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#126 2005-09-01 18:43:02

ganesh
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Re: Problems and Solutions

You are correct, wcy.
Good, you didn't tell how you did it smile
Try earlier problems too.


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#127 2005-09-01 19:00:03

ganesh
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Re: Problems and Solutions

Problem # k + 9

A square, whose side is 2 meters, has its corners cut away so as
to form an octagon with all sides equal. Then, what is the length of each side of the octagon, in meters?


Character is who you are when no one is looking.
 

#128 2005-09-01 19:21:29

MathsIsFun
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Re: Problems and Solutions

Ganesh, I am thinking of an upgrade to the "hide" tag.

Wouldn't it be cool if we could really hide the results from everyone (except moderators) until a certain time, maybe 1 week after the post, or based on the time you post the question.

A third possibility would be for you to have a keyword in the topic like "open" and that could be what controls whether the hide tag really hides, so "Ganesh's Puzzles" would be a list of solved/unsolved puzzles, with other peoples answers hidden until you let them be shown.

I would obviously need to program all this, and I am not sure the hurdles I would face, but what do you think of the idea?


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman
 

#129 2005-09-01 20:10:01

ganesh
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Re: Problems and Solutions

The idea seems great!
Inspite of the hide tag, its too tempting for many to view the answer.
Since most of our members solve the problems and post their solutions in a day or two, I post a problem or two everyday. Once the problem is solved, I forget to tell how it is done.
Your idea would be of great help smile


Character is who you are when no one is looking.
 

#130 2005-09-01 22:29:43

MathsIsFun
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Re: Problems and Solutions

So, do you think it would be good to post a new topic for every puzzle? That way they could have titles like "Cut a Square (Current)", which you can edit to "Cut a Square" when it is solved. I could use the phrase "(Current)" to tell the forum to really hide answers in the hide tag.

Also, if someone posts a full answer you can edit their post, insert a "hide" tag and put a gentle reminder to use the hide tag smile

(This is all based on the assumption I can get the hide tag to work like we want!)


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman
 

#131 2005-09-02 14:59:11

ganesh
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Re: Problems and Solutions

Yes, that seems a good suggestion.

Two tricky problems to start the day:-

Problem # k + 10
Complete the series:-
1248, 1632, 6412, 8256, _____


Problem # k + 11
What is special about the number 2592?


Character is who you are when no one is looking.
 

#132 2005-09-02 21:36:15

ganesh
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Re: Problems and Solutions

Problem # k + 12

In a 4-digit number, the sum of the first two digits is equal to that
of the last two digits. The sum of the first and last digits is equal to the third digit. Finally, the sum of the second and fourth digits is twice the sum of the other two digits. What is the third digit of the number?


Character is who you are when no one is looking.
 

#133 2005-09-02 22:37:13

kylekatarn
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Re: Problems and Solutions

solution(#k+9)


tongue

Last edited by kylekatarn (2005-09-02 22:40:05)

 

#134 2005-09-03 13:50:24

ganesh
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Re: Problems and Solutions

Solution to problem # k + 9

The side of the square is 2.
Let a length 'c' be cut from the two ends of a side.
We have right angled triangles of sides 'c'.
The hypotenuse would be h = 2c
or h = (√2)c
Since it is a regular octagon.
2 - 2c =  (√2)c
c = 2/(2+√2)
h is the side of the octagon,
h = 2 (√2)/(2+√2)
or h = 2/(1+√2)


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#135 2005-09-03 14:22:16

ganesh
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Re: Problems and Solutions

Problem # k + 13

Two squares are chosen at random on a chessboard. What is the probability that they have a side in common?


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#136 2005-09-03 15:24:18

John E. Franklin
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Re: Problems and Solutions

I guess 1/18 chance if they can't both be the same chess square.


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#137 2005-09-03 15:42:49

ganesh
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Re: Problems and Solutions

You got it right! Well done! Try the earlier unsolved problmes. smile

The number of ways of choosing the first square is 64. The number of ways of choosing the second square is 63. There are a total of 64 * 63 = 4032 ways of choosing two squares.

If the first square happens to be any of the four corner ones, the second square can be chosen in 2 ways. If the first square happens to be any of the 24 squares on the side of the chess board, the second square can be chosen in 3 ways. If the first square happens to be any of the 36 remaining squares, the second square can be chosen in 4 ways. Hence the desired number of combinations = (4 * 2) + (24 * 3) + (36 * 4) = 224. Therefore, the required probability = 224/4032 = 1/18


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#138 2005-09-04 17:02:29

ganesh
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Re: Problems and Solutions

Problem # k + 14

What is the area of the largest triangle that can be fitted into a rectangle of length 'l' units and width 'w' units?


Character is who you are when no one is looking.
 

#139 2005-09-05 12:05:36

John E. Franklin
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Re: Problems and Solutions

Last edited by John E. Franklin (2005-09-05 12:05:54)


igloo myrtilles fourmis
 

#140 2005-09-05 12:40:58

John E. Franklin
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Re: Problems and Solutions

Last edited by John E. Franklin (2005-09-05 12:42:33)


igloo myrtilles fourmis
 

#141 2005-09-05 12:47:29

John E. Franklin
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Re: Problems and Solutions


igloo myrtilles fourmis
 

#142 2005-09-05 13:08:40

John E. Franklin
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Re: Problems and Solutions


igloo myrtilles fourmis
 

#143 2005-09-05 13:34:44

John E. Franklin
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Re: Problems and Solutions


igloo myrtilles fourmis
 

#144 2005-09-05 14:00:55

ganesh
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Re: Problems and Solutions

Good work, John E. Franklin  smile

Solution to Problem # k + 14

Any triangle you try to draw with the maximum area would have same base and height. The solution is, without doubt, lw/2. You can try all possibilities. You'd get the same answer, both when the base is 'l' and 'w'.

Solution to Problem # k + 12
Yes, you would be one equation short. But, when you get one number is eight times the other, the numbers would have to be 1 and 8, as each number a,b,c, and d is a single digit number!

Solution to Problem # k + 10
Yes, 5121 is the correct answer. As you said, there may not be another as 0242 is not acceptable!


Solution to Problem # k + 11
You have given a different property! I had this is my mind.
It is a number of the form abcd equal to (a^b)*(c^d)

Solution to Problem # k + 6
You are correct. The ages of the grandmother and the grandson would be (61,1), (62,2), (63,3), (64,4), (65,5), and (66,6).


Character is who you are when no one is looking.
 

#145 2005-09-05 14:14:07

ganesh
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Re: Problems and Solutions

Problem # k + 15

A sample of x litres from a container having a 60 litre mixture of milk and water containing milk and water in the ratio of 2 : 3 is replaced with pure milk so that the container will have milk and water in equal proportions. What is the value of x?


Character is who you are when no one is looking.
 

#146 2005-09-05 14:46:15

John E. Franklin
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Re: Problems and Solutions


igloo myrtilles fourmis
 

#147 2005-09-05 15:10:54

John E. Franklin
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Re: Problems and Solutions

Thanks ganesh.  Yeah, I see now on #k + 12 that you can solve that
"b" is twice "d", and  "d" is 4 times bigger than "a".
That's really something.


igloo myrtilles fourmis
 

#148 2005-09-05 16:26:46

ganesh
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Re: Problems and Solutions

Solution to Problem # k + 6

You are right, John. I don't know the reason. Just as MathsIsFun thought, I too believed 97531 x 86420 would be the highest product! smile

Problem # k + 16

The pages in a book are serially numbered from 1. If the number of digits required to total all the pages in the book is 972, how many pages are there in the book?


Character is who you are when no one is looking.
 

#149 2005-09-06 01:21:41

John E. Franklin
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Re: Problems and Solutions


igloo myrtilles fourmis
 

#150 2005-09-06 14:05:39

ganesh
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Re: Problems and Solutions

John, you went wrong somewhere; please try again smile


Character is who you are when no one is looking.
 

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