Math Is Fun Forum / Problem

Roraborealis · 2005-05-27 03:53:39

24= 3x8
24=8/3

There must be some link...................

Milos · 2005-05-27 06:47:33

(8*3)-3^0+8^0=24
I know that 3^0 is not the same as 3, but it was said that we need to use 8,8,3,3 - and as you can see every of these numbers are used. I though of it logically, that's why i did it in this way. ????

puzzler09 · 2005-05-27 09:29:34

I've got the answer...at least I think so....

((8 x 3!)/3)+8

= ((8 x 3 x 2 x 1)/3)+8
= (48/3)+8
= (16)+8
= 24

yay!!

mathsyperson · 2005-05-27 09:36:11

Its about half past midnight, but I just thought of a genius answer (that doesn't have factorials) and I couldn't wait to share!

8/(3-(8/3))=
8/(1/3)=
24

I'm so happy!

MathsIsFun · 2005-05-30 15:47:07

So impressed with both solutions ... !

And I thought we were just being teased.

I might add this one to our "official" puzzle list

Zach · 2005-05-30 19:29:10

Gasp! The horror.

justlookingforthemoment · 2005-05-30 20:05:40

What's the official puzzle list?

Roraborealis · 2005-05-30 20:09:34

Like, this page.

justlookingforthemoment · 2005-05-30 20:29:28

Huh?

Roraborealis · 2005-05-30 20:30:58

That page.

MathsIsFun · 2005-05-30 21:08:23

"Click and ye shall find"

justlookingforthemoment · 2005-05-31 17:14:27

Ohh! I see. Is there are way for you to make all links colourful or underlined or something in your forum? You can never tell if it is linked or not... or is that just me?

MathsIsFun · 2005-05-31 18:06:02

Oh... I wonder why not. It is underlined in Internet Explorer and Firefox on my PC.

Do you have anything unusual about your setup? Operating System / Browser or something?

justlookingforthemoment · 2005-05-31 18:10:10

Okie dokie, fixed it... I'm using firefox.

I just ticked underline links!

JD · 2005-06-02 22:12:18

Well, the answer is not easy, but it exists:

8/3=2,6666666666666666666... (=2,66periodic) (=8/3)

3-2,66p=0,33p (in other way, 9/3-8/3=1/3)

8/0,33p=24 (in other way, 8/1/3=8*3=24)

Summarizing...

8/(3-(8/3))=24

Zach · 2005-06-03 03:25:26

You realise that answer was said all the way up there, right?

jebediah · 2006-06-04 09:44:13

8/(3-(8/3) =
8/(3-(2 2/3) =
8/(1/3) = 24

justlookingforthemoment · 2006-06-04 12:35:15

Zach wrote:
You realise that answer was said all the way up there, right?

And plus, you realise that this post is one year old? Almost exactly.

Oh well, well done for working it out. You missed a closing parenthesis in the second line though.

krassi_holmz · 2006-06-04 17:27:08

Interesting... Can't you make some program, which gives all possible solutions?

krassi_holmz · 2006-06-04 18:34:43

Making progress...

krassi_holmz · 2006-06-04 19:08:17

My program is ready. And guess what-there aren't another solutions except:
8/(3-(8/3))=24!!!

krassi_holmz · 2006-06-04 19:10:31

This program was personal challenge.
Here's list of all numbers, which can be expressed using 8,8,3,3:

Uploaded Images

Last edited by krassi_holmz (2006-06-04 19:17:46)

krassi_holmz · 2006-06-04 19:20:35

Here's the code (Mathematica, rewritten, but really messy and hard-to-understand):

Code:

K[n1_, n2_] := Union[{n1 + n2, n1 - n2, n1*n2, n1/n2}];
KK[list_, num_] := Union[Flatten[Table[K[list[[i]], num], {i, 
      1, Length[list]}]]];
KKK[list1_,
     list2_] := 
      Union[Flatten[Table[KK[list1, list2[[i]]], {i, 1, Length[list2]}]]];
d[a_, b_, c_, d_, f_] := {
    (*abcdfff*)
    f[{a}, f[{b}, f[{c}, {d}]]],
    (*abcfdff*)
    f[{a}, f[f[{b}, {c}], {d}]],
    (*abcffdf*)
    f[f[{a}, f[{b}, {c}]], {d}],
    (*abfcdff*)
    f[f[{a}, {b}], f[{c}, {d}]],
    (*abfcfdf*)
    f[f[f[{a}, {b}], {c}], {d}]
    }
d[l_, f_] := d[l[[1]], l[[2]], l[[3]], l[[4]], f];
dd[l_, f_] := dd[l[[1]], l[[2]], l[[3]], l[[4]], f];
dd[a_, b_, c_, d_, f_] :=
  (
    Print["abcdfff:", f[{a}, f[{b}, f[{c}, {d}]]]];
    Print["abcfdff:", f[{a}, f[f[{b}, {c}], {d}]]];
    Print["abcffdf:", f[f[{a}, f[{b}, {c}]], {d}]];
    Print["abfcdff:", f[f[{a}, {b}], f[{c}, {d}]]];
    Print["abfcfdf:", f[f[f[{a}, {b}], {c}], {d}]];
    )
p = Permutations[{3, 3, 8, 8}];
res = Table[Union[Flatten[d[p[[i]], KKK]]], {i, 1, Length[p]}];
Union[Flatten[res]]

Could explain and rewrite it later.

alexhak · 2010-12-02 05:21:16

8/(3-(8/3))

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#26 2005-05-27 03:53:39

Re: Problem

#27 2005-05-27 06:47:33

Re: Problem

#28 2005-05-27 09:29:34

Re: Problem

#29 2005-05-27 09:36:11

Re: Problem

#30 2005-05-30 15:47:07

Re: Problem

#31 2005-05-30 19:29:10

Re: Problem

#32 2005-05-30 20:05:40

Re: Problem

#33 2005-05-30 20:09:34

Re: Problem

#34 2005-05-30 20:29:28

Re: Problem

#35 2005-05-30 20:30:58

Re: Problem

#36 2005-05-30 21:08:23

Re: Problem

#37 2005-05-31 17:14:27

Re: Problem

#38 2005-05-31 18:06:02

Re: Problem

#39 2005-05-31 18:10:10

Re: Problem

#40 2005-06-02 22:12:18

Re: Problem

#41 2005-06-03 03:25:26

Re: Problem

#42 2006-06-04 09:44:13

Re: Problem

#43 2006-06-04 12:35:15

Re: Problem

Zach wrote:

#44 2006-06-04 17:27:08

Re: Problem

#45 2006-06-04 18:34:43

Re: Problem

#46 2006-06-04 19:08:17

Re: Problem

#47 2006-06-04 19:10:31

Re: Problem

#48 2006-06-04 19:20:35

Re: Problem

Code:

#49 2010-12-02 05:21:16

Re: Problem

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