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Hi ganesh,
Hello,
*ignores what has just been said and does the actual exercise*
I will the rest later.
Hey ganesh
Hey ganesh
Hey
Yeah I must have added an extra zero in my working somewhere XD, sorry!
Hello!
I don't like trains >_<
Hi guys;
This took me longer than expected to answer >_<
Hey,
Sorry, I don't know how to solve this, D:
Can you tell me the solution?
Thanks
Hey ganesh,
Hey ganesh,
Yes, I understand this now
Thank you bob and bobby and anonim!
Because the question says that the different equation has to have 2 as a root
I don't think so because the question asks for the sum of the roots of the ORIGINAL equation, not the different equation
That is if you're thinking the roots are 2 and 1, but that is from the different equation, not the original
Unless your saying the roots of the original equation are 1/2 and √19 / 2
Which I don't think is right
Oh okay thanks guys!
Yeah, after using your methods, I get 5/4 as well
I tried doing something different:
Let the solutions of the different equation be X and 2
The solutions of the original equation is 1/X and 1/2 (after playing around, I found this rule)
So 1/X=X
Which means X=1 or -1
Sum of squares (1)²+(1/2)²=5/4
Btw even though 2x²-5x+2 works, the question says 2 different equations, 1 original and the other with the coefficients swapped... this stays the same.
Thanks a lot guys!
As for Q2
Can you tell me what equations you formed, because I couldn't make some..
Oh okay anonimnystefy,
so I make the equation: (x-2)(ax+b)=0
ax²+(b-2a)x-2b=0
And the other equation is -2bx²+(b-2a)x+a=0
Which factorises to (bx+a)(-2x+1)=0
And the solutions are -a/b and 1/2
Okay so either -b/a=-a/b or -b/a=1/2
Doesn't that mean theres still many solutions for a and b?
Also, I don't have the answers so I'm trusting you guys ;S
Yeah, probably
I used the quadratic formula to solve for the two equations,
but I don't know which one to be 2 or to be equal with the other roots from the other equation
Hey guys!
Well I've been trying to do previous exams as practice for the one I have next week.
I came across 2 questions, of which I have no idea how to solve.
If you guys could show working and explanations so that I understand as well, that'll be great.
Q 1
While attempting to solve a quadratic equation, Christobel inadvertently interchanged the coefficient of x² with the constant term, causing the equation to change.
She solved this different equation accurately.
One of the roots she got was 2 and the other was a root of the original equation.
What are the sum of the squares of the two roots of the original equation?
I tried letting the first equation be ax²+bx+c=0 and the other be cx²+bx+a=0 but then I didn't know what to do...
Q 2
A goods train leaves Southampton at 9.17 am and arrives in London at 12.02 pm.
On the same day, a passenger express train leaves Southampton at 9.56 am and arrives in London at 11.36 am.
At what time does the passenger train pass the goods train if each is travelling non-stop at constant speed?
Yeah... I didn't even bother trying this question, I have no clue as to what variables I need to make or such..
Any help is appreciated. Thanks guys.
Hey guys,
The ones I answered:
The rest are too hard for me XD
Hey guys,
Hey guys,
Hey guys,
Hi ganesh!