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Hi;
What have you tried here?
If you can define what a negative distance is then we can talk about that.
Hi;
Can you say something about a and b?
I do not think so. The distance of (2,3) from the y axis is a straight line. There is no right triangle.
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Nice page, I got it!
We did not use the slope intercept form. We are still plugging x = 0 into x+3y-9=0 to get the y intercept.
It is not necessary to use Pythagoras on such an easy question.
Just to interject this though:
The problem of finding simple evaluations of major classes of sums that involve factorials,
binomial coefficients, and their q-analogues, has been completely solved. Sums that have
the rather general form specified in Section 3 can all be done algorithmically, that is to say,
you can do them on your own PC. Your computer evaluates the sum as a simple formula,
if that's possible, and gives you a proof that you can check, or gives you a proof that your
sum cannot be done" in simple closed form, if that is the case.
If you are to start doing lots of these then I suggest A=B and Generatingfunctionology and picking up the appropriate software from those books.
As a beginning course, let us examine the work of the first person to ever attack these sums in a systematic manner, Sister Mary Celine:
The Pythagorean theorem states that the 3 sides of a right triangle are related by this a^2 + b^2 + c^2. Know how to apply that?
Not really. It confuses people having more than one choice.
The y intercept is where x = 0. So plug in in x = 0 in x+3y-9=0 and solve for y.
Possibly by snake oil...
What is the distance of blue line segment?
I have no y intercept
Do you need the y intercept or not?
You need the distance formula or pythagoras for that.
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That is the correct slope. Did you solve for y in the equation x+3y-9=0? Then you can get the y intercept.
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Do not forget to visualize problems by drawing diagrams and plots.
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This is a bit tricky to get but I would say the distance from the y axis is 2. I suggest to not abandon a visual approach here. Please check bob bundy's drawing.
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There are lots of lines parallel to that one. Start by finding the slope. You do that by putting the equation into standard form y = mx + b