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You are not logged in. #26 20130421 23:19:43
Re: Compressing a milelong steel barhi bobbym and BeamReacher, From these last two I used trial and improvement to find a = 0.03370775.... radians. This gives the radius as From the top two equations Using the value of R and the quadratic formula d = 44.498509..... (My earlier answer of 63 was because I had used 2641 rather than 2640.5 for the arc length.) Bob You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #27 20130421 23:28:51
Re: Compressing a milelong steel barHi; In mathematics, you don't understand things. You just get used to them. I have the result, but I do not yet know how to get it. All physicists, and a good many quite respectable mathematicians are contemptuous about proof. #28 20130422 03:29:18
Re: Compressing a milelong steel barAn arc of a circle is into what shape a rod gets bent if the bending moment (and cross section) are the SAME all along its length  which they can never be if the forces are only at the ends!. Last edited by Mrwhy (20130422 04:05:46) #29 20130422 03:51:14
Re: Compressing a milelong steel barIf the compression is one inch then the revised figures are You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei #31 20130424 01:10:49
Re: Compressing a milelong steel barThanks much! An answer I can understand. Also gratified to see that my approximation of 14.5' was not THAT far off (I did say it would be "a little higher" than the actual value). #32 20130424 03:50:10
Re: Compressing a milelong steel barAn interesting thing about this question: 