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#1326 Re: Puzzles and Games » . » 2005-12-31 13:34:23

Recursive:
Let use this:
a[i]=F[a[1],a[2],...,a[i-1]] depends of a[1..(i-1)]
We must fund iteractive approach.

#1327 Re: Puzzles and Games » . » 2005-12-31 13:30:56

kylekatarn wrote:

What's wrong?
That is computable in a finite number of steps: )

acc := 0
k:=1

while i<n
{
   acc:=acc+1/i^k
   k:=k+1
}
in the end, return acc

You have forgotten one line:
while i<n
{
acc:=acc+1/i^k
k:=k+1
i:=i+1
}

#1328 Re: Puzzles and Games » . » 2005-12-31 13:28:14

First we must define what are the differences between the Iterative and Recursive approach.

#1329 Re: Puzzles and Games » . » 2005-12-31 13:20:59

Then R-I conjecture must be true.

#1330 Re: Puzzles and Games » . » 2005-12-31 13:19:26

Oh,so "iterative" meant this?
Then...

#1331 Re: This is Cool » Fermat's last theorem » 2005-12-31 11:30:36

Thank you Siva, but it's not the full proof.

#1333 Re: Help Me ! » Help with 3D rotation » 2005-12-31 09:42:44

As you see the coordinates of A in the second coordinate system A=={x',y'}II are equal to the coordinates of point A1 =={x',y'}I, which is A, rotated 45deg --clock.
So we must find what will be the coorinates of point A{x,y}, when we rotate it 45deg --clock.

#1336 Re: Help Me ! » Help with 3D rotation » 2005-12-31 05:20:52

1. Coordinate transforms:
Let the point A has coordinates {a,b} in coordinate system xOy.
We must find the coordinates of a in coordinate system x'Oy', which is xOy rotated 45° ++clock:

#1337 Re: Help Me ! » Help with 3D rotation » 2005-12-31 03:50:02

For the first -you're right.
For the second-no.
I'm starting explaining everything.

#1338 Re: Help Me ! » Factor Theorem? » 2005-12-31 03:46:17

Here is it:
(x-a1)(x-a2)(x-a3)=-a1 a2 a3 + (a1 a2 + a1 a3 + a2 a3) x - (a1 + a2 + a3) x² + x³.
The coeficients for the same powers of x must be same, so:
a1 a2 a3 = 15 AND
a1 a2 + a1 a3 + a2 a3 = 13 AND
a1 + a2 + a3 = -3

(
|equation1
|equation2
...
|equationm
means equation1 && equation2 && ... equationm
(system)

#1342 Re: Puzzles and Games » . » 2005-12-31 01:35:40

Try to calculate


with iterative approach!
smile smile

#1343 Re: Puzzles and Games » . » 2005-12-31 01:33:04

I'll find a counter-example

#1346 Re: Dark Discussions at Cafe Infinity » obsessed with proofs » 2005-12-31 01:18:48

The things that cannot be proved are the axioms.
They are true without proving.

But something very very interesting:
Guedel proof that there doesn't exist a full set of axioms, e.a. there exist a statement that cannot be proved using finite number of axioms.

#1347 Re: Help Me ! » Factor Theorem? » 2005-12-31 00:02:44

A factorization in complex numbers:
x^3+3x^2+13x-15=(x-a1)(x-a2)(x-a3)
So
|-a1a2a3=-15
|a1a2+a2a3+a3a1=13
|a1+a2+a3=-3

#1348 Re: Help Me ! » Factor Theorem? » 2005-12-30 23:43:39

Yes. Other roots are immagineric.

#1349 Re: Help Me ! » D(x^x) » 2005-12-30 23:32:04

And how is
∫(x^x)dx?

#1350 Re: This is Cool » vector multiplicated by i » 2005-12-30 23:28:06

I think you are right. But in Minklovski's 2D space the length between two points (x1,y1) and (x2,y2) is
L=sqrt(|x1-x2|²+(i|y1-y2|)²)=sqrt(|x1-x2|²-|y1-y2|²)

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