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## #26 2005-05-26 05:53:39

Roraborealis
Member
Registered: 2005-03-17
Posts: 1,594

### Re: Problem

24= 3x8
24=8/3

School is practice for the future. Practice makes perfect. But - nobody's perfect, so why practice?

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## #27 2005-05-26 08:47:33

Milos
Member
Registered: 2005-05-06
Posts: 44

### Re: Problem

(8*3)-3^0+8^0=24
I know that 3^0 is not the same as 3, but it was said that we need to use 8,8,3,3 - and as you can see every of these numbers are used. I though of it logically, that's why i did it in this way. ????

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## #28 2005-05-26 11:29:34

puzzler09
Guest

### Re: Problem

I've got the answer...at least I think so....

((8 x 3!)/3)+8

= ((8 x 3 x 2 x 1)/3)+8
= (48/3)+8
= (16)+8
= 24

yay!!

## #29 2005-05-26 11:36:11

mathsyperson
Guest

### Re: Problem

Its about half past midnight, but I just thought of a genius answer (that doesn't have factorials) and I couldn't wait to share!

8/(3-(8/3))=
8/(1/3)=
24

I'm so happy!

## #30 2005-05-29 17:47:07

MathsIsFun
Registered: 2005-01-21
Posts: 7,684

### Re: Problem

So impressed with both solutions ... !

And I thought we were just being teased.

I might add this one to our "official" puzzle list

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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## #31 2005-05-29 21:29:10

Zach
Member
Registered: 2005-03-23
Posts: 2,075

### Re: Problem

Gasp! The horror.

Boy let me tell you what:
I bet you didn't know it, but I'm a fiddle player too.
And if you'd care to take a dare, I'll make a bet with you.

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## #32 2005-05-29 22:05:40

justlookingforthemoment
Moderator
Registered: 2005-05-26
Posts: 2,161

### Re: Problem

What's the official puzzle list?

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## #33 2005-05-29 22:09:34

Roraborealis
Member
Registered: 2005-03-17
Posts: 1,594

### Re: Problem

School is practice for the future. Practice makes perfect. But - nobody's perfect, so why practice?

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## #34 2005-05-29 22:29:28

justlookingforthemoment
Moderator
Registered: 2005-05-26
Posts: 2,161

Huh?

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## #35 2005-05-29 22:30:58

Roraborealis
Member
Registered: 2005-03-17
Posts: 1,594

### Re: Problem

That page.

School is practice for the future. Practice makes perfect. But - nobody's perfect, so why practice?

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## #36 2005-05-29 23:08:23

MathsIsFun
Registered: 2005-01-21
Posts: 7,684

### Re: Problem

"Click and ye shall find"

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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## #37 2005-05-30 19:14:27

justlookingforthemoment
Moderator
Registered: 2005-05-26
Posts: 2,161

### Re: Problem

Ohh! I see. Is there are way for you to make all links colourful or underlined or something in your forum? You can never tell if it is linked or not... or is that just me?

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## #38 2005-05-30 20:06:02

MathsIsFun
Registered: 2005-01-21
Posts: 7,684

### Re: Problem

Oh... I wonder why not. It is underlined in Internet Explorer and Firefox on my PC.

Do you have anything unusual about your setup? Operating System / Browser or something?

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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## #39 2005-05-30 20:10:10

justlookingforthemoment
Moderator
Registered: 2005-05-26
Posts: 2,161

### Re: Problem

Okie dokie, fixed it... I'm using firefox.

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## #40 2005-06-02 00:12:18

JD
Guest

### Re: Problem

Well, the answer is not easy, but it exists:

8/3=2,6666666666666666666... (=2,66periodic) (=8/3)

3-2,66p=0,33p (in other way, 9/3-8/3=1/3)

8/0,33p=24 (in other way, 8/1/3=8*3=24)

Summarizing...

8/(3-(8/3))=24

## #41 2005-06-02 05:25:26

Zach
Member
Registered: 2005-03-23
Posts: 2,075

### Re: Problem

You realise that answer was said all the way up there, right?

Boy let me tell you what:
I bet you didn't know it, but I'm a fiddle player too.
And if you'd care to take a dare, I'll make a bet with you.

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jebediah
Guest

8/(3-(8/3) =
8/(3-(2 2/3) =
8/(1/3) = 24

## #43 2006-06-03 14:35:15

justlookingforthemoment
Moderator
Registered: 2005-05-26
Posts: 2,161

### Re: Problem

Zach wrote:

You realise that answer was said all the way up there, right?

And plus, you realise that this post is one year old? Almost exactly.

Oh well, well done for working it out. You missed a closing parenthesis in the second line though.

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## #44 2006-06-03 19:27:08

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,905

### Re: Problem

Interesting... Can't you make some program, which gives all possible solutions?

IPBLE:  Increasing Performance By Lowering Expectations.

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## #45 2006-06-03 20:34:43

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,905

### Re: Problem

Making progress...

IPBLE:  Increasing Performance By Lowering Expectations.

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## #46 2006-06-03 21:08:17

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,905

### Re: Problem

My program is ready. And guess what-there aren't another solutions except:
8/(3-(8/3))=24!!!

IPBLE:  Increasing Performance By Lowering Expectations.

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## #47 2006-06-03 21:10:31

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,905

### Re: Problem

This program was personal challenge.
Here's list of all numbers, which can be expressed using 8,8,3,3:

Last edited by krassi_holmz (2006-06-03 21:17:46)

IPBLE:  Increasing Performance By Lowering Expectations.

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## #48 2006-06-03 21:20:35

krassi_holmz
Real Member
Registered: 2005-12-02
Posts: 1,905

### Re: Problem

Here's the code (Mathematica, rewritten, but really messy and hard-to-understand):

``````K[n1_, n2_] := Union[{n1 + n2, n1 - n2, n1*n2, n1/n2}];
KK[list_, num_] := Union[Flatten[Table[K[list[[i]], num], {i,
1, Length[list]}]]];
KKK[list1_,
list2_] :=
Union[Flatten[Table[KK[list1, list2[[i]]], {i, 1, Length[list2]}]]];
d[a_, b_, c_, d_, f_] := {
(*abcdfff*)
f[{a}, f[{b}, f[{c}, {d}]]],
(*abcfdff*)
f[{a}, f[f[{b}, {c}], {d}]],
(*abcffdf*)
f[f[{a}, f[{b}, {c}]], {d}],
(*abfcdff*)
f[f[{a}, {b}], f[{c}, {d}]],
(*abfcfdf*)
f[f[f[{a}, {b}], {c}], {d}]
}
d[l_, f_] := d[l[[1]], l[[2]], l[[3]], l[[4]], f];
dd[l_, f_] := dd[l[[1]], l[[2]], l[[3]], l[[4]], f];
dd[a_, b_, c_, d_, f_] :=
(
Print["abcdfff:", f[{a}, f[{b}, f[{c}, {d}]]]];
Print["abcfdff:", f[{a}, f[f[{b}, {c}], {d}]]];
Print["abcffdf:", f[f[{a}, f[{b}, {c}]], {d}]];
Print["abfcdff:", f[f[{a}, {b}], f[{c}, {d}]]];
Print["abfcfdf:", f[f[f[{a}, {b}], {c}], {d}]];
)
p = Permutations[{3, 3, 8, 8}];
res = Table[Union[Flatten[d[p[[i]], KKK]]], {i, 1, Length[p]}];
Union[Flatten[res]]``````

Could explain and rewrite it later.

IPBLE:  Increasing Performance By Lowering Expectations.

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alexhak
Guest

8/(3-(8/3))