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#201 Re: Help Me ! » systems » 2006-11-11 13:59:20

If it's (1/2)b:




No solution.

#203 Re: This is Cool » Finite Series and For Next Loops » 2006-10-29 13:31:48

Or you can define abstract operators, which act as programs:


Or you can use them as "constructors" for more complex objects:

#204 Re: Exercises » Requests » 2006-10-29 13:26:56

Take my thread.
(late)

#205 Re: Help Me ! » Simplification » 2006-10-29 13:24:18

But the expression is NOT defined when r=1

#206 Re: Help Me ! » Volume » 2006-10-29 13:17:11

There is.
This follows immediately from the fact that the volume of a pyramid is exactly 1/3 of the volume of the prism, which can be proved by suitable disection of the prism into 3 pyramids, which must have equal volumes by the Cavalery (the name may be spelled incorrectly) principe.

#208 Re: Help Me ! » Help me with these problems..... » 2006-10-29 13:06:04

All_Is_Number wrote:
Prakash Panneer wrote:

1)Find the number of  Rectangles  on the chess board.

The number of rectangles that can be found on any checkerboard with dimensions n squares * m squares can be represented:

.... which is exactly:

#210 Re: Help Me ! » Largest integer function ! » 2006-10-29 12:43:28

polylog wrote:

Ok here is another way, no Fourier:
It is evident that this formula always gives -1.

Eg for 2.1 , the floor is 2, the ceiling is 3, and we are always taking the floor - ceiling, which is always going to be -1.

Thus the function simply reduces to f(x) = -1 for all x.

This makes the proof of the limit trivial. smile

Not so fast!
if x is integer, then

#211 Re: Help Me ! » Help DATE TO CODE » 2006-09-21 19:57:36

I think the code is random.

#212 Re: Help Me ! » I have a really hard question » 2006-09-12 00:26:15

"Creative"?
What do you mean?
(give an example of some "creative" names)

#214 Re: Euler Avenue » About this forum » 2006-09-10 07:34:12

You already know the Pythagorean's.
Good.

#220 Re: Help Me ! » This is unsolvable... right? » 2006-09-10 07:03:56

But sorry. If you don't like my comments, I'll stop posting.

#221 Re: Help Me ! » This is unsolvable... right? » 2006-09-10 07:02:25

But there are also K and L that are known. You don't use those. I don't understand why not.

Because in my example it doesn't matter what K and L are.
They can be any.
(I'm tlking about a particular case, when M+N+Q+P≠ 2S. I'm not talking about the whole problem.)

#222 Introductions » plzzzzzzzzzzzzzzzzzzzzzzzzzzzzz » 2006-09-10 05:25:52

krassi_holmz
Replies: 14

I like these z-s!
Espeon, you're a part of the Z-team!
lol

#224 Re: Help Me ! » This is unsolvable... right? » 2006-09-10 05:09:18

OK I'll try another.
Using:
M=A+C
N=B+D
Q=A+D
P=B+C
S=A+B+C+D

We have:M+N+Q+P=A+C+B+D+A+D+B+C= (A+B+C+D)+(A+B+C+D)=2S.
So M+N+Q+P=2S should be right.
But if you pick some values for M,N,Q,P and S, for which 
M+N+Q+P=2S
is false, then the system will have no solutions for the chosen M,N,Q,P and S.
clear now?

#225 Re: Help Me ! » I have a really hard question » 2006-09-10 05:03:17

I don't think "mirror squares" is best, because we should name the numbers, not their squares.
But we can take 2 names - for example "passerby" for the numbers, and "mirror squares" for their squares.

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