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#151 Re: Computer Math » Very good approximation of pi by rational number » 2022-12-15 03:24:51

Hi Keckman,

Keckman wrote:

There is six number in divide operation and you get seven right numbers of pi. But is there even better ones? I guess there is not same kind rational number under one trillion.

Well, according to my research, there's a very big jump from your 355/113 to the next one (103993/33102): your Pascal program might be quite busy for a while. smile

I initially thought of trying brute force like you did, but changed my mind after I googled 'oeis pi fractions approximations 22/7 355/113 104348/33215' (as a single-line search using your fraction, imcute's and the 22/7 I know)...which introduced me to a minefield of info about this topic!

I started here: OEIS (sequence of convergents to Pi): A002485 (numerators) & A002486 (denominators).

Those two links (and a StackExchange post) quoted the following Mathematica formula for obtaining a sequence of increasingly accurate fraction approximations: Convergents[Pi, x].

That interested me as I have Mathematica. I chose 10 for x (for an output of a sequence of 10 fractions) and ran the code in my program and also online at WolframAlpha, with the following output in both:
3, 22/7, 333/106, 355/113, 103993/33102, 104348/33215, 208341/66317, 312689/99532, 833719/265381, 1146408/364913.

The 2nd fraction in the sequence shows the well-known 22/7, the 4th is yours from post #1, and the 6th is imcute's from post #2.

Links to a couple of other sites I looked at:
Wikipedia: Continued fraction expansion of π and its convergents.

Wolfram MathWorld: Pi Continued Fraction.

#152 Re: Help Me ! » Negative second degree equation » 2022-10-17 22:49:05

Hi;

I thought I'd try Excel's Goal Seek, and managed to solve this thread's cubic and a couple of others I tested it on:
UeUq0W6.png

The two extra cubics have 3 roots each, and to find them I entered into column D the initial x values that I'd predetermined and stored in Column C, those values being:
(a) a high initial value to try to find the highest x;
(b) a low initial value to try to find the lowest x;
(c) half the sum of the resulting highest & lowest x values from (a) & (b) to find the remaining x (not sure if that's a good idea generally, but it worked for these equations).

Then I ran Goal Seek (individually for the equations in rows 2, 3, 5-7 & 10-12) with the respective Goal Seek boxes filled from columns E & D as per the image example.

Btw, to increase Goal Seek's precision (quite a necessary step for good accuracy with this method), I first set 'Maximum Change' in Excel's File/Options/Formulas/'Enable iterative calculation' to 0.000000000000001, which gave accuracy to 14 decimal places for this thread's cubic: i.e., x ≈ -2.09144638072228 (the last few digits aren't displayed in the image).

The above cubics are the only ones I've tried this Goal Seek method on...

#153 Re: Help Me ! » Negative second degree equation » 2022-10-13 21:42:10

Hi imcute;

imcute wrote:

5x^3+10x^2=-2
then you factor out 5x^2
x^2(x+2)=2/5

The resulting equation after factoring out 5x² is missing something...

#154 Help Me ! » Image test 2 » 2022-10-02 19:11:39

phrontister
Replies: 2

Hi Bob;

I thought I'd keep this going, even though the other thread is closed.

We've done a fair bit of work on this and maybe it's worth trying my latest finding, so that, if we're successful (hope against hope!), we have the solution for anyone who needs it.

Sorry to bother you further after the disappointing direction this episode has taken and just leave it if you'd rather, but maybe still keep my thread open in case someone else takes an interest in it later.

Cheers,
phro 

This is what I wrote on the other thread:

Bob wrote:

I'm using Android.  Tried all sorts of image sharing but have yet to get the bcc version. Elsewhere on the help it says bcc is not an option for mobiles

This is from a Quora post:
"Unfortunately there is no option to upload photos to imgur using your phones web browser because they want you to download their app. But some mobile browsers (like Chrome) have an option for you to view the desktop version of a website. If you select this option, it will load imgur as it would on your desktop PC and you can upload images that way."

Here's a link to some info on enabling/disabling the desktop version view on a range of browsers: How to View Desktop Version of Any Site on Mobile.

Maybe the desktop view gives the ability to copy the url of the actual image (ie, one with an image extension) instead of an imgur web page?

#155 Re: Help Me ! » Image test » 2022-10-01 22:50:58

Hi Bob;

Bob wrote:

I'm using Android.  Tried all sorts of image sharing but have yet to get the bcc version. Elsewhere on the help it says bcc is not an option for mobiles

This is from a Quora post:
"Unfortunately there is no option to upload photos to imgur using your phones web browser because they want you to download their app. But some mobile browsers (like Chrome) have an option for you to view the desktop version of a website. If you select this option, it will load imgur as it would on your desktop PC and you can upload images that way."

Here's a link to some info on enabling/disabling the desktop version view on a range of browsers: How to View Desktop Version of Any Site on Mobile

Maybe the desktop view gives the ability to copy the url of the actual image (ie, one with an image extension) instead of an imgur web page?

#156 Re: Help Me ! » Image test » 2022-10-01 12:31:40

harpazo1965 wrote:

Please copy and paste the following link. Tell me if you can see the image.

https://imgur.com/gallery/PXM8kTT

Yes, I can...as part of the following Imgur web page (a screen capture):

n3c7hgA.png

However, while your link works for me now, I've found from your other posts that your web page links only work for a limited time, if at all.

#157 Re: Help Me ! » Image test » 2022-10-01 03:00:46

Bob wrote:

Worryingly, I don't remember a thing from that thread.

Oh dear!

#158 Re: Help Me ! » Image test » 2022-10-01 00:50:26

Hi Bob;

If the temptation for me to replace my PC & laptop with a 'smart'phone becomes too overpowering for me, please jump in and save me!!

Right now, I don't feel the least bit tempted.

#159 Re: Help Me ! » Image test » 2022-10-01 00:05:33

Hi Bob;

Have you tried this?
MJYMiDQ.png
It's from the Imgur on mobile web FAQ section on Imgur Help.

According to the How do I get a direct image link from imgur on mobile? thread on Reddit, that method will only work on iOS.

Just trying to save you some steps & extra work! smile

#160 Re: Help Me ! » Unbounded Intervals » 2022-09-30 10:41:54

phrontister wrote:
harpazo1965 wrote:

Do you understand my question here?

Sorry, but I don't.

My last year of maths was 4th year high school and I don't recall ever covering these kinds of problems. So I guess they were taught in higher levels...or maybe I just dozed off in class.

harpazo1965 wrote:

If you don't recall high school mathematics, why bother to reply? Seems like a big waste of your time and mine.

You asked me a question and I obliged with my response so that you weren't left wondering in the absence of one, and I simply stated my reason for being unable to assist...

#161 Re: Help Me ! » Unbounded Intervals » 2022-09-29 11:20:08

harpazo1965 wrote:

Do you understand my question here?

Sorry, but I don't.

My last year of maths was 4th year high school and I don't recall ever covering these kinds of problems. So I guess they were taught in higher levels...or maybe I just dozed off in class.

#163 Re: Help Me ! » Unbounded Intervals » 2022-09-28 11:19:54

Thanks, Bob...glad it works for you. up

But the OP said:

harpazo1965 wrote:

Thanks but I don't have a computer or a laptop to do all that fancy stuff you talked about.

What device did you try it with, Bob? I'm hoping it was a smartphone, because, although I don't have one of those and can't perform the test, I thought my method would've been non-fancy enough to even work on a smartphone.

They have the capacity to perform the kind of copy/paste I referred to, don't they? dizzy

#164 Re: Help Me ! » Unbounded Intervals » 2022-09-28 02:38:45

Hi Bob;

I use a PC, and so maybe my experience differs from how the OP's device works (or can work) with Imgur, but this is what I've observed and got:

The OP's address isn't to the image itself...it's only to the Imgur web page with the image on it (amongst other things).

An image address has an image format extension, such as PNG, JPEG...which isn't the case with the OP's 'https://imgur.com/a/MMz2Kir'.

Solution:
I copied the OP's url into my browser's address bar, right-clicked the image that appears on the resulting Imgur page, selected 'Copy image address' from the drop-down menu, and then pasted that address into MIF (in 'img' tags nested inside 'hide' tags)...which gives me:
CRkvwKf.jpeg

You'll see that the image address is very different from that of the OP's.

Maybe my method would work for the OP on his device...

#165 Re: Puzzles and Games » First- and last-letter alphabet game » 2022-09-21 23:35:01

J : Jij (Dutch, meaning 'you')
Z : Zzz (sleep)

#166 Re: Exercises » Non - Routine Algebra » 2022-08-30 03:43:16

Hi CurlyBracket;

Question 6: How many children do they have?

They have 3 children.

#167 Re: Exercises » Non - Routine Algebra » 2022-08-29 20:53:24

Yes, that would do it. up

That also works in the event of there being joint winners, who would then be named as such.

#168 Re: Exercises » Non - Routine Algebra » 2022-08-28 22:48:56

Hi CurlyBracket;

Yes, I like that method. up

Just a comment re the puzzle wording:

I know what you meant with it, but, in a strict interpretation of the wording, answering the second question could have been a bit awkward if there was a tie...and there are 3 scenarios with at least one winner in which a tie occurs. smile

#169 Re: Help Me ! » Marquis De L'Hopital puzzle » 2022-08-25 15:02:18

Here's a link to a video I created from my Geogebra file.

Marquis De L'Hôpital's pulley puzzle

The animation is from the Slider function that I linked to BC values, and is set to oscillate between BC=70 & BC=72, with 0.00001 increments.

I didn't capture all the increments, of course(!), although it can be done.

Changing BC values moves Point C along Circle A's circumference, impacting on other objects' measurements...including the length of ED.

The oscillation shows ED approaching and reaching its max of ≈51.90438 at BC≈71.322, continuing past it until BC=72, then returning past it until BC=70, and finally back again to ED's max of ≈51.90438.

Jeremy Desmond wrote:

Relying on trigonometry I used my calculator to work out the various altitudes of the weight depending on different angles of BAC, and I repeated the laborious calculation to gradually home in on the maximum result. I got the answer to be 51.90438 to 5 decimal places. This method gives the right answer but in the most boring and prosaic manner possible. It misses out on the beauty and elegance inherent in math.

up

Oh well...I'm sure I'll get over it! wink

#170 Re: Help Me ! » Marquis De L'Hopital puzzle » 2022-08-25 03:24:37

Here are some interesting links about L'Hôpital's Pulley Problem:
     Simple Geometric Solutions to De L'Hôpital's Pulley Problem
     Optimization – L'Hôpital's Pulley Problem
     Proof of length of line segment x

Bob wrote:

Triangle BCE is isosceles...

Shouldn't that read CBE, Bob?

But maybe placing the letter of the vertex angle of an isosceles triangle in the middle is just a habit of mine...similar idea to the order in naming angles.

#171 Re: Help Me ! » What is the number? » 2022-08-24 05:03:40

Edit:
I deleted my answer, which was just the number.
I posted it very prematurely without giving any help at all, despite this being the Help Me! forum. shame
Sorry about that!
>blush<

#172 Re: Help Me ! » Marquis De L'Hopital puzzle » 2022-08-24 04:38:16

Hi Jeremy & Bob,

The maths is beyond me, but I wanted to try graphically, drew this up in Geogebra, and got ED ≈ 51.90438 to 5 decimal places.

lfU9aYI.png

I moved C (radius 100 - BC) along circle A (radius 40) to get the largest ED (approx).

Is that anywhere near the mark? dizzy

#173 Re: Exercises » Non - Routine Algebra » 2022-07-11 03:14:19

Hi CurlyBracket;

Question 5: The Woodcutting Competition:

I think that there was no tie, and Third won, the felling ratio being Third:Second:First = 5:4:3.

EDIT: Included my solution method...

#174 Re: Help Me ! » Tough word problem » 2022-05-24 12:56:38

Hi Median Joe;

I opened my Excel file in LibreOffice Calc, and it ran perfectly...including the Goal Seek function.

#175 Re: Help Me ! » Tough word problem » 2022-05-23 19:48:38

Sorry, Median Joe, but the Goal Seek image had some errors in column D. Fixed now.

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