That's right, very good!

If some polynomial is divided by ( x- 9 ) the remainder is 10. When it is divided by ( x+ 6 ) the remainder is 4. When it is divided by ( 3 x - 4 ) it has a remainder of 12. What is the polynomial?

When you divide your answer by (x-9) what do you get for a remainder? Is it 10?

Hi;

That is not the correct way to divide the 2 polys. MIF has a good page on it. Take a look and I will help you if you get stuck. Work your way to this answer.

(x^2 + 27x + 22) / (x - 9 ) = x + 36 with a remainder of 346

Hi phrontister;

Here is the solution to the polynomial problem. You will see that it requires no more math than you already know. I will steer clear of fancy jargon and leave only the barebones.

Hi phrontister;

Glad to help.

Hi phrontister;

Try this:

http://www.mathsisfun.com/algebra/polyn … actor.html

Post where you are having a problem, I will try to help. If I can't there are others here who are stronger than I on this subject, they will help.

Hint: Don't let a little piece of wording stop you. Skip over it if necessary, but learn the method. This way you can solve a similiar problem. Later on you can come back and pound out the definitions. You don't have to totally understand something to use it.

Hi phrontister;

Okay, Wikipedia is either good or terrible. It is typically only for people that already understand the particular material. We will pick it up when you get back.

Hi ZHero;

First 2 steps are fine; Since the question wants the moves rather than the answer to the integral can you please expand line 2 to 3 and the next one a little bit more.

Last edited by ZHero (2010-05-01 23:59:18)

prob 46

A factory is determining how much to charge for a dinner. Each month it produces 78 dinners for sale. The factory figures that charging x pounds for the dinners, the sales will be 78-3x dinners. At the months end, unsold dinners will be bought back at regular price by the factory.What price x should the factory charge for the dinners so they can maximize profit?

B says)

I am assuming regular price is x.

Factory profit is:

P = x ( 78 - 3x ) - 3 x^2

Which gives a maximum at 6.5. Since they cannot sell 6.5 dinners the maximum occurs when x = 6 or x = 7 then their profit will be 252 pounds.

A says) B is wrong, the answer is x = 13.

What do you like?

Hey bobbym!

Hey.. bobbym!!

bobbym wrote:

At the months end, unsold dinners will be bought back at regular price by the factory.

so the factory must have first sold it for x. I mean, u cannot buy back without selling it first.. right?
and thus B is wrong in subtracting 3x²?

bobbym wrote:

Since the factory manufactured them this implies a loss of some amount  when they don't sell the product. B assumes a loss of x dollars as he states, his solution is based on that assumption. If their is no loss on each product then there is no maximum. Since the question does not indicate what the loss is, it is not possible to determine a maximum price.

         

The profit is "Maximized or Minimized" depending upon the "No. of Dinners sold" which is "Dependent upon the price x".

If you sell dinner at price 2, then the profit is P₂ = 2*(78-3*2)=144.

If you sell it at 10, then the profit is P₁₀ = 10*(78-3*10)=480. (P

If you sell it at price 5, then the profit is P₅ = 5*(78-3*5)=315.

If you sell it at price 15, then the profit is P₁₆ = 16*(78-3*16)=480.

hence.. P₂<P₁₀, P₅<P₁₀, P₁₀=P₁₆ and so on.

thus... Different prices offer different profits to the factory (even though there is no loss on the products)!


this is coz the profit decreases with an increase in the price!!!

B is wrong if he thinks that the unsold dinners are a loss...
Its a typical case where there's no question of loss but of profit only!

Q: You and I buy a slice of Cheese each at $10. I sell it for $100 and you sell it for $50 only.
Wud you say you made a profit of $(50-10)=$40 or a loss of $(100-50)=$50 (had you sold it for $100)??
see the difference.....?