I'm at a lose end

Sorry guys

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 93,935

Hi wally187;

What does your data look like? How large is it? Can and are you willing to post it?

There ought to be a correlation between fear and performance. Anxiety, I am not so sure of. Some fit for your data may be possible. Theoretically that is true. Practically it may not be, I can not tell without seeing it.

**In mathematics, you don't understand things. You just get used to them.**

**I agree with you regarding the satisfaction and importance of actually computing some numbers. I can't tell you how often I see time and money wasted because someone didn't bother to run the numbers.**

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**mollydacochrane****Guest**

Thankyou, i found this strait away,

what a great website

thankyou!

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 93,935

Hi mollydacochrane;

Welcome to the forum!

**In mathematics, you don't understand things. You just get used to them.**

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**jonny****Guest**

how do i find the average of time when decimals come into play for example, 11.50,9.40,4.40,19.50,7.21,14.22

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,878

hi jonny,

Still the same as all the previous posts.

Ah time. I hadn't thought this through properly.

You need to convert the minutes into decimal fractions of an hour.

eg. 11.50 = 11 hours and 50 mins = 11 + 50/60 = 11.833333

Or, if you want to avoid all those 'nasty' decimals, change all the hours to minutes and get the answer in minutes.

eg. 11.50 = 11 x 60 + 50 minutes = 660 + 50 = 710 minutes.

Add 'em up and divide by how many there are (6 in your example)

Some calculators have a conversion button to change hrs and minutes into decimals.

Bob

*Last edited by bob bundy (2011-04-26 02:22:39)*

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**jonny****Guest**

bob your a dimond cheers very much

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,878

You are welcome.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**tayla Jessica****Guest**

I don't know maths to well but i need to know how to work out an avrage on numbers... how do i do that??? HELP ME

**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,878

hi tayla Jessica

There are three types of average that sometimes get used in maths but I expect you want the mean average.

Have a look at

http://www.mathsisfun.com/definitions/average.html

The Maths Is Fun teaching pages are really excellent!

If you have a set of numbers, why not post them for a worked example.

Bob

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**drv12021****Member**- Registered: 2011-07-02
- Posts: 1

Hey I have a problem on this one !

Martins average score after 4 tests is 89. What score on the 5th test would bring Martins average up to exactly 90? plzz help me

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 93,935

Hi drv12021;

Welcome to the forum.

So he needs a 94 on his next test.

**In mathematics, you don't understand things. You just get used to them.**

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**hotty****Guest**

X_alicia_X wrote:

heyaaaa

ta for that guys^^^^^

it proper helps (Y)

xo:D:lol:::cool:

:cool::mad:::lol::o:|:)

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 93,935

Hi hotty;

You are right she did say that. I have always wondered why she said that and you have clarified it. Now just one more thing, what are you saying? How long will I have wait until somebody explains your post?

Anyways, welcome to the forum!

**In mathematics, you don't understand things. You just get used to them.**

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**alicetheobald95****Guest**

hello, i need some help working out the average of percentage coverage. I have got about five different species in my five different quadrat sample and want to work out the average of each sample. I have 50% grass and 50% weed in sample one. 35% grass, 10% clover, 25 % thistle and 30% weed in sample two. In sample three i have 60% grass, 10% dirt, 10% clover, 10% dandelionand 10% leaves. In sample four i have 75 % grass and 15% weed. Finally in sample 5 i have 25% clover, 25% dandelion, 45 % grass and 5% plantain.

I was thinking you add each species percentage ad divide by how many percentages they are there. Yet when i do this all my percentage averages dont add up to 100 % and therefore i didnt think that was right. please help.

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 93,935

Hi alicetheobald95;

Sample 4 is incomplete.

Welcome to the forum.

**In mathematics, you don't understand things. You just get used to them.**

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**brennan****Guest**

how do you find the average of this table?

pulse rate bpm number of students

68 6

72 7

76 9

80 10

82 3

88 2

92 1

118 1

120 1

ive completey forgot!:/

**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 93,935

Hi;

78.7

Welcome to the forum!

**In mathematics, you don't understand things. You just get used to them.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,878

hi brennan,

You need to add up (6 people each with pr 68) and (7 at 72) and (9 at 76) and .... (1 at 120). When you have the grand total you've got to divide it by the total number of people ( 6 + 7 + 9 + ....+1)

Bob

*Last edited by bob bundy (2011-10-15 10:25:18)*

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**mary_ann right****Guest**

John E. Franklin wrote:

I'll do the 29 + 30 + 20 divided by 3 one another way: answer = 26 and 1/3, but how another way?

Well, do this:

29 30 20

make 30 go down 5 and 20 go up 5, so

29 25 25

Then make 25 and 25 go up by 1 each and 29 go down by 2, so

27 26 26

Then make 26 and other 26 go up 1/3, and then make the 27 go down 1/3, but then 1/3 more down again.

So then,

26 1/3 26 1/3 26 1/3

That's the answer when they are all the same.

that is the most complicated way ive ever seen i got to stick to adding them all together then dividing by the number of them there is. thanks for the confusion tho lol

**365****Guest**

Charlotte wrote:

hey can someone please help me out a little.

gotta find the average of these numbers:

80, 78, 60

and then to find out the average of these numbers too:

29,30,20

if anyone can help would be much appreciated:D

[80 + 78 + 60 = 218]

[218 / 3 = 72.66]

[29+30+20 = 79]

[79/3 = 26.33]