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#101 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-11 00:59:38

Instead of just countering points, I'll try posting one of my own for Anthony to counter.
If 0.999... is 0.000...1 difference from 1, where 0.000...1 has an infinite amount of 0s, followed by(?) a 1, then what is half of the value of 0.000...1? For any two numbers that are not equal, we should be able to find the average of those two numbers, being equal to half the difference between them. So the average of 0.999... and 1 should be equal to 0.999... + (0.000...1 / 2), so I'm wondering how you believe we'd be able to do that math, and what the answer should be?

#102 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-11 00:56:33

Anthony.R.Brown wrote:

---------------------------------------------------------------------------------------------------------------
THE INFINITE/RECURRING ( N ) = N PROOF 11/03/07 by Anthony.R.Brown
---------------------------------------------------------------------------------------------------------------

Infinite Recurring ( n ) = n because! ( n ) will always = n

Wow, that's so wrong....
So 0.222... = 2?

I'll assume you mean 0.222 = 0.2; But that's wrong too
0.555... = 0.5? What about the 0.0555... difference?

#103 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-09 02:29:27

Anthony.R.Brown wrote:

(1) C <> ( C + D ) " INFINITE 0.9 <> 1 " " C must always = .999... and D must always = .001...

(C + D ) or A  only = 1 " That's an Infinite Proof!! " making C < 1

So your argument is that C MUST not be equal to C + D because 0.999... is not equal to 1, so C must be < 1, meaning that 0.999 is not equal to 1. The problem with this is still the second step... you're assuming 0.999... is not equal to 1, and using that to support your proof that it isn't. You can't just use an assumption to support a proof of that assumption, you must first prove it to be true. If you drop the assumption, then C can equal C + D for cases where D = 0, therefor C + D = 1 = A, if D = 0 then C = A.

Anthony.R.Brown wrote:

(2) " This quote has also been rebuttled above. "
(2) Prove yourself wrong with this one! and give us your Definition for Recurring?

Recurring - A recurring decimal (or "repeating decimal") is an expression representing a real number in the decimal numeral system, in which after some point the same sequence of digits repeats infinitely.

Anthony.R.Brown wrote:

(3) " I don't even understand this one... there's a 10% difference between what? 0 and 9? And where did the 1.8, 2.7, etc, come from? I'm thoroughly confused, sorry. "

(3) you will always be " thoroughly confused " unless you learn where Numbers come from! and how they are made!

Okay, I did some reading and learned that numbers originally come from Sumeria, between 8000 and 3500 BC. About 3100 BC they invented the concept of abstract numbers that don't represent specific items. Originally they were made of small clay tokens, but they gradually became markings made with a round stylus at different angles, to represent the different numbers.

Now although I find the history lesson fascinating, I'm sure that you didn't mean for me to study 10 000 years of numerical history to understand why you're multiplying 0.9 x 4 as part of a proof that shows there's a 10% difference between 3.6 and 4.0, which somehow represents that 0.999... is less than 1. But the problem is that I'm not sure what else you could mean by "where numbers come from and how they're made". Why does a number have to come from somewhere? Where does the number 1 come from? What about 0.9? What about 4? Does it matter where these numbers "come from"? We all understand what they represent, right? Or do we have to start this conversation with a proof of the relationship be 1 and 2, and why 3 <> 2, 3 > 2 > 1, and where does 4 fit into this odd series of symbols?

#104 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-08 01:25:06

Anthony.R.Brown wrote:

A = 1                " Single Start Value For 1 "

B = 0.9             " Single Start Value For 0.9 "

C ( A/B ) x B     " Infinite 0.9 Value "

D ( A - C )         " Infinite < 1 Value "

C <> ( C + D )  " INFINITE 0.9 <> 1 "

This proof has been countered many times, and you've still yet to raise a coherant defense for it.

Anthony.R.Brown wrote:

( 0.1 ) Recurring < 1 and <> 1

( 0.2 ) Recurring < 1 and <> 1

( 0.3 ) Recurring < 1 and <> 1

( 0.4 ) Recurring < 1 and <> 1

( 0.5 ) Recurring < 1 and <> 1

( 0.6 ) Recurring < 1 and <> 1

( 0.7 ) Recurring < 1 and <> 1

( 0.8 ) Recurring < 1 and <> 1

( 0.9 ) Recurring < 1 and <> 1

This quote has also been rebuttled above.

Anthony.R.Brown wrote:

---------------------------------------------------------------------------------------------------------------
INFINITE 0.9 <> 1 PROOF : THE INFINITE 10 % PERCENT DIFFERENCE 03/03/07 
by Anthony.R.Brown.
---------------------------------------------------------------------------------------------------------------
One of the most Accurate and sound ways to prove Infinite 0.9 <> 1 is to give the Infinite Percent Difference Values from the Start Onwards!

The example below is for the first Ten Decimal Place's,which clearly shows the count increasing as more and more Infinite .9's are looked at! But remain a constant Difference of 10% in relation to how far the example has traveled.

Count = ...... ( 1 ).....( 2 )....( 3 )...( 4 )....( 5 )...( 6 )....( 7 )....( 8 )....( 9 ).....( 10 )

Infinite 10 %
Difference =..(10%).(10%).(10%).(10%).(10%).(10%).(10%).(10%).(10%)...(10%)


Infinite 0.9 = ( 0.9 ) ( 1.8 )  ( 2.7 ) ( 3.6 )  ( 4.5 ) ( 5.4 ) ( 6.3 )  ( 7.2 ) ( 8.1 )  (  9   )

................... ( x 1 ) ( x 2 )  ( x 3 ) ( x 4 )  ( x 5 ) ( x 6 ) ( x 7 )  ( x 8 ) ( x 9 )  ( x 10 )

Infinite 0.9 Onwards! there will always be a 10 % Difference making it Impossible for Infinite 0.9 to ever = 1

I don't even understand this one... there's a 10% difference between what? 0 and 9? And where did the 1.8, 2.7, etc, come from? I'm thoroughly confused, sorry.

Anthony.R.Brown wrote:

p.s This is my last Post on this so called Math forum! unless the Post title is Changed to something that is not BIASED!

The Moderators! and Admin should only be Referees! and not have any Personnel Opinions on the Math subjects! and especially not allow titles like this! that straight from the Start are clearly expressing a BIASED View!

The title was already changed to be unbiased. It's now a question of whether or not 0.999... = 1, open for discussion on whether or not it's true.

#105 Re: This is Cool » Infinite 0.9 And Recurring 0.9 : Posts Only! : Unbiased! » 2007-03-07 01:15:18

George,Y wrote:

Yes he's right. The title "0.999...=1" is already biased even before a reader opening the thread.

Then why don't we just ask a Moderator to change the title of the thread, instead of starting yet another new one?

#106 Re: This is Cool » Infinite 0.9 And Recurring 0.9 : Posts Only! : Unbiased! » 2007-03-07 01:03:00

Isn't this just ANOTHER duplicate topic of the conversation that's already gone on at 4 different threads by now? Can't we just keep it all in one place?

#107 Re: Help Me ! » Heeeeelp Please » 2007-03-06 14:03:39

Do you need to use all 4 numbers? If not, it's pretty easy, just remember that dividing a fraction is like multiplying by it's inverse (so 4 / 1/6 = 24)

If you need to use all 4, obviously the 1 is easy, but working in the 3/8 is a bit harder...

#108 Re: Help Me ! » I Need Help Bad!!! » 2007-03-06 08:32:44

pi man wrote:

Sally  (sin)          =  Oscar (opposite)     \   Hat (Hypotenuse)
Can    (cosine)    =  Has (hypotenuse)    \   On (Oppposite)
Tell     (Tangent) =  A (adjacent)            \   Always (adjacent)

"Sally Can Tell Oscar Has A Hat On Always"   (except we used a different word instead of "hat".   Think about,  it's not hard.   Or maybe it is).

Hmm... except that if you memorize that you'll always get the wrong answers. ;-) (especially since you'll always get "Tan = 1" for any angle, hehe)
SOH CAH TOA means that
Sally  (sin)          =  Oscar (opposite)     \   Has (Hypotenuse)
Can    (cosine)    =  Always (adjacent)    \   Hat (hypotenuse)
Tell     (Tangent) =  On (Oppposite)            \   A (adjacent)
Which makes much less sense. :-o

#109 Re: Help Me ! » I Need Help Bad!!! » 2007-03-06 07:03:38

Leslie wrote:

i need help finding another sentence for the word SOHCAHTOA  meaning sin  opposite  hypotenuse, cos adjacent hypotenuse, & Tan  opposite adjacent???? please help if you can

I never used a sentence, I always just remembered it as Soh Cah Toa (sounded out as 3 words), and found that easier than trying to remember that Sally Only Hates Cars And ... (whatever silly pneumatic you can come up with). Or if you have trouble remembering Soh Cah Toa, try "Sock it To ya!" (same thing, just translated into real words)

#110 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 05:00:34

Anthony.R.Brown wrote:

How many times do I have to explain it to you! they are the start! unless you can show how Infinite Numbers start in a Different way! then you have no argument!!

Infinite numbers don't "start" in any way. 0.999... is an infinitely recursive number. So is 0.111... and so is 0.010101.... These numbers each have several ways of being represented (infinitely recursive decimals or fractions), but they are still numbers, independantly of the formula that you might've used to achieve that number.

#111 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 04:55:46

Anthony.R.Brown wrote:

To mathsyperson

This is the Sister thread! the other one got no response! lets keep it fare!

A.R.B

By "sister thread" I think he meant that he'd also close the "proof why 0.999... = 1" thread that you created your thread in retaliation to. Now both are closed, and all of the discussion about this should continue on this thread alone.

#112 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 04:51:53

Anthony.R.Brown wrote:

To Maelwys

Quote:

" There you go on about the "single value" again, which I still don't understand or recognize as any valid math theory. I really have no idea what this last sentence of yours means (or should I say sentences, since there seems to be punctuation randomly in the middle of it). "

A.R.B

The most important thing to do with any Argument! is knowing where the Numbers have come from! and how they are made!

A number is a number, and the value that is has is the value that it has. 0.999... has a value of 0.999..., it doesn't have a value of 0.9 anymore than it has a value of 42, and it never did.

Anthony.R.Brown wrote:

Because we are Calculating an Infinite Number!! and Calculators Round the Number up!!

Lets look at the Start again!

Infinite 0.9 "one Decimal place " x 1.1 = 0.99

Infinite 0.9" two Decimal place's " x 1.11 = 0.999

Those aren't infinite numbers, those are real numbers (you're just multiplying 0.9 x 1.1, no infinite-long recursions involved in that). You can't apply normal rules for finite numbers into infinitely recursive numbers, just like you can't apply normal rules for finite numbers into infinity. Infinity + 1 = Infinity, but if you said that about any real number, you'd be wrong (1 + 1 = 1 is an incorrect statement, for example).
0.9 x 1.1 <> 1
0.9 x 1.11 <> 1
but
0.9 x 1.111... = 1

Lets take this a different way. For any two different numbers, M and N, there is always a 3rd number P that can be added to M to equal N, because P expresses the difference between the two numbers. There is also always a 4th number Q that can be multiplied by M to equal N, because Q expresses the ratio between the numbers.
So, if
M = 0.9
N = 1
What do you believe the numbers P and Q are?

#113 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 04:27:48

Anthony.R.Brown wrote:

" Alright, here's a different one. 1/3 * 3 = 0.999... 1/3 = 0.333... * 3 = 0.999... Agreed? "

A.R.B

Firstly using fractions is not accurate! you cant get a true 1/3 Decimal Value!

i.e give me 3 Single Decimal Values of equal Value! that equal 1

I wasn't using fractions, I was expressing a division of 1 divided by 3 * 3 (the same way you were dividing 1/0.9 * 0.9). Yes, my 1 divided by 3 = 0.333... is a repeating value, the same way that your 1 divided by 0.9 = 1.111... is a repeating value.

Anthony.R.Brown wrote:

Allowing for your mistake! you are now agreeing with me! that your version of Infinite 0.9 has come from the single Value of 0.333... x 3

But just as I said! from the first Decimal point onwards when there is a total Value of 0.9 this is the first single value for your version of Infinite 0.9

There you go on about the "single value" again, which I still don't understand or recognize as any valid math theory. I really have no idea what this last sentence of yours means (or should I say sentences, since there seems to be punctuation randomly in the middle of it).

#114 Re: This is Cool » INFINITE 0.9 <> 1 PROOF : COMPLETE : By,Anthony.R.Brown,15/02/07 » 2007-03-06 04:18:23

Anthony.R.Brown wrote:

1 is divided by 0.9 = 1.111....." this proves 0.9 is less than 1 "

Okay, I'm with you so far. 0.9 < 1.

Anthony.R.Brown wrote:

i'm now going to mutiply it so nothing will change!

0.9 x 1.111.... " will always equal a Value less than 1 " because 0.9 was divided within a greater Value! that Value being 1

Lost me here. How do you conclude that the answer will be less than 1, based on a previous calculation you did? My logic tells me that it's equal to 1. My calculator tells me that it's equal to 1. It seems to me like it should be equal to 1. Why isn't it?

#115 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 03:54:38

luca-deltodesco wrote:

oh and yes, windows calculator actually does give that result, although a less precise one would not.

Lol, that's funny... all this time debating and I never even thought to try punching that formula into windows calculator. I just assumed that it rounded to 32 digits (although that's impressive in itself) and would give the 0.999... result for the formula. Apparantly it's smarter than I gave it credit for, with regards to infinitely repeating decimals. ;-)

#116 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 03:31:24

Anthony.R.Brown wrote:

To Maelwys

Quot: " Umm... read the first line of my reply above "

A.R.B

You obviously cant think for yourself! don't copy my examples! put something forward yourself! or are you afraid of it being ripped to pieces! by me showing you any Infinite Number Starts from a Single Value!

I answered your question, with a formula that we can both agree on, to ensure that we have a common point of understanding, and now you're insulting me for it? You asked me "NOW YOU HAVE TO SHOW AS AN ARGUMENT! WHERE YOUR VERSION OF INFINITE 0.9 COMES FROM! AND I WANT TO SEE THE MATH!!" and I answered "1/0.9 * 0.9 = 0.999..." which is all the math you need, and it's something that I already know you agree to (so once less thing for us to argue about) and you're refusing it as an explanation simply because you stated it first?

Alright, here's a different one. 1/3 * 3 = 0.999... 1/3 = 0.333... * 3 = 0.999... Agreed?

#117 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 03:06:06

Anthony.R.Brown wrote:

To Maelwys

A.R.B

Better than that!! Answer my Main Question for once!

" NOW YOU HAVE TO SHOW AS AN ARGUMENT! WHERE YOUR VERSION OF INFINITE 0.9 COMES FROM! AND I WANT TO SEE THE MATH!! "

Umm... read the first line of my reply above. "I'm not arguing against the idea that 1/0.9 * 0.9 = 0.999..., I completely agree with that. "
So I agree with you that A/B * B = 0.999..., I just also happen to believe that A/B * B = A = 1, which means that 0.999... = 1

#118 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 02:35:47

Anthony.R.Brown wrote:

It's very clear! a Child could understand this Calculation!!

A = 1 " " A.R.B = " " A = 1 "
B = 0.9            " Single Start Value For 0.9 " " A.R.B = " " B = 0.9 "
B = ( A/B ) x B    " Infinite 0.9 Value " " A.R.B = " " B = 1/0.9 x 1.111... "

As clear! as clear! can be!! Infinite 0.9 starts as 0.9 It then shows how it is/becomes Infinite!
I am afraid you have no argument! if you think you can just pluck a Value out of the sky! and call it an Infinite Number!

NOW YOU HAVE TO SHOW AS AN ARGUMENT! WHERE YOUR VERSION OF INFINITE 0.9 COMES FROM! AND I WANT TO SEE THE MATH!!

I'm not arguing against the idea that 1/0.9 * 0.9 = 0.999..., I completely agree with that. However, I also argue that X/Y * Y = X for any X, and any Y <> 0; which means that 1/0.9 * 0.9 = 1 as well, meaning that 0.999... = 1. I also take issue that B = A/B * B, because you can't change the value of a variable halfway through an equation, which makes it appear that you're saying 0.9 = 0.999..., which is definitely not the case. If you want to go back to saying C = A/B * B, I'm okay with that, but I'll continue to use my proof above to show that C = A, and D = 0.

#119 Re: This is Cool » INFINITE 0.9 <> 1 PROOF : COMPLETE : By,Anthony.R.Brown,15/02/07 » 2007-03-06 02:17:30

Anthony.R.Brown wrote:

To Maelwys

Quot: " B isn't being infinitely multiplied by 1.1 as far as I can see... "

A.RB

you always cant see very far!!

from my Formula

C ( A/B ) x B    " Infinite 0.9 Value " ( = C ) using another variable! makes things clearer! it can also be wrote as " B is being infinitely multiplied by 1.1 "

Sorry, I was looking at the wrong B. But you still didn't respond to the rest of the issue I had with your formula, just managed to pick up on the one inconsequential comment that I made and was wrong about.

#120 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 02:16:18

Anthony.R.Brown wrote:

A = 1

B = 0.9            " Single Start Value For 0.9 "

B = ( A/B ) x B    " Infinite 0.9 Value "

That formula is clearly wrong though. Now you're trying to prove that 0.9 = 0.999...? In what world can B = A/B * B?

#121 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 02:05:23

Anthony.R.Brown wrote:

in my Formula below B Starts as 0.9 and is < 1 everyone has agreed! it becomes Infinite 0.999...as C

B doesn't "become" 0.999..., B is still 0.9, C is 0.999...
Using your logic I could just as well say "in your fomula, A starts equal to 1, and then by being divided by B and then multiplied by B, A becomes equal to 0.999..., proving that 0.999... = 1"

#122 Re: This is Cool » INFINITE 0.9 <> 1 PROOF : COMPLETE : By,Anthony.R.Brown,15/02/07 » 2007-03-06 02:02:04

Anthony.R.Brown wrote:

" why would A/B × B ≠ A? "

Because B is being Infinitely Multiplied by 1.1 which is .1 > 1

If the Number 1 was also Infinitely Multiplied by 1.1 it would again be greater than B

B isn't being infinitely multiplied by 1.1 as far as I can see... there's not even any infinitely recurring numbers in the formula, A = 1, B = 0.9, very straightforward. And using our definitions of multiplication and division, we know that the two are opposites and basically cancel each other out, so we know that A/B * B = A. Just like I have no idea what 5678544 / 23349 is, but I know that if I multiply the answer by 23349, I'm going to get a final answer of 5678544. I don't need a calculator to tell me that, pure logic will do it (and verifying it on a calculator I'm told that 5678544 / 23349 = 243.2028780675831941410767056405, and 243.2028780675831941410767056405 * 23349 = 5678544).

#123 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-06 01:38:28

Anthony.R.Brown wrote:

All you have to do!! is show a Number that Starts < 1 and <> 1 that is Recurring!

and is! or somehow becomes! > or = 1 and yet still conforms to the Definition Recurring!!

then you have won! the Argument! I'm Sure we will all have a long! long! Wait!......................

What? Numbers can't "start <1 and somehow become >= 1". A number is a number, and doesn't change in any way. So of course I can't show you a number that magically changes. The problem seems to be your belief that 0.999... starts <1, which it doesn't. 0.999... = 1 at all times, it doesn't start <1 and become =1, it is simply = 1. And don't say "but it starts at 0.9" just because those happen to be the first couple digits of the number, because that doesn't mean anything at all. In mathematics, there is no such thing as a "single start value" that is equal to the first few digits of the number. A number is equal to what the number is, it is in no way equal to what the first few digits are (unless it's only those digits). I'm not sure how many more different ways I can try to make you understand that.

#124 Re: Puzzles and Games » Where did the dollar go puzzel? or How come I am $2 up? » 2007-03-05 03:49:09

JaneFairfax wrote:

Now you’re confusing me even more. Why do you plus 2 to the 27? The $27 includes the $2 that the waiter deviously pockets for himself, so what for add 2 to it?

See,

            $27                          =      $25            +          $2
(amount spent by the ladies)    (price of meal)     (unreturned change)

Please explain to me why you need to add 2 to 27 because this is getting on my nerves. swear

And that's exactly the point of the riddle. By phrasing it the way that Pi did (as the riddle does), it tricks the listener into thinking that there's money missing. But as you picked up on, there isn't any money missing at all, because applying the numbers in that way is false logic. But if you don't realize that right away, it can be a tricky puzzle, trying to figure out where the "missing dollar" went.

#125 Re: This is Cool » 0.9999....(recurring) = 1? » 2007-03-04 04:33:04

Anthony.R.Brown wrote:

( 0.1 ) Recurring < 1 and <> 1

( 0.2 ) Recurring < 1 and <> 1

( 0.3 ) Recurring < 1 and <> 1

( 0.4 ) Recurring < 1 and <> 1

( 0.5 ) Recurring < 1 and <> 1

( 0.6 ) Recurring < 1 and <> 1

( 0.7 ) Recurring < 1 and <> 1

( 0.8 ) Recurring < 1 and <> 1

( 0.9 ) Recurring < 1 and <> 1

I'm not sure I see your logic here... just because 1 < 9, 2 < 9, 3 < 9,  4 < 9, 5 < 9, 6 < 9, 7 < 9, 8 < 9, doesn't mean 9 < 9... you can't just create an arbitrary logic pattern and assume that it continues. Sorry, you need better logic than that.

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