Math Is Fun Forum

The distance of comet d from a Jupiter's moon is determined by the equation d = 47.9t² + 0.03t - 908.7 whereas t is how many hours passed ever since that comet appeared during June 28 2001. Determine the date when that comet reaches the moon again.

I tried to draw the illlustration as follows:

According to the illustration, t = 0 June 28 2001. After reaching the turning point located in the symmetrical axis, the comet appears once more from that moon. That means, the value of t when the comet comes again to the moon is twice the symmetrical axos, but I got negative number which is -0.03/47.9. Or was my method for solving this question learn?

I think that it has been quite a long time since the last time we have a puzzle like this. In this puzzle, you use all integers from 0 to 9 to arrange a mathematical calculation whose result is the post number. Only approximation is disallowed. Now since it is the first post here, let me do it first which results in 1:
94875326 x 0 + 1= 1
Let's the fun begin! *say it in Sakaki Yuya's style*