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#451 2006-02-23 18:26:34
- rimi
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Re: Problems and Solutions
For problem#K+101
It does not hold for n=2... as (2!+1)=3,which is a prime number.
Ganesh ,by infinitely many values of n , do you mean large values of n? Then what is the lower limit for n?
#452 2006-02-23 19:03:10
- ganesh
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Re: Problems and Solutions
rimi, your solution to Problem # k + 100 is correct 
In Problem # 101, infintely many values means an unending sequence. Like the list of prime numbers, powers of the number 2 etc. For both n=1, n=2, and n=3, the resultants are prime numbers. However, for n=4, n=5, n=6, n=7 etc., the value of n! + 1 is composite.
Character is who you are when no one is looking.
#453 2006-02-23 19:41:05
- ganesh
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Re: Problems and Solutions
Problem # k + 102
Three-fourth of a number is equal to 60% of another
number, and the difference between the two numbers is 20. What
is the sum of the two numbers?
Character is who you are when no one is looking.
#454 2006-02-24 08:11:14
#455 2006-02-24 08:55:24
- mathsyperson
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Re: Problems and Solutions
By taking the route of a - b = 20, instead of b - a = 20, you can also get an answer of -180.
Why did the vector cross the road?
It wanted to be normal.
#456 2006-02-24 09:11:01
- irspow
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Re: Problems and Solutions
Nice catch mathsyperson, can I still be half right? Maybe it should have read, "What are the sums of the numbers?". Hey, did I just get tricked!?
Last edited by irspow (2006-02-24 09:20:06)
#457 2006-02-24 09:25:38
- mathsyperson
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Re: Problems and Solutions
You can be almost fully right, really. You did all the working, and I just stuck a little comment on the end. And I think the reason why ganesh didn't phrase it like that was because he missed it himself. 
Why did the vector cross the road?
It wanted to be normal.
#458 2006-02-24 17:11:12
- ganesh
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Re: Problems and Solutions
mathsyperson is right! Although I explore the possibilites of other solutions, this time I didn't think of that
Well done, irspow and mathsyperson 
Character is who you are when no one is looking.
#459 2006-02-24 17:43:12
- ganesh
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Re: Problems and Solutions
Problem # k + 103
A circle is inscribed within an equilateral triangle and another is circumscribed. Calculate the ratio of the area of the incircle to the circumcircle.
Character is who you are when no one is looking.
#460 2006-02-24 20:50:00
- ganesh
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Re: Problems and Solutions
Problem # k + 104
What is the maximum slope of the curve y = -x³ - 3x² + 9x - 27 and what point is it?
Character is who you are when no one is looking.
#461 2006-02-25 04:12:42
- mathsyperson
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Re: Problems and Solutions
Why did the vector cross the road?
It wanted to be normal.
#462 2006-02-25 22:56:40
- ganesh
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Re: Problems and Solutions
Well done, mathsyperson
Problem # k + 105
A group of bess equal in number to the square root of half the whole swarm alighted on a jasmine bush, leaving behind 8/9 of the swarm. And only one bee circled a lotus for it was attracted by the buzzing of a sister bee that was so careless as to fall into the trap of the fragrant flower. How many bees were there in the swarm?
Character is who you are when no one is looking.
#463 2006-02-25 23:40:29
- ganesh
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Problem # k + 106
Four brother have 45 Dollars. If the money of the first is inreased by 2 Dollars and the money of the second is decreased by 2 Dollars, and the money of the third is doubled and the money of the fourth is halved, then all of them will have the same amount of money. How much does each have?
Character is who you are when no one is looking.
#464 2006-02-26 08:17:57
- mathsyperson
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Re: Problems and Solutions
Why did the vector cross the road?
It wanted to be normal.
#465 2006-02-26 16:31:21
- ganesh
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Re: Problems and Solutions
Character is who you are when no one is looking.
#466 2006-02-26 16:38:44
- ganesh
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Re: Problems and Solutions
Problem # k + 107
The price of a water-melon is 50 cents, an apple is 10 cents and a plum is 1 cent. Five dollars were used to buy 100 items of different kinds of fruit. How many pieces of each type were bought?
Character is who you are when no one is looking.
#467 2006-02-26 23:13:53
- ganesh
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Re: Problems and Solutions
Problem # k + 108
What is the sum of the first 50 terms common to the series 15,19,23 ... and 14,19,24 ... ?
Character is who you are when no one is looking.
#468 2006-02-27 05:48:06
- mathsyperson
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Possibly a bit unconventional...
But nothing unconventional here.
Why did the vector cross the road?
It wanted to be normal.
#469 2006-02-27 07:38:42
- MathsIsFun
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Re: Problems and Solutions
(19 pages, wowee! Maybe you could start a new topic?)
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
#470 2006-02-27 14:56:27
- Ricky
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I was actually wondering that for quite a while, MathIsFun. Wouldn't it be more organized if Ganesh did one question per topic? I mean, we got an entire section of the forum for it, why not?
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
#471 2006-02-27 15:49:34
- ganesh
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Re: Problems and Solutions
To mathsyperson :- Funnily, your solution to Problem # k + 107 is correct, although unconventional, as you put it. Please read the Problem # k + 108 again before posting your solution. 
To MathsIsFun :- Good suggestion, worth considering.
To Ricky :- One question per topic is fine. But what do we do with the problems already posted? Put them all in an 'Assorted' or 'Miscellaneous' topic? Good suggestion, worth considering.
Character is who you are when no one is looking.
#472 2006-02-27 21:18:34
- krassi_holmz
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Re: Problems and Solutions
Do you mean this is the end of "Problems and solutions"?
IPBLE: Increasing Performance By Lowering Expectations.
#473 2006-02-27 21:26:23
- ganesh
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Re: Problems and Solutions
I hope not. Some problems would be posted here in the future too. There are some unanswered problems for which solutions would have to be posted. Hence, this is not the end of 'Problems and solutions'. This topic shall remain the precursor of other topics.
Character is who you are when no one is looking.
#474 2006-03-01 15:28:18
- ganesh
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Re: Problems and Solutions
Problem # k + 109
Prove that every number of the form a4+4 is a composite number (a≠1).
(This problem was posed by the eminent French mathematician Sophie Germain).
Character is who you are when no one is looking.
#475 2006-03-02 02:34:28
- mathsyperson
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It's fairly simple apart from when a ends in 5.
When mod(10) a = 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9, mod(10)(a4 + 4) = 4, 5, 0, 5, 0, 9, 0, 5, 0 and 5 respectively.
Numbers that end in 4, 5 or 0 are never prime (apart from 5) so that proves it for all values of a except for ##5. But proving it for that is quite difficult.
Why did the vector cross the road?
It wanted to be normal.