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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

hi guys

i wonder if you can guess what this topic is about from the title.anyway i have recently started looking into this a little,so i'm wondering if you can give a few problems for me to do?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 84,453

What kind of analysis?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

well look at the title one more time.it's not spelled Ho,ho,ho as usual,but Oh,Oh,Oh.helpful?

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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So then you are trying to do Big Oh, or Landau notation as it is sometimes called?

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

Correct!!!

so,can you give me some relatively simpler problems i could do?

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Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Simplify

f(x)=6x^9+8x^8+11 using Big O notation.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

i'm not sure what's meant by that.do you mean just

f(x)=O(x^9) ?

*Last edited by anonimnystefy (2012-01-21 07:13:52)*

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**bobbym****Administrator**- From: Bumpkinland
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Yes, that is correct.

What is the meaning of the Big O notation here:

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

hi

well maybe that other terms are of "order" greater or equal to x^4.i saw this ex. on wiki.didn't read it carefully.

EDIT:i just looked at the wiki article.it means that the error of calculating the abs. difference e^x-1-x-x^2/2-x^3/6 is less in value than c*|x^4| for some const. c>0

*Last edited by anonimnystefy (2012-01-21 07:36:27)*

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**John E. Franklin****Member**- Registered: 2005-08-29
- Posts: 3,562

Big-O is like a sort-of estimation of the maximum or minimum or something near the answer.

Big-O square or Big-O log base 10, etc...

**igloo** **myrtilles** **fourmis**

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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well maybe that other terms are of "order" greater or equal to x^4.i saw this ex. on wiki.didn't read it carefully

Not quite.

I have the result, but I do not yet know how to get it.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

hi JEF

i read about that.but i think that the O(log x) does not really need a base specified.

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**John E. Franklin****Member**- Registered: 2005-08-29
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oh yeah, I think you're right, it is a general overview type of statement.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

hi JEF

i'm not sure exactly why that is.

hi bobbym

i edited my post.

*Last edited by anonimnystefy (2012-01-21 07:25:23)*

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**bobbym****Administrator**- From: Bumpkinland
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What about mine?

I have the result, but I do not yet know how to get it.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

look at #14.

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**bobbym****Administrator**- From: Bumpkinland
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Hmmm, that is not correct.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

how is it not correct.did you see the edit in #9

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**bobbym****Administrator**- From: Bumpkinland
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Yes, I did. That is what I am talking about.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

what is it then?

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**bobbym****Administrator**- From: Bumpkinland
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You are copying straight from Wiki and not adapting the ideas it contains to the new problem.

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

changed it once more.

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**bobbym****Administrator**- From: Bumpkinland
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Which is asymptotically greater?

9^n or n!

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,340

hi bobbym

i would say n!

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
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Correct!

Log(n!) or e^n

I have the result, but I do not yet know how to get it.

All physicists, and a good many quite respectable mathematicians are contemptuous about proof.

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