You are not logged in.
Length: 10
MaxNumber: 23
sq(23,10)={23, 2, 7, 9, 16, 20, 5, 4, 12, 13}
Plots:
But we may say:
2) x^2 hasn't inverse function because there exist two solutions of
x^2=y
x1=sqr(y)
x2=-sqr(y)
So inverse function must have 2 different values at point y.
To reduce this we need to use only positive x in the first function.
I way:
i think if we can proof that f[g[x]] = x
For example: f[x]=2x; g[x]=x/2
f[g[x]]=2(x/2)=x
I presentiment katy will become bery good in Maths.
jadesia, please post this into the introductions, too.
Yes, I can, but it's ugly:
a=bx^3+cx^2
I need to inprove my algoritm.
Length:28
MaxNumbr:52 !!!!
sq(41,28)={41, 8, 1, 3, 6, 10, 15, 21, 4, 5, 11, 14, 2, 7, 9, 16, 20, 29, 35, 46, 18, 31, 33, 48, 52, 12, 13, 23}
Length:21
MaxNumber:35
sq(32,21)={32, 4, 5, 11, 14, 2, 7, 9, 16, 20, 29, 35, 1, 3, 6, 10, 15, 21, 28, 8, 17}
Length:23
Maximal number:35!
sq(21,23)={21, 4, 5, 11, 14, 2, 7, 9, 16, 20, 29, 35, 1, 3, 6, 10, 15, 34, 30, 19, 17, 8, 28}
A 36 long. Max=52(F**K IT!!!)
sq(19,36)={19, 6, 3, 1, 8, 17, 32, 4, 5, 11, 14, 2, 7, 9, 16, 20, 29, 35, 46, 18, 31, 33, 48, 52, 12, 13, 23, 26, 10, 15, 21, 28, 36, 45}
A 28 long, MaxNumber=52(too close ):
sq(13,28)={13, 3, 1, 8, 17, 19, 6, 10, 15, 21, 4, 5, 11, 14, 2, 7, 9, 16, 20, 29, 35, 46, 18, 31, 33, 48, 52, 12}
Then you have got much luck!
sq(1,23) means with length 23, tarting on 1 that is generated by my algoritm. My algoritm gives it too.
sq(3,24)={3, 1, 8, 17, 19, 6, 10, 15, 21, 4, 5, 11, 14, 2, 7, 9, 16, 20, 29, 35, 46, 18, 31, 33}
Length-24
#<50
Yes, yes.
And seerj's curves are close.
For the 1b problem.
The parabloa is quadratic surve. So you're right.
Conjection:
The greatest number in the chain sq(1, n) is >n and ≈2n.
Oh. I forgot!
sq(x,y) - x means the first number in the chain, y-the length of the chain.
I just have found something very interesting:
The biggest number in the square sum chain sq(2,17)={2, 7, 9, 16, 20, 5, 4, 12, 13, 3, 1, 8, 17, 19, 6, 10, 15} with length 17 is 20!
Unfortunately sq(2,17) is not circular.
Of course, but I thought that you are not permissed to calculate the discriminant.
And something else :
10>3^2 => discriminant is > 0.