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Sometimes the degrees are better than the radians...
Yes, the mistake in pirst proof is from the redians.
I'll try different way.
<[BOC]=4*30°+30((60-35)/60)=132.5°
Please post a proof of k+28 Please! It must be more prime than mine!
The clock:
Here's how must the chessboard look like:
Combined chess-domino question:
Prove that the chessboard with two opposite corners cutted cannot be overlayed with 31 same domino bricks. Each of the brick overlays exactly 2 chessboard cells.
I though some statistical methods could help understanding the sequences.
But no, the numbers are VERY RANDOM.
Here's a picture, that shows it:
hristo, where are you from?
This sequences have been maked with krassi_holmz algoritm!
I told you that it won't be bad.
1, 3, 6, 10, 15, 11, 5, 4, 12, 13, 23, 2, 7, 9, 16, 20, 29, 27, 22, 14, 35, 21, 28, 8, 31, 18, 38, 26, 30, 19, 17, 32, 24, 25, 39, 42, 58, 63, 37, 44, 56, 65, 79, 90, 54, 46, 75, 69, 52, 48, 33, 67, 77, 92, 104, 40, 41, 59, 62, 82, 87, 34, 47, 53, 68, 76, 45, 55
length=68!!!
1, 3, 6, 10, 15, 11, 5, 4, 12, 13, 23, 2, 7, 9, 16, 20, 29, 27, 22, 14, 35, 21, 28, 8, 31, 18, 38, 26, 30, 19, 17, 32, 24, 25, 39, 42, 58, 63, 37, 44, 56, 65, 79, 90, 54, 46, 75, 69, 52, 48
length=50
1, 3, 6, 10, 15, 11, 5, 4, 12, 13, 23, 2, 7, 9, 16, 20, 29, 27, 22, 14, 35, 21, 28, 8, 31, 18, 38, 26, 30, 19, 17, 32, 24, 25, 39, 42, 58, 63
length=38
1,3,6,10,15,11,5,4,12,13,23,2,7,9,16,20,29,27,22,14,35
length=21
But there's infinity long sircular sequence!
Could somebody proof the upper using analisis?
I'll try solving it but i'm not so good at analisis.
Condition for existing line that divides grafhic of f(x) more than 2 times is that is nessesery to exist at least one inflex point.
And we'll proof that there doesn't exist line that intersects with 2^i more than 2 times. That's because
ln x means natural logaritm of x
(2^i)'=2^i(ln2)=2^iC
That means that (2^i)' is a monotonic growing function so (2^i) is "convex".
Geometric proof:
We have two answers:
x=1 and x=2.
Picture 6: The function we've iust assembled.
Picture 5: ss[x]=sinr[x]/(|sinr[x]|)
Picture 4: sinr(x)=sin(Pi x)
Picture 3: sin[x]