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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

hi bobbym

well i would suggest you take the first 5 terms of the mclaurin's polynomial expansion and put in -0.1 instead of x.

*Last edited by anonimnystefy (2012-01-22 10:45:02)*

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,233

HI anonimnystefy;

That would not get the correct answer.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
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hi bobbym

i don't know what's wrong with me.i keep using the incorrect numbers.i fixed it.anyway,you get the idea.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Hi;

Uhhhh, that one is not correct.

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

now?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,233

Did we not start with a -.1?

**In mathematics, you don't understand things. You just get used to them.Of course that result can be rigorously obtained, but who cares?Combinatorics is Algebra and Algebra is Combinatorics.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

edited for the fourth time

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Correct a mundo!

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

next?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,233

Hmmm, have we squeezed all the juice out of the last question? I think not. Are 5 terms really necessary? Could you have provided a sharper bound then the Big O bound that wolfram provided?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

hi bobbym

i don't know what you meant by that.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Hi anonimnystefy;

Can you do a little better than the answer provided by using Big O?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

i don't know

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Oh okay. Holler if you would like to see how.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
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how.explain to me.but let me do it by myself.tell me how should i do it.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Experimenting is okay. Did you try less terms for that truncated series?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
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hi bobbym

for 4 terms i found the abs. difference of about 4*10^(-6)

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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What was the highest power in your truncated series?

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
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hi bobbym

x^3.

oh yeah i forgot x^4.for that i get 8*10^(-8)

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Then what do you say about whether or not we can use a smaller series?

Of course that result can be rigorously obtained, but who cares?

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

well we can,but only on experimental basis.if you were supposed to find the least number of terms you have to take,without that kind of calculation,then i would suggest using Big Oh notation.

btw,what is the name of the problem associated with this image:

i know that the literal translation from Serbian is "The Great Problem"

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,233

Hi;

Beats me what that is?!

Yes, I would say we should stick to the Big O estimate here. So good work!

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,507

next?

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**John E. Franklin****Member**- Registered: 2005-08-29
- Posts: 3,562

lots of parallel lines with those four circles.

Looks complicated.

Did you need to solve it?

**igloo** **myrtilles** **fourmis**

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 85,233

Hi;

Do you still need more today?

Of course that result can be rigorously obtained, but who cares?

Combinatorics is Algebra and Algebra is Combinatorics.

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