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no no i try them of course.what are you doing on the first one?
the US elevator was funny.
the roman one was amazing never woulda guessed.
there is also the read and write one.
the frist one is easy:
.1,+1,.2,+2,.3,+3,...
sqrt(-1) doesnt exist because it is indefined.
I have been waiting for a long time to open this topic.
i have some questions about these but all in good time.first step is to open up the topic.
so here you can post anything useful,interesting,helpful about sequences,any problem involving the same.
hi ganesh
well you shouldn't this one has a lot of use in the future.
hi ganesh
hi ganesh
i am sorry i have to go.see you tomorrow.
the only answer that is asked is the positive one which is 8.
but if it told you to look at all integers and not just the positive ones than it would be 8 and -9.
i already told you that you shouldn't do that,so no you don't switch negative to positive.
the work is correct.don't worry about it.
no,no,if you change them to positive they wouldn't be correct answers.the negative ones i think should not be posted.
has your teacher told you anything about negatives in these problems?
hi zee-f
your -9 solution was correct but it wasn't included because you are looking for positive solutions as bobbym explained.it was correct the first time,so don't worry about that one.
also for the #17 you take only the 7 because it is positive.you don't take -9 because it is negative.
18134
3+4+8-1-1=13
hi ganesh
hi ganesh
it is a book problem.
well actually i could use the fact that alpha is greater or equal to zero and less than one but i don't know what to do then.
hi guys
i have just noticed that it should be -13floor(x).sorry about that.
also i was wondering if a method could work because i tried to do it that way and didn't get the answer,but if you were to help maybe i could gete it:
hi flip550
in your case the middle man would know that his hat is white.so that case doesn't match the propositions.