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  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

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#126 Re: Help Me ! » I hope someones sticky's this "Amazing math resource" » 2008-04-06 13:25:54

I promise it's secure, I use it all the time to help me when I'm doing solids of revolution, I've scanned the kernel with symantic and it's virus and spyware free. Feel free to test it and tell me what you think.

#127 Re: Help Me ! » I hope someones sticky's this "Amazing math resource" » 2008-04-06 12:08:12

http://mathplotter.lawrenceville.org/mathplotter/MSP/resources/solids/solids

Try this one, and if you get the same warning I don't know what to tell you.

The first link is to a directory of various applications, the one in this post is to an equation plotter that vinds the volume of a solid of revolution and gives the graph as well as the 3-D picture. It's quite useful.

#128 Re: Help Me ! » Tell me what I did wrong >.< » 2008-04-06 11:10:25

Luis, I thought that when you had a horizontal axis of revolution that your equation is in terms of x???

#129 Help Me ! » I hope someones sticky's this "Amazing math resource" » 2008-04-06 11:07:17

SvenBee
Replies: 7

http://mathplotter.lawrenceville.org/mathplotter/mathPage/index.htm

This pretty much has you set on any number of advanced math through higher level questions.


Hope it's Useful to everyone!!!


Cheers, Sven

#130 Re: Dark Discussions at Cafe Infinity » I hope this is okay » 2008-04-06 11:04:05

If you're going to play portal the only way to play it is on P.C. Although the physics engine of the Hl2 series is amazing on both platform and P.C. the control you get with a mouse and keyboard can't be touched by the controller.  As for good games: Halo 3 (A given), Rainbow 6 Vegas 2, Gears of War, COD 4, condemned 1 and 2, and for the non-FPS games, Guitar Hero 3 is a must, as well as Rock Band.  Assassin's Creed  is an exceptional game but it's nothing new if you have played a Prince of Persia game before.  Dark Sector is good and Oblivion is good if you are an MMORPG kind of person.

P.S. Don't know where you're from, but all these games are out here in the U.S. =P

#132 Help Me ! » Tell me what I did wrong >.< » 2008-04-06 03:40:41

SvenBee
Replies: 26

I got a my grades posted today on a math test and there was one problem that I thought I did correctly, but it turns out I did it wrong.

Set up the integral using the shell method for:

Some please just explain how to set up this integral.

#134 Re: Help Me ! » Integration » 2008-04-02 06:49:20

Oops, what level calc are you in? It might be better to do integration by parts.

#135 Re: Help Me ! » Integration » 2008-04-02 06:47:51

U-substitution. If you need a bigger nudge bump me.

#136 Re: Dark Discussions at Cafe Infinity » how old » 2008-04-02 06:34:24

17 18 in Oct. and moving FAR away to college, woot!! can't wait. :DDD

#137 Help Me ! » Don't need help this is just to see who else can do this quickly :D » 2008-04-02 05:34:53

SvenBee
Replies: 0

There are 11 problems and each student was given 1 and a half hours to do it.  Ok, show all of your work ( aka post it and your answers big_smile ) and how long it took you to do them. Remember that this was given to Calc 1 students who haven't learned integration by parts yet. wink

1. A tank on the wing of a jet is formed by revolving the region bounded by the graph of

and the x-axis.  The axis of rotation is the x-axis. Find the tank's volume, given that x and y are measured in meters.


2. Set up the integral a, b, and c using the Shell Method, solving is not necessary. Woot!


     a. Revolving about the x-axis.
     b. Revolving about the y-axis.
     c. Revolving about y=1


3. Another JUST SETTING UP (Don't solve) using both the Washer and the Shell method.


4. Again just setting up (I don't think I need to say that it's not necessary to solve but I will again tongue) using any method.


5. Match each integral with the solid whose volume it represents.
Choices:     a. Right cylinder     b. Sphere     c. Cone

     i.

     ii.

     iii.

I know it's redundant to have
but that's how it's written.


6. Find the area of the zone of a sphere formed by revolving the graph of

about the y-axis.


7. Set up and evaluate with a calculator surface area generated by revolving the curve

about the x-axis on the interval [1,2]


8.A spring of natural length 10 in. stretches 1.5in. under a weight of 8lbs. Find the work done in stretching the spring:
     a. From it's natural length to a length of 14in.
     b. From a length of 11in. to a length of 13in.


9. A freight elevator weighing 3000lbs is supported by a 12ft. long cable that weighs 14lbs per foot. Approximate the work required to life the elevator 9ft. by winding the cable onto a winch.


10. A force of 25lbs is required to compress a spring of natural length .8tf to a length of .75ft. Find the work done in compressing the spring from its natural length to a length of .7ft.


11. A vertical cylindrical tank of diameter 3ft and a height 6 ft is full of water. Find the work required to pump all the water over the top of the tank.

When we did this review Monday we were scored out of 10 with the question we scored the least points on omitted. See how well you do!!
Good luck and remember to time yourself.

#138 Re: Help Me ! » basic probability stumping me nonetheless » 2008-04-01 11:42:45

My bad posted as a guest, but I'm a member. bump XD

#139 Re: Help Me ! » How should I integrate this? » 2008-03-10 14:56:50

You could also integrate by U-sub. if you were like me and in Calc. AB and didn't know parts yet. dunno

But if that were the case you would have to sub U back in a second time.

Good luck.

(>^^)> here's a kirby for you.

#140 Re: Help Me ! » Need help with this mathematical induction problem. » 2008-03-08 09:42:30

Thanks!

= (4)2^(2k+1)+(9)3^(2k+1)

= (4)2^(2k+1)+(4)3^(2k+1)+(5)3^(2k+1)

= (4)[2^(2k+1)+3^(2k+1)]+(5)3^(2k+1)

And since {2^(2k+1)+3^(2k+1)} is already divisible by 5 from the previous step and (5)3^(2k+1) is being multiplied by 5 it is logically divisible by 5, the entire f(k+1) is divisible by 5 and the proff is complete. qed.


Is that correct and thank you.

#141 Help Me ! » Need help with this mathematical induction problem. » 2008-03-08 06:05:30

SvenBee
Replies: 3

Prove that 2^(2n+1) + 3^(2n+1) is divisible by 5.

I completed the trivial first step and when n=1 the equation proves true.

So far I have:

f(n)=2^(2n+1) + 3^(2n+1), and since n=k and f(n)=f(k) then f(k) is divisible by 5 (or f(k)=5x, where x is an integer)

then:

2^(2k+1) + 3^(2k+1) for the second step

Inductive step:

2^(2(k+1)+1) + 3^(2(k+1)+1) = 2^(2k+3) + 3^(2k+3) = (4)2^(k+1)+(9)3^(k+1)

That's as far as I can get. I don't know what the next step is. PLEASE HELP!!!!

Thanks.

#142 Re: Help Me ! » Calculus » 2008-03-08 05:59:10

du, dx, dy... They are all notations representing "with respect to". But... when you get to the point where you are graphing the area under the curves they become interchangeable with Δx, Δy, Δu, etc. The variable being integrated (u in u substitution) has to be respected. For example: ∫u dx is nothing.  You cannot integrate or derive a function of one variable with respect to another. So in cases where it is used in u-substitution and swapped with dx it is treated like a variable itself.

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